Aldehydes Ketones and Carboxylic Acids Test

Result

Aldehydes Ketones and Carboxylic Acids Test - 43

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

A

B

C

D

Solution
Question 2
1 / -0

What are the suitable reagent for following conversion

A
$$Br_2/FeBr_3, KMnO_4, HNO_3 / H_2SO_4$$

B
$$KMnO_4, Br_2/ FeBr_3, HNO_3$$

C
$$HNO_3, Br_2 / FeBr_3, KMnO_4$$

D
$$HNO_3, KMnO_4, Br_2 / FeBr_3$$

Solution

this is suitable answer
Question 3
1 / -0

Which of the following is isobutyric acid?

A
$${CH}_{3}{CH}_{2}{CH}_{2}COOH$$

B
$${({CH}_{3})}_{2}CHCOOH$$

C
$${CH}_{3}{CH}_{2}COOH$$

D
$$(C_2H_5)CH(CH_3)COOH$$

Solution

Isobutyric acid, also known as 2-methyl propanoic acid is a carboxylic acid with structural formula $$(CH_3)_2CHCOOH.$$

Hence option (B) is correct.
Question 4
1 / -0

Which one of the following statements is wrong?

A
Aldehydes and ketones are good reducing agents

B
Aldehydes and ketones are polar compounds

C
Aldehydes are more reactive than ketones

D
Aldehydes and ketones are reduced to alcohols

Solution
Question 5
1 / -0

$${CH}_{3}CH_{2}I\xrightarrow [ ]{ KCN } \xrightarrow [ \Delta ]{ { H }_{ 2 }O } $$
here the end product would be:

A
2-cyanorpopanoic acid

B
ethane-1,1-dicarboxylic acid

C
2-methyl ethanoic acid

D
propanoic acid

Solution

Complete Reaction:
$$\mathrm{CH_3-CH_2I \xrightarrow{KCN} CH_3CH_2-CN\xrightarrow[\Delta]{H_2O} \underset{Propanoic \ Acid}{CH_3CH_2COOH}}$$

Hence, Option "D" is the correct answer.
Question 6
1 / -0

Which of the following has the highest $$p{K}_{a}$$ value?

A

B

C

D

Solution

The order of acidic strengths of given compounds is $$\mathrm{B>D>C>A}$$

Stronger the acid is, lower is its $$\mathrm{pK_a}$$ value.
So, the order of $$\mathrm{pK_a}$$ values of given compounds is $$\mathrm{A>C>D>B}$$

Hence, Option "A" is the correct answer.
Question 7
1 / -0

Soaps can be classified as:

A
carbohydrates

B
ethers

C
salts of fatty acids

D
none of these

Solution

Soaps can be classified as salts of fatty acids.
Question 8
1 / -0

The strongest of the four acids listed below is:

A
$$HCOOH$$

B
$$CH_3COOH$$

C
$$ClCH_2COOH$$

D
$$FCH_2COOH$$

Solution

As the fluorine is electronegative atom stabilises the conjugate base, hence it is stronger acid.
Question 9
1 / -0

The general formula for monocarboxylic acids is

A
$$C_nH_nCOOH$$

B
$$C_nH_{2n+1}COOH$$

C
$$C_nH_{2n-1}COOH$$

D
$$C_nH_{2n}O_2$$

Solution

General formula of monocarboxylic acid is $$C_nH_{2n+1}COOH $$ or $$C_nH_{2n}O_2$$ .
Question 10
1 / -0

The IUPAC name of the following compound is

$$\begin{matrix} HOOC & - & { CH }_{ 2 } & - & CH & - & { CH }_{ 2 } & - & { CH }_{ 2 } & - & COOH \\ & & & & | & & & & & & \\ & & & & COOH & & & & & & \end{matrix}$$

A
$$2-$$(Carboxy methyl)-pentane$$-1,5-$$dioic acid

B
$$3-$$Carboxy hexane$$-1,6-$$dioic acid

C
Butane$$-1,2,4-$$tricarboxylic acid

D
$$4-$$Carboxy hexane$$-1,6-$$dioic acid

E
$$1,2$$ dicarboxypentanoic acid

Solution

The IUPAC name of the compound is Butane$$-1,2,4-$$tricarboxylic acid.

$$\begin{matrix} HOOC & - & { \overset{1}CH }_{ 2 } & - & \overset{2}CH & - & { \overset{3}CH }_{ 2 } & - & { \overset{4}CH }_{ 2 } & - & COOH \\ & & & & | & & & & & & \\ & & & & COOH & & & & & & \end{matrix}$$