Aldehydes Ketones and Carboxylic Acids Test

Result

Aldehydes Ketones and Carboxylic Acids Test - 39

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Weekly Quiz Competition

Question 1
1 / -0

The Compound E is:

A

B

C

D

Solution
Question 2
1 / -0

$$C_{4}H_{8}O_{2}$$ represents:

A
an acid only

B
an ester only

C
an ketone only

D
an acid and an ester also

Solution

$$C_{4}H_{8}O_{2}$$ represents an acid only.
Question 3
1 / -0

Which of the following will not form acetyl chloride with $$ PCl_{5} $$?

A
MeCOOH

B
MeCOOMe

C
MeCOOCOMe

D
$$ MeCONH_{2} $$

Solution
Question 4
1 / -0

When o-xylene is oxidised with alkaline $$KMnO_4$$, the product is:

A
Terephthalic acid

B
Phthalic acid

C
Benzoic acid

D
Salicylic acid

Solution

Option B is correct.
Question 5
1 / -0

$$R - \overset{O}{\overset{||}{C}} - Cl \xrightarrow[conc. \,H_2SO_4]{NaN_3} \xrightarrow[]{CH_3 - Cl (1 \,eqvt.)} \underset{\left( \text{Major product} \right)}{P}$$Hence, Product $$(P)$$ is:

A
$$R - NH_2$$

B
$$R - NH - CH_3$$

C
$$R - \overset{O}{\overset{||}{C}} - NH - CH_3$$

D
$$R - NH - \overset{O}{\overset{||}{C}} - CH_3$$

Solution

Alkyl or aryl acyl chloride reacts with sodium azide to give acyl azides.
See the figure i.
The acyl azides undergo thermal decomposition to an isocyanate with loss of $$N_2$$ gas. The isocyanate then undergoes nucleophilic attack to yield a primary amine.
See the figure ii and ii.
Question 6
1 / -0

The order of acidity for the following compounds is:

A
$$I > II > III > IV$$

B
$$III > I > II > IV$$

C
$$I > IV > II > III$$

D
$$I > III > IV > II$$

Solution

$$COOH$$ and $$OH$$ group are electron-withdrawing groups. $$COOH$$ is the main group here because of its high acidic nature. $$OH$$ group actively withdraws electron density from ortho and para positions greater than at meta position. Ortho position withdraws less electron density than para position because of ortho effect. More the number of $$OH$$ groups, more will be the withdrawing capacity and more will be the acidity.
(Refer to Image)
Question 7
1 / -0

A tripeptide $$x$$ on partial hydrolysis gave two dipeptides Cys-Gly and Glu-Cys.
Identify the tripeptide,
$$\overset{+}{N}H_3 - \overset{CH_2CH_2COOH\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!}{\overset{\!\!\!\!\!\!|}{CH}} - \underset{Glu-Cys}{\underset{\!O}{\underset{||}{C}}} - NH - \overset{CH_2 SH\!\!\!\!\!}{\overset{\!\!\!\!\!\!|}{CH}} - \underset{O}{\underset{||}{C}} - \overset{-}{O}$$
and
$$\overset{+}{N}H_3 - \overset{CH_2SH\!\!\!\!\!\!\!\!}{\overset{\!\!\!\!\!\!|}{CH}} - \underset{Cys-Gly}{\underset{\!O}{\underset{||}{C}}} - NH - CH_2 - \underset{O}{\underset{||}{C}} - \overset{-}{O}$$

A
Glu-Cys-Gly

B
Gly-Glu-Cys

C
Cys-Gly-Glu

D
Cys-Glu-Gly

Solution

$$\overset{+}{N}H_3 - \overset{CH_2CH_2COOH\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!}{\overset{\!\!\!\!\!\!|}{CH}} - \underset{Glu-Cys}{\underset{\!O}{\underset{||}{C}}} - NH - \overset{CH_2 SH\!\!\!\!\!}{\overset{\!\!\!\!\!\!|}{CH}} - \underset{O}{\underset{||}{C}} - \overset{-}{O}$$
and
$$\overset{+}{N}H_3 - \overset{CH_2SH\!\!\!\!\!\!\!\!}{\overset{\!\!\!\!\!\!|}{CH}} - \underset{Cys-Gly}{\underset{\!O}{\underset{||}{C}}} - NH - CH_2 - \underset{O}{\underset{||}{C}} - \overset{-}{O}$$

The tripeptide is Glu - Cys - Gly
Question 8
1 / -0

A

B

C

D

Solution

Malononitrile reacts with aldehydes following knoevenagel condensation reaction with the elimination of water molecule.
See the given figure.
Question 9
1 / -0

Identify $$X$$

A

B

C

D

Solution

Answer $$C.$$ See the figure i.
Benzaldehyde undergoes cannizaro reaction with acetophenone in presence of a base. See the giver figure ii, ii and iv.
Question 10
1 / -0

A

B

C

D

Solution

Hydrolysis (complete) produces carboxylic acid from cyanide / nitriles.
So, correct answer is option $$A$$.