Aldehydes Ketones and Carboxylic Acids Test

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Aldehydes Ketones and Carboxylic Acids Test - 17

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Weekly Quiz Competition

Question 1
1 / -0

When acetonitrile is hydrolysed the product formed is ________.

A
$$CH_{3}COOH$$

B
$$C_{2}H_{5}COOH$$

C
$$CH_{3}CONH_{2}$$

D
$$C_{2}H_{2}NH_{2}$$

Solution

Acetonitrile is $$CH_{3}CN$$.
Question 2
1 / -0

Consider the reaction:
$$RCHO + NH_{2}NH_{2} \rightarrow RCH = N NH_{2}$$
What sort of reaction is it?

A
Free radical addition elimination reaction

B
Electrophilic substitution-elimination reaction

C
Nucleophilic addition elimination reaction

D
Electrophilic addition elimination reaction

Solution

$$R-CHO+N{ H }_{ 2 }-N{ H }_{ 2 }\longrightarrow RC{ H }=NN{ H }_{ 2 }$$
The above reaction is Wolf Kirchner reduction.
Here $$N{ H }_{ 2 }-{ NH }^{ \ominus }$$ is nucleophile added to aldehyde and water molecule is eliminated from the compound hence it is nucleophilic addition elimination reaction.
Question 3
1 / -0

The functional group present in carboxylic acids is ?

A
-COOH

B
-CO-

C
-OH

D
-CHO

Solution

Carboxylic acids are represented by -COOH- functional group. It ionizes to give carboxylate ions and hydrogen ions. This group present in a compound makes it an acid and if present with other groups in the compound it is always present at position no.1 and carbon is included in the carbon chain atoms.
Question 4
1 / -0

Which of the following is the characteristic smell of benzaldehyde?

A
Fish like smell

B
Bitter almond like

C
Pungent smell

D
Rotten egg like smell
Question 5
1 / -0

In the above sequence of reactons D is :

A

B

C

D

Solution

B
A:- 1-Methylcyclopent-1-ene
B:- 5-Bromo-1-methylcyclopent-1-ene
C:- 5-Cyano-1-methylcyclopent-1-ene
D:- 1-Methylcyclopent-1-ene-5-oic acid
Question 6
1 / -0

The correct structural formula of butanoic acid is

A
$$H-\overset{H}{\overset{|}{\underset{H}{\underset{|}{C}}}}-\overset{H}{\overset{|}{C}}=\overset{H}{\overset{|}{C}}-\overset{O}{\overset{||}{C}}-OH$$

B
$$H-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{O}{\overset{||}{C}}}}-OH$$

C
$$H-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-OH$$

D
$$H-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\overset{O}{\overset{||}{C}}-OH$$

Solution

Butanoic acid is a carboxylic acid with the structural formula CH₃CH₂CH₂-COOH. where $$-COOH$$ is the functional group.

$$H-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}-\overset{O}{\overset{||}{C}}-OH$$

So, the correct representation of butanoic acid is $$D$$
Question 7
1 / -0

Nucleophilic addition reaction will be most favoured in:

A
$$CH_{3}$$ - $$CH_{2}$$ - $$CH_{2}C$$ - $$CH_{3}$$

B
$$\left (CH_{3} \right)_{2}C$$ = $$O$$

C
$$CH_{3}CH_{2}CHO$$

D
$$CH_{3}CHO$$

Solution

1.Aldehydes are most favoured than ketones for Nucleophilic addition reaction. Because ketones has two $$+I$$ groups which produces less positive charge on carbonyl carbon
Hence it may be C and D
2. Here comes steric hinderance and large chain, C has large chain more electron releasing and $$+I$$ effect. So that D is most favored.
Question 8
1 / -0

The IUPAC name for the compound $$CH_3-C(CH_3)=CH-COOH$$ is:

A
2-Methyl-2-butenoic acid

B
3-Methyl-3-butenoic acid

C
3-Methyl-2-butenoic acid

D
2-Methyl-3-butenoic acid

Solution

The numbering is done from right-hand side as carboxylic acid is present in right-hand side. There is double bond present at the C-2 position and methyl group at C-3 position.
Thus, the IUPAC name is: 3-methyl-2-butenoic acid
Question 9
1 / -0

In aldehydes and ketones, carbonyl carbon shows _______ hybridisation.

A
$$sp$$

B
$${ sp }^{ 3 }$$

C
$${ sp }^{ 2 }$$

D
$${ sp }^{ 3 }d$$

Solution

The carbonyl carbon in aldehydes and ketones forms $$sp^2$$ hybridization, as the Carbon and the oxygen atoms form a sigma bond in the molecule by overlapping the $$sp^2$$ hybrid orbitals. The pi bond between the carbon and oxygen is the 2p-2p overlap.
Question 10
1 / -0

The general formula of carboxylic acids is:

A
$$C_{n}H_{n}COOH$$

B
$$C_{n}H_{2n}COOH$$

C
$$C_{n}H_{2n-2}COOH$$

D
$$C_{n}H_{2n+1}COOH$$

Solution

General formula of acids is: $$C_{n}H_{2n+1}COOH$$.
For example: for n=1 we get $$CH_3-COOH$$ which is acetic acid.