Amines Test

Result

Amines Test - 11

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Weekly Quiz Competition

Question 1
1 / -0

Correct energy profile for amine inversion and hybridization of nitrogen in transition state is:

A

B

C

D

Solution

Amine is $$sp^3$$ hybridised and the transition state in $$Sp^2$$ hybridised as the lone pair enters the nucleus leaving behind a vacant orbital. And after sometime, the lone pair popes out of the either side, since the inverted amine is an enantiomer, the $${\text {energy remains the same}}$$.
Option D is the correct curve.
Question 2
1 / -0

Which one of the following will be most basic?

A
Aniline

B
P-methoxyaniline

C
P-nitroaniline

D
Benzylamine

Solution

Aliphatic amines are more basic than aromatic amines. This is because lone pair of nitrogen takes part in resonance in case of aromatic amines and hence, are less available for donation. Thus, benzylamine $$(C_{6}H_{5}CH_{2}NH_{2})$$ is most basic among the given.
Question 3
1 / -0

Which of the following statements is not correct?

A
Methylamine is more basic than $$NH_{3}$$.

B
Amines form hydrogen bonds.

C
Ethylamine has higher boiling point than propane.

D
Dimethylamine is less basic than methylamine.

Solution

As the number of electron donating groups increases, basic character increases.
Thus, dimethylamine is more basic than methyl amine.
All other statements are correct.
Question 4
1 / -0

A primary amine {B), on treatment with a solution of $$AuCl_{3}$$ in conc. $$HCl$$ yields a compound whose formula would be?

A
$$(BH)^{+}.AuCl_{4}^{-}$$

B
$$(BH_{2})^{+}.AuCl_{4}^{-2}$$

C
$$(BH)^{+}.HAuCl_{4}^{-}$$

D
$$B.AuCl_{4}$$

Solution

$$B+AuCl_3 \xrightarrow []{HCl}(BH)^+AuCl_4^-$$ .
Question 5
1 / -0

Amine that can't be prepared by Gabriel phthalimide synthesis is:

A
Aniline

B
Benzylamine

C
Methyl amine

D
Iso-butyl amine

Solution

Gabriel phthalamide cannot be used to prepare aromatic amines since aromatic halides donot undergo nucleophilic subsitution from the salt formed by phthalamide. Hence A is the correct answer
Question 6
1 / -0

Identify the statement about the basic nature of amines.

A
Alkylamines are weaker bases than ammonia

B
Arylamines are stronger bases than alkyl amines

C
Secondary aliphatic amines are stronger bases than
primary aliphatic amines

D
Tertiary aliphatic amines are weaker bases than
arylamines

Solution

The lone pair of the electron on nitrogen atom present is arylamines is less available for protonation partly due to -I effect of a phenyl group and mostly due to resonance. Hence aryl amines are weaker bases than alkyl amines.
Also, the secondary amines are a stronger base than the primary amines as the number of alkyl groups attached to the nitrogen atoms are more in secondary alkyl amines.
Question 7
1 / -0

Which of the following compound gives secondary amine on reduction?

A
Alkyl nitrile

B
Carbylamine

C
Primary amine

D
Secondary nitro compound

Solution

here carbylamine is given secondary amine
so B is correct
Question 8
1 / -0

Product D is

A
$$H_5C_2-NH_2$$

B
$$H_5C_2-OH$$

C

D
None
Question 9
1 / -0

Benzylamine is a stronger base than________________

A
Aniline

B
Acetamide

C
o-methylaniline

D
All of these
Question 10
1 / -0

Which is most basic among the following?

A
$$C{H}_{3}N{H}_{2}$$

B
$$C{H}_{3}C{H}_{2}N{H}_{2}$$

C
$$N{H}_{3}$$

D
$$(C{H}_{3})_{2}CHN{H}_{2}$$

Solution

The basic character of a compound is determined by the stability of the conjugate acid. Among the following alternatives, D will be the most basic due to stabilization of the conjugate acid by the positive inductive as well as the hyperconjugation effect of the two methyl groups