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Alcohols Phenols and Ethers Test - 56

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Alcohols Phenols and Ethers Test - 56
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following is phenolic 
    Solution
    Picric acid is phenolic while others are non phenolic

  • Question 2
    1 / -0
    The structural formula of cyclohexanol is
    Solution

  • Question 3
    1 / -0
    During dehydration of alcohols to alkenes by heating with conc. $$ H_2SO_4 $$ the initiation step is
    Solution
    $$H_2SO_4 \rightarrow H^+ + HSO_4^-$$

    In the first step protonation of alcohol molecule takes place.

    Option A is correct.

  • Question 4
    1 / -0
    Dehydration of ethanol gives 
    Solution
    $$ CH_3-CH_2-OH  \xrightarrow [170^0]{Conc.H_2SO_4} CH_2 =CH_2 +H_2O $$

    Option C is correct.
  • Question 5
    1 / -0
    Wine (alcoholic beverages) contains:
    Solution
    Alcoholic beverage, any fermented liquor, such as wine, beer, or distilled spirit, that contains ethyl alcohol, or ethanol $$(CH_3CH_2OH)$$, as an intoxicating agent.
    Hence, option $$C$$ is the answer.
  • Question 6
    1 / -0
    In the following series of chemical reactions, identify Z $$ C_3H_7OH  \quad \xrightarrow [ 160-180^{ 0 }C ]{ Conc.H_{ 2 }SO_{ 4 } } X\xrightarrow [  ]{  Br_2 }Y\xrightarrow [ Excess\ of ]{ Alc. KOH  }  Z $$
    Solution

    $$ CH_3CH_2CH_2OH \xrightarrow [160-18060 C]{conc.H_2SO_4} CH_3CH =CH_2 \xrightarrow []{Br_2} CH_3 - \underset{Br}{\underset{\!\!\!\!|}{CH}} - \underset{Br}{\underset{\!\!\!\!|}{CH_2}}\xrightarrow {Alc.KOH} \underset{Propyne}{CH_3-C\equiv CH}$$
  • Question 7
    1 / -0
    The reaction of $$ C_2H_5OH $$ with $$ H_2SO_4 $$ does not give  
    Solution
    Option C is correct.

  • Question 8
    1 / -0
    Propan-1-ol can be prepared from propene by alcohol 
    Solution
    $$ 6CH_3-CH=CH_2+B_2H_6 \xrightarrow []{H_2O_2} CH_3-CH_2-CH_2OH $$
    Preparation of Propan-1-ol is shown in the above reaction.

    Option C is correct.

  • Question 9
    1 / -0
    In the following sequence of reactions
    $$CH_3CH_2CH_2Br \overset{KOH(alc)}{\longrightarrow} (A) \overset{HBr}{\longrightarrow} (B) \overset{KOH (aq.)}{\longrightarrow} (C).$$
    The product (C) is
    Solution

  • Question 10
    1 / -0
    One of the following that cannot undergo dehydro - halogenation is
    Solution
    Ethanol doesn't have any halogen group. Thus ethanol cannot undergo dehydrohalogenation. 
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