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Haloalkanes and Haloarenes Test - 26

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Haloalkanes and Haloarenes Test - 26
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Weekly Quiz Competition
  • Question 1
    1 / -0
    When octa-O-methyl d-cellobiose is hydrolysed by aqueous acid, two O-methylated glucose derivatives are formed:  One is tetramethyl derivative and the other is trimethyl derivative. Why is a single methyl substituent lost in this process ? 
  • Question 2
    1 / -0
    Ethyl chloride is converted to butane by :
    Solution
    Williamson's synthesis: Sodium ethoxide reacts with alkyl halide and ether forms as product.
    $$RONa+RX\rightarrow ROR +NaX$$

    Wurtz reaction:
    $$RX+2Na+RX\rightarrow R-R+2NaX$$

    It is clear from above reactions Option C is correct.

  • Question 3
    1 / -0
    Chloroethane is reacted with alcoholic potassium hydroxide. The product formed is:
    Solution
    Chloroethane reacts with alc. KOH and ethene forms. 

    It is a basic method for preparation of alkene.

    Alcoholic KOH when used the elimination reaction takes place.

    Option C is correct.

  • Question 4
    1 / -0
    Reaction of ethyl chloride with sodium leads to (in the presence of dry ether):
    Solution
    The above reaction is Wurtz Reaction where alkyl halides react with sodium in presence of dry ether to form higher hydrocarbon.

    $$2C_2H_5-Cl\xrightarrow{2Na}C_4H_{10}+2NaCl$$

    Option C is correct.
  • Question 5
    1 / -0
    $$1$$-Chlorobutane on reaction with alcoholic potash gives:
    Solution
    Alc. $$KOH$$ is a dehydrohalogenation agent, it reacts with an alkyl halide and alkene forms as a product.

    Reaction of process:
    $$CH_3CH_2CH_2CH_2Cl\xrightarrow {alc.KOH} CH_3CH_2CH=CH_2$$

    Option A is correct.
  • Question 6
    1 / -0
    In the dehydrohalogenation of ethyl chloride, which of the following change occurs?
    Solution
    In dehydrohalogenation, alkyl halide converts into an alkene. Alkyl halide contains $$sp^3$$ carbon and alkene contains $$sp^2$$ carbon.

    Hence, the correct option is 'D'.

  • Question 7
    1 / -0
    Ethyl bromide on boiling with alcoholic solutions of sodium hydroxide forms:
    Solution
    $$C_2H_5-Br\xrightarrow{NaOH(alc.)}C_2H_4+HBr$$
  • Question 8
    1 / -0
    Reaction of alkyl halide with metallic sodium in presence of dry ether solution is called:
    Solution
     Wurtz reaction: Alkyl halide reacts with $$Na$$ in presence of dry ether and alkane forms.

    $$RX+2Na+RX\rightarrow R-R+2NaX$$

    Option C is correct.
  • Question 9
    1 / -0
    Which of the following reagents, when heated with ethyl chloride, forms ethylene?
    Solution
    Ethyl chloride reacts with aq. $$KOH$$ and alcohol forms.
    Ethyl chloride reacts with $$Zn/HCl$$ and alkane forms.
    Ethyl chloride reacts with alc. $$KOH$$ and ethene forms.
    The reaction of the process is:
    $${ C }_{ 2 }{ H }_{ 5 }Cl \xrightarrow { alc.KOH } { CH }_{ 2 }=C{ H }_{ 2 }+HCl$$
  • Question 10
    1 / -0
    The reaction conditions leading to the best yield of $$C_{2}H_{5}Cl$$ are:
    Solution
    Halogenation of alkanes will lead to the formation of alkyl halide.

     In this reaction, if we use $$Cl_2$$ in excess, then dichloro and trichloro forms as product and if ethane is used in excess, ethyl chloride forms as major product. 

    So, the reaction takes place as follows:
    $$C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl$$
    (excess)

    Option A is correct.
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