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Aldehydes Ketones and Carboxylic Acids Test - 15

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Aldehydes Ketones and Carboxylic Acids Test - 15
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following cannot form $$CH_{3}COOH$$ from $$C_{2}H_{5}OH$$?
    A) PCC
    B) PDC
    C) $$K_{2}Cr_{2}O_{7} / H^{+}$$
    D)$$KMnO4/ H^+$$
    Solution
    PCC and PDC are the mild oxidizing agent.

    They oxidize ethanol to ethanol, not ethanoic acid. 

    While the $$KMnO_4$$ and $$K_2Cr_2O_7$$ are strong oxidizing agents, hence, they convert ethanol into acetic acid.

    Option A is correct.
  • Question 2
    1 / -0
    $$C_{6}H_{5}CONH_{2} \xrightarrow[\Delta]{H_{3}O^+} A + NH_{3}$$
    In this reaction, $$A$$ is ___________.
    Solution
    When benzamide is hydrolyzed, it produces benzoic acid and ammonia.
    The reaction is: 
    $$C_{6}H_{5}CONH_{2} \xrightarrow[\Delta]{H_{3}O^+} C_6H_5COOH + NH_{3}$$
  • Question 3
    1 / -0
    $$CH_{3}OH \xrightarrow[(ii)\: Rh, \: \Delta]{(i)\: X} CH_{3}COOH$$
    In the above reaction, $$X$$ is :
    Solution
    The compound $$X$$ is $$CO$$.
    The reaction is as follows:
    $$CH_{3}OH \xrightarrow[(ii)\: Rh, \: \Delta]{(i)\:{CO}} CH_{3}COOH$$
    The reaction of $$CO$$ with methanol, followed by heating with $$Rh$$ gives acetic  acid. This process is called as Monsanto process.
  • Question 4
    1 / -0
    Which of the following is the strongest acid?
    Solution
    Lower the pKa value, higher is the acid dissociation constant and so, higher is the acidic strength.

    Hence, option A with least $$pK_a$$ value is the correct answer.

    Option A is correct.
  • Question 5
    1 / -0
    Methyl cyanide on hydrolysis gives :
    Solution
    Methyl cynide on hydrolysis gives Acetic Acid.

    Hence option A is correct.
  • Question 6
    1 / -0
    $$CH_{3}CH_{2}OH+O_{2}\xrightarrow[]{X}$$ Vinegar
    In the above reaction, $$X$$ is:
  • Question 7
    1 / -0
    Which of the following is not a monovalent group?
    Solution
    Valency is the number of chemical bonds formed by the functional group. Aldehyde, carboxylic acid and hydroxy groups form one chemical bond, whereas ketone can form two chemical bonds. Therefore, ketonic group is not monovalent.

    $$R-CO-R$$ is ketone functional group, which is bivalent.
  • Question 8
    1 / -0
    Isobutyraldehyde on oxidation gives:
    Solution
    The aldehydes gets oxidised to carboxylic acid.

  • Question 9
    1 / -0
    An aldehyde on oxidation gives
    Solution
    Alcohols on oxidation give aldehydes while aldehydes on further oxidation give carboxylic acids.
  • Question 10
    1 / -0
    List-A
    List-B
    Aldehyde
    Oxidised product of
    Aldehyde
    1. Formaldehyde
    A. Acetic Acid
    2. Acetaldehyde
    B. Propanoic acid
    3. Propionaldehyde
    C. Isobutyric acid
    4. Isobutyraldehyde
    D. Methanoic acid

    Match the contents in List-A to that in List-B.
    Solution
    Formaldehyde $$(HCHO)$$ on oxidation gives methanoic acid $$(HCOOH)$$.

    Acetaldehyde $$(CH_3CHO)$$ on oxidation gives acetic acid $$(CH_3COOH)$$.

    Propionaldehyde $$(CH_3CH_2CHO)$$ on oxidation gives propanoic acid $$(CH_3CH_2COOH)$$.

    Isobutyraldehyde $$(CH_3CH(CH_3)CHO)$$ on oxidation gives isobutyric acid $$((CH_3CH(CH_3)COOH)$$.

    Option A is correct.
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