Alcohols Phenols and Ethers Test

Result

Alcohols Phenols and Ethers Test - 52

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Weekly Quiz Competition

Question 1
1 / -0

$$3-methyl-1-butene$$ on oxymercuration -demercuration yields________ as the major product

A
$$3-methyl-2-butanol$$

B
$$2-methyl-2-butanol$$

C
$$3-methyl-1-butanol$$

D
$$2-methyl-1-buranol$$

Solution
Question 2
1 / -0

Arrange above structures in increasing order of acidic strength.

A
$$I<II<III$$

B
$$I<III<II$$

C
$$II<I<III$$

D
$$II<III<I$$
Question 3
1 / -0

Ethene reacts with $$Y$$ to produce ethanol.
$$ethene + Y \rightarrow ethanol$$
What is $$Y$$?

A
Hydrogen

B
Oxygen

C
Steam

D
Yeast

Solution

Solution:- (C) Steam
Ethanol can be manufactured by hydration of ethene.
Ethene is heated with steam in the presence of a catalyst of phosphoric acid to produce ethanol.
$${C}_{2}{H}_{4} + {H}_{2}O \xrightarrow{\text{high temperature}} \underset{\left( \text{Ethanol} \right)}{{C}_{2}{H}_{5}-OH}$$
Hence $$Y$$ is steam.
Question 4
1 / -0

Correct order of acidic strength.

A
$$I > II > III$$

B
$$II > III > I$$

C
$$I > III > II$$

D
$$III > II > I$$

Solution

Acidic nature $$\alpha - I$$.

Question 5

1 / -0

But-$$2$$-ene, $$1, 4$$-diol is converted in two steps through an intermediate X into oxobutanedioic acid.
$$\underset{but-2-ene-1, 4-diol}{HOCH_2CH=CHCH_2OH}\overset{step 1}{\rightarrow} x\underset{hot, acidified KMnO_4}{\overset{step 2}{\rightarrow}}\underset{oxobutanedioic acid}{HO_2CCOCH_2CO_2H}$$
What could be the reagent for step $$1$$ and what is the intermediate X?

	reagent for step $$1$$	X
A	cold, acidified $$KMnO_4$$	$$HOCH_2CH_2CH(OH)CH_3OH$$
B	hot, acidified $$K_2Cr_2O_7$$	$$HO_2CCH=CHCO_2H$$
C	steam and concentrated $$H_2SO_4$$	$$HOCH_2CH(OH)CH_2CH_2OH$$
D	warm, acidified $$K_2Cr_2O_7$$	$$OHCCH(OH)CH_2CHO$$

A

B

C

D

Solution

Alkenes react with concentrated sulphuric acid to produce alkyl hydrogen sulphates which on hydrolysis gives alcohol.

Thus but-$$2$$-ene-$$1, 4$$-diol will react with steam and concentrated $${H}_{2}S{O}_{4}$$ and will produce butan-$$1, 2, 4$$-triol (X} which on further reaction with hot and acidified $$KMn{O}_{4}$$ gives oxobutandioic acid.

Hence (C) is correct.

Question 6
1 / -0

Find the product:

A

B

C

D

Solution
Question 7
1 / -0

Menthol is a naturally occurring alcohol. When menthol is heated with concentrated sulfuric acid it reacts, and the products formed is:

A

B

C

D
Question 8
1 / -0

What is the major product formed when compound $$Q$$ is warmed with excess $$HBr$$?

A

B

C

D

Solution

The $$-OH$$ group will react with $$HBr$$ to undergo nucleophilic substitution reaction and will replace $$OH$$ with $$Br$$ and the double bond in the compound will also react with $$HBr$$ and undergo addition rection.
Hence (C) will be the major product formed.
Question 9
1 / -0

A

B

C

D

Solution
Question 10
1 / -0

Which reagent is suitable for this conversion?

A
$$Zn-Hg/HCl$$

B
$$LiAlH_4$$

C
$$NH_2-NH_2/OH^-$$

D
Red $$P+HI$$

Solution

Suitable Reagent for this conversion is $$LiAlH_4$$.