Haloalkanes and Haloarenes Test

Result

Haloalkanes and Haloarenes Test - 48

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following reaction, does not give chloro benzene as product?

A

B

C

D

Solution

All the remaining reaction does not have fluorine involved as its compound reaction.When such compound exists,then
Question 2
1 / -0

Additional of $$Br_2$$ to trans-2- butene would give a product which is :

A
achiral

B
racemic

C
meso

D
optically active

Solution

As refer to the above image,
TAM- Anti addition to Trans results in meso compound.
Question 3
1 / -0

The IUPAC name of $$(CH_3)_3C. CH_2CH_2Cl$$ is:

A
$$2, 2$$ - Dimethyl - $$4$$-chloro butane

B
$$1$$ - Chloro - $$3, 3$$ - dimethylbutane

C
$$4$$ - Chloro - $$2, 2$$ - dimethylbutane

D
none of these

Solution

Parent chain consist of $$4-$$carbonation and it is also saturated.So,butane is parent chain.
On $$3rd$$ carbon atom two methyl substituent are attached.
So its name is $$1-$$chloro$$-3,3-$$dimethyl butane.
Question 4
1 / -0

In the given pair of alcohol, in which pair second alcohol is more reactive then first towards hydrogen bromide?

A

B

C
$$CH_3-\underset{\underset{OH}{|}}{CH}-CH_2-CH_3\, and \, CH_3-CH_2-\underset{\underset{CH_3}{|}}{CH}-CH_2-OH$$

D
$$CH_3-\underset{\underset{OH}{|}}{CH}-CH_2-CH_3\, and \, (CH_3)_2-\underset{\underset{OH}{|}}{C}-CH_2-CH_3$$

Solution

$$CH_{ 3 }-\overset { \oplus }{ \underset { \underset { 2^{ 0 } }{ \downarrow } }{ CH } }-CH_2-CH_3<(CH_3)_2 \underset { \underset { \underset { 3^ 0 }{ \downarrow } }{\oplus } }{ C } -CH_2-CH_3$$

Alcohols are more reactive towards $$HBr$$, if the formed carbocation is highly stable.
$$3^o cation >2^o cation > 1^o cation$$ [stability]
(Refer to Image) $$CH_3$$
As $$3^o$$ cation is more stable than $$2^o$$, $$(CH_3)_2\underset {|}{C}-CH_2-CH_3$$ is more stable than $$CH_3-\underset {|}{CH}-\overset {|}{CH_2}$$.
$$OH$$ $$OH$$
Question 5
1 / -0

In $$E_2$$ elimination some compounds follow Hofmann's rule which means:

A
the double bond goes to the most substituted carbon

B
the compound is resistant to elimination

C
no double bond is formed

D
the double bond mainly goes to the less substituted carbon
Question 6
1 / -0

Identify the product.

A

B

C

D

Solution

$$KSH$$ is potassium hydrosulfide. It is a colourless salt & consists of the cation $$K^+$$ and the bisulphide anion $$SH^-$$. It is the product of the half neutralization of hydrogen sulphide with potassium hydroxide. The compound is used in the synthesis of some organosulphur compound. It is prepared by neutralizing aqueous $$KOH$$ with $$H_2S$$.
Question 7
1 / -0

Which compound is a possible product from addition of $$Br_2$$ to 1- butene?

A

B

C

D

Solution

As refer to the above image, Bromination results in the formation of $$1,2-dibromobutane$$.
Question 8
1 / -0

Taking into account the stability of various cycloalkanes and carbocations, as well as the rules governing mechanisms of carbocation rearrangements What is the most likely product of this reaction ?

A

B

C

D

Solution

As shown in the above image hence, carbocation rearrangement is the mechanism.
Question 9
1 / -0

Compare rate of reaction $$Ag^+NO^-_3$$ or rate of $$S_N1$$ reaction.
The correct choice is:

A
I $$>$$ II $$>$$ III

B
II $$>$$ III $$>$$ I

C
II $$>$$ I $$>$$ III

D
I $$>$$ III $$>$$ II

Solution

Reaction with $$AgNO_3$$ will give precipitate of AgI only in that case where stable carbocation get form
so order will be ii.>iii.>i
Question 10
1 / -0

$$2$$-Methyl propane on monochlorination under photochemical condition give:

A
$$2$$-chloro-$$2$$-methylpropane as major product

B
$$(1:1)$$ mixture of $$1$$-chloro-$$2$$-methylpropane and $$2$$-chloro-$$2$$-methylpropane

C
$$1$$-chloro-$$2$$-methylpropane as a major product

D
$$(1:9)$$ mixture of $$1$$-chloro-$$2$$-methylpropane

Solution

2-chloro-2-methyl-propane.
This reaction occur via radical mechanism.