Alcohols Phenols and Ethers Test

Result

Alcohols Phenols and Ethers Test - 24

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Weekly Quiz Competition

Question 1
1 / -0

The correct IUPAC name of the compound is:

A
Isopropyl butanol

B
2-methylbutane-3,4-diol

C
3-methylbutane-1,2-dial

D
3-methylbutane-1,2-diol

Solution

The correct IUPAC name of the compound is 3-methyl butane-1,2-diol.

A methyl substituent is present on third C atom and $$-OH $$ substituents are present on first and second C atoms.

Note: The longest chain of C atoms containing the $$-OH$$ group is selected as the parent alkane and numbered from the end closer to $$-OH$$ group.
Question 2
1 / -0

2-methyl pentane-1-ol is a:

A
$$1^{0}$$alcohol

B
$$2^{0}$$alcohol

C
$$3^{0}$$alcohol

D
none of the above

Solution

As shown in the structure the $$-OH$$ functional group is attached to 1st degree carbon, hence it is $$1^0$$ alcohol.
Question 3
1 / -0

The IUPAC name of the compound is:

A
1 - dimethylbutane - 1, 3 - diol

B
1, 3, 3 -trimethylpropane - 1, 2 -diol

C
2 - methylpentane - 2, 4 - diol

D
1, 3, 3 -trimethylpropane - 1, 3 -dial

Solution
Question 4
1 / -0

$$CH_3-CH_2-\overset{OH}{\overset{|}{C}H}-CH_2-CH_2-\underset{CH_3}{\underset{|}{C}H}-CH_2-CH_3$$
The IUPAC name of the compound is:

A
6-methyl-3-hexanol

B
6-Methyl-3-octanol

C
1-methyl-4-hexanol

D
4-methyl-1-octanol

Solution

The parent chain will be of 8 carbons. The funtional group is $$-OH$$, so the name of the parent chain will be octanol.

The numbering will start from left side, $$-OH$$ will get number 3 and $$-CH_3$$ will get number 6.

Therefore, IUPAC name is 6-Methyl-3-octanol.

Option B is correct.
Question 5
1 / -0

Which of the following is a tertiary alcohol?

A
$$(CH_{3})_{2}CHCH_{2}OH$$

B
$$CH_{3}CH_{2}CH_{2}CH_{2}OH$$

C
$$CH_{3}CH_{2}CH_{2}OH$$

D
$$(CH_{3})_{3}COH$$
Question 6
1 / -0

The IUPAC name is:

A
2-ethyl-2-butanol

B
3-Methyl-3-pentanol

C
3-ethyl-3-methyl-3-pentanol

D
1,1-diethyl ethanol

Solution

Hence IUPAC name is 3-methyl-3-pentanol.
Question 7
1 / -0

The IUPAC name of $$(CH_{3})_{2}CHCH_{2}CH_{2}OH$$ is:

A
3-Methyl butan-1-ol

B
2-methyl pentan-1-ol

C
3-ethyl pentan-1-ol

D
2-ethyl butan-1-ol

Solution

$$H-\overset{\overset{4}{CH_3}}{\overset{|}{\underset{CH_3}{\underset{|}{C_3}}}}-\underset{2}{CH}-CH_2-OH$$

3-Methyl butan-1-ol

Option A is correct.
Question 8
1 / -0

The IUPAC name is:

A
2, 4 -dimethyl pentan-2-ol

B
2, 4 - dimethyl pentan-4-ol

C
2, 2 - dimethyl butan-2-ol

D
butan-2-ol

Solution
Question 9
1 / -0

IUPAC name of the following compound is:

$$CH_{3}-CH(C_{2}H_{5})-CH_{2}-CH(OH)-CH_{3}$$

A
4-Methyl -2- hexanol

B
4-ethyl -2- pentanol

C
2-ethyl -2- pentanol

D
3-methylhexanol

Solution

IUPAC name of $$CH_{3}-CH(C_{2}H_{5})-CH_{2}-CH(OH)-CH_{3}$$ is 4-methyl -2- hexanol.
The parent compound contains a 6 C atom chain and a hydroxyl group. Hence, it is a derivative of hexanol. The hydroxyl group is present on the second C atom and methyl substituent is present on the fourth C atom.

Note: The longest chain of C atoms containing the $$-OH$$ group is selected as the parent alkane and numbered from the end closer to $$-OH$$ group.

Hence, the correct option is $$\text{A}$$
Question 10
1 / -0

Enzymes involved used in the fermentation of cane sugar to alcohol?

A
Diastase, invertase

B
Invertase, zymase

C
Diastase, zymase

D
Maltase, zymase

Solution

Invertase and zymase enzymes are used in the fermentation of cane sugar to alcohol.

Invertase converts sucrose present in the sample to glucose and fructose, while zymase converts it finally to ethanol and $$CO_2$$.

Option B is correct.