Haloalkanes and Haloarenes Test

Result

Haloalkanes and Haloarenes Test - 57

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Weekly Quiz Competition

Question 1
1 / -0

(i) Chlorobenzene and (ii) benzene hexachloride are obtained from benzene by the reaction of chlorine, in the presence of

A
(i) Direct sunlight and (ii) anhydrous $$AlCl_{3}$$

B
(i) Sodium hydroxide and (ii) sulphuric acid

C
(i) Ultraviolet light and (ii) anhydrous $$FeCl_{3}$$

D
(i) Anhydrous $$AlCl_{3}$$ and (ii) direct sunlight

Solution
Question 2
1 / -0

The major amount of $$(C)$$ is:

A

B

C

D

Solution
Question 3
1 / -0

What would be the product formed when $$1$$-bromo-$$3$$-chloro cyclobutane reacts with two equivalents of metallic sodium in ether ?

A

B

C

D

Solution

$$ (C - Br) $$ bond is weaker than $$ (C - Cl) $$ bond ; Hence, Wurtz reaction will take place with $$ (C - Br) $$ bond.
Question 4
1 / -0

Condition for maximum yeild of $$C_2H_5Cl$$ is

A
$$C_2H_6 (\text{excess}) + Cl_2\xrightarrow[]{\text{UV Light}}$$

B
$$C_2H_6 + Cl_2 \xrightarrow[\text{Room temp.}]{\text{Dark}}$$

C
$$C_2H_6 + Cl_2$$ (excess) $$ \xrightarrow[]{\text{UV Light}}$$

D
$$C_2H_6 + Cl_2 \xrightarrow[]{\text{UV Light}}$$

Solution

$$C_2H_6 (\text{excess}) + Cl_2 \xrightarrow[]{\text{UV Light}} \underset{\text{(Major product)}}{\underset{\text{Ethyl chloride}}{C_2H_5Cl}} + HCl$$
Question 5
1 / -0

The compounds are optically inactive because

A
Both compounds have the plane of symmetry

B
Both compounds have the centre of symmetry

C
Compound I has the plane of symmetry, while compound II has the centre of symmmtry.

D
Compound I has the centre of symmetry, while compound II has the plan of symmmtry.

Solution

The statement is self-explanatory.
Question 6
1 / -0

Arrange the following in the decreasing order of nucleophilic acyl substitution reaction.

A
(I)>(II)>(III)>(IV)

B
(IV)>(III)>(II)>(I)

C
(I)>(III)>(II)>(IV)

D
(IV)>(II)>(III)>(I)

Solution

(I)>(II)>(III)>(IV)
Acyl chloride > Anhydride > Ester > Amide.
Question 7
1 / -0

When the substances Si, KCl, $$CH_{3}OH$$ and $$C_{2}H_{6}$$ are arranged in order of increasing melting point, what is the correct order?

A
Si, KCl, $$CH_{3}OH, C_{2}H_{6}$$

B
$$CH_{3}OH, C_{2}H_{6}, Si, KCl$$

C
$$KCl, Si, C_{2}H_{6}, CH_{3}OH$$

D
$$C_{2}H_{6}, CH_{3}OH, KCl, Si$$

Solution

$$C_{2}H_{6}$$ < $$CH_{3} - OH$$ < $$KCl$$ < $$Si$$
(Molecular lattice) (Molecular lattice ) (Ionic lattice) (Covalent lattice)
Question 8
1 / -0

What is the correct IUPAC name for

A
1-Bromo-2-ethylpropane

B
1-Bromo-2-ethyl-2-methylethane

C
1-Bromo-2-methylbutane

D
2-Methyl-1-bromobutane

Solution

The correct IUPAC name of the given compound is 1-Bromo-2-Methylbutane.
Hence, Option "C" is the correct answer.
Question 9
1 / -0

Match the isomers given in column I with their names given in column II and mark the appropriate choice.

A
$$(A) \rightarrow (iii), (B) \rightarrow (i), (C) \rightarrow (iv), (D) \rightarrow (ii)$$

B
$$(A) \rightarrow (iv), (B) \rightarrow (iii), (C) \rightarrow (ii), (D) \rightarrow (i)$$

C
$$(A) \rightarrow (i), (B) \rightarrow (ii), (C) \rightarrow (iii), (D) \rightarrow (iv)$$

D
$$(A) \rightarrow (ii), (B) \rightarrow (iii), (C) \rightarrow (iv), (D) \rightarrow (i)$$

Solution
Question 10
1 / -0

In the question arrange the compounds in increasing order of rate of reaction towards nucleophilic substitution.

A
(I) < (II) < (III)

B
(III) < (II) < (II)

C
(I) < (III) < (II)

D
(III) < (I) < (II)

Solution

Presence of electron withdrawing group (-NO$$_2$$) increases the reactivity towards nucleophilic substitution and the effect of o-position is greater than at m-position due to resonance.

So, the order becomes (I) < (III) < (II)
Hence, Option "C" is the correct answer.