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Haloalkanes and Haloarenes Test - 53

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Haloalkanes and Haloarenes Test - 53
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Pure methane can be produced by:
    Solution
    Soda line decarboxylation reaction can produce pure methane.
    CH3COONa+NaOHCaoΔCH4+Na2CO3 CH_3 COONa + NaOH \xrightarrow[Cao]{\Delta } CH_4 + Na_2 \,CO_3

  • Question 2
    1 / -0
    Given Reaction.
    Y in reaction is:

    Solution

    (Refer to Image)
    When MgMg in presence of ether reacts known as Grignard reagent and this form salt with halogen. Then H2OH_2O and HClHCl provide H+H^+ in place of MgBrMgBr. This is an example of substitution reaction.

  • Question 3
    1 / -0
    To prepare a pure sample of normal hexane using sodium metal as one reactant, the other reactant or reactants will be:
    Solution
    Option C is correct answer

  • Question 4
    1 / -0
    wC2H6+xI2+HIO3yC2H5I+zH2OwC_{2}H_{6}+xI_{2}+HIO_{3}\rightarrow y C_{2}H_{5}I+z H_{2}O the value of w,x,y,zw,x,y,z are:
    Solution
    5C2H6+2I2+HIO35C2H5I+3H2O5{C}_{2}{H}_{6} + 2{I}_{2} + HI{O}_{3} \rightarrow 5{C}_{2}{H}_{5}I + 3{H}_{2}O
    The given reaction is an iodonation of ethane to get ethanoic acid. Here HIO3HIO_3 act as an oxidizing agent.
    After balancing the reaction the value of w,x,y,zw,x,y,z are
    w,x,y,z=5,2,5,3w,x,y,z = 5,2,5,3

    Option A is correct
  • Question 5
    1 / -0
    In which of the following compound the electrophile attack on o- and p- position :
    Solution

  • Question 6
    1 / -0
    The product obtained on reaction of C2H5ClC_2 H_5 Cl with hydrogen over palladium carbon is: 
    Solution

  • Question 7
    1 / -0
    Which among the following compounds is used to decaffeinate coffee?
    Solution
    The two most commonly used solvents for decaffeinating coffee today are methylene dichloride and ethyl acetate.

    After soaking in these, the coffee beans are steamed, dried, and roasted. These processes ensure that no residual solvent remains in the beans. Soaking coffee beans in solvent removes caffeine as it dissolves in the solvent.

    Hence, option CC is correct.
  • Question 8
    1 / -0
    Sn1 S_n^1 reaction is favoured by:
    Solution
    SN1S_{N^1} mechanism proceeds through carbocation formation and as stability of carbocation increases, it favours SN1S_{N^1} mechanism and as we add bulky group to carbon attached with halogen, carbocation formed will become more stable due to +I+I effect of bulky alkyl group so it favours SN1S_{N^1} mechanism.

  • Question 9
    1 / -0
    The hydrolysis of 2-bromo-3-methyl butane by SN1 S_N1 mechanism gives mainly
    Solution
    Mechanism of hydrolysis of 2-bromo-3-methyl butane is given above.
    The product formed is 2-methyl-2-butanol.

    Hence, Option "B" is the correct answer.

  • Question 10
    1 / -0
    CH3CHCH3CH2CH2COCH3H2/PdCH_3-\overset{CH_3}{\overset{|}{C}H}-CH_2-CH_2-\underset{O}{\underset{||}{C}}-CH_3 \xrightarrow[]{H_2/Pd}No. Of stereoisomerism.
    Solution
    CH3C    CH3=CHCH2COCH3H2/Pd/CCH3C    CH3CH2CH2CHOHCH3CH_3-\underset{\,\,\,\,CH_3}{\underset{|}{C}}=CH-CH_2-\underset{O}{\underset{||}{C}}-CH_3 \xrightarrow []{H_2/Pd/C}CH_3-\underset{\,\,\,\,CH_3}{\underset{|}{C}}-CH_2-CH_2-\underset{OH}{\underset{|}{C}H}-CH_3
    Total number of stereo isomer = 22
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