Amines Test

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Amines Test - 12

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Weekly Quiz Competition

Question 1
1 / -0

The strongest base in aqueous solution among the following amines is:

A
N-N-diethylethanamine

B
N-ethylethanamine

C
N-methylmethanamine

D
ethanamine

E
phenylmethanamine

Solution
Question 2
1 / -0

Diphenyl hydrazine is same as :

A
azoxybenzene

B
azobenzene

C
hydrazobenzene

D
aniline

Solution

Diphenyl hydrazine is same as hydrazobenzene.
Two phenyl groups are attached to two nitrogen atoms of hydrazine.
Question 3
1 / -0

Which of the following is a secondary amine?

A
$${ H }_{ 2 }N-{ NH }_{ 2 }$$

B
$${ CH }_{ 3 }-{ NH }_{ 2 }$$

C
$$\left( { CH }_{ 3 } \right) _{ 2 }{ NC }_{ 6 }{ H }_{ 5 }$$

D
$$C_{ 6 }{ H }_{ 5 }-NH-{ CH }_{ 3 }$$

Solution

$$C_{6}H_{5}NHCH_{3}$$ contains 2 alkyl group attached to the nitrogen atom
So, it is a secondary amine
Question 4
1 / -0

Out of the following compounds, which is the most basic in aqueous solution?

A
$${ CH }_{ 3 }{ NH }_{ 2 }$$

B
$$\left( { CH }_{ 3 } \right) _{ 2 }NH$$

C
$$\left( { CH }_{ 3 } \right) _{ 3 }N$$

D
$${ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$

Solution

$$(CH_{3})_{2}NH$$ is the most basic compound out of the compounds given.

The explanation is as follows :
It is more basic than $$CH_{3}NH_{2}$$ because of one more methyl group that increases basicity by $$+I$$ effect.

But a number of factors count into basicity.
One of the important ones being the solvation effect.

In $$N(CH_{3})_{3}$$, due to excess steric hinderance, the solvation of the resulting ion is reduced. So, the conjugate acid is not much stabilized. So, it is less basic.

Option B is correct.
Question 5
1 / -0

$$o-Br-{ C }_{ 6 }{ H }_{ 4}-{ NH }_{ 2 }$$ is :

A
aliphatic $${ 1 }^{ 0 }$$ - amine

B
aromatic $${ 1 }^{ 0 }$$ - amine

C
aliphatic $${ 2 }^{ 0 }$$ - amine

D
aromatic $${ 2 }^{ 0 }$$ - amine

Solution

Since a benzenoid ring is attached directly to the nitrogen atom, it is an aromatic amine.
Also, only 1 hydrogen of ammonia is replaced by alkyl group and there are 2 hydrogens intact. So, it is a $$1^0$$ amine.

Hence, option $$B$$ is correct.
Question 6
1 / -0

Which of the following is a secondary amine?

A
Dimethylamine

B
Aniline

C
Isobutylamine

D
Secondary butyl amine

Solution

Dimethylamine is $$(CH_{3})_{2}NH$$
So clearly, 2 alkyl groups are attached to the nitrogen atom.
So, it is a secondary amine
Question 7
1 / -0

The correct order of basic strength is:

A
$${ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }>{ CH }_{ 3 }{ NH }_{ 2 }>{ NH }_{ 3 }$$

B
$${ CH }_{ 3 }{ NH }_{ 2 }>{ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }>{ NH }_{ 3 }$$

C
$${ CH }_{ 3 }{ NH }_{ 2 }>{ NH }_{ 3 }>{ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$

D
$${ NH }_{ 3 }={ CH }_{ 3 }{ NH }_{ 2 }={ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$

Solution

To determine the order of basicity of amines, we have to check for the availability of lone pair, means how easily the lone pair on the nitrogen atom is available for the attack of an electrophile.
A) $$NH_3$$:- it has lone pair which is available on it.
B) $$CH_3NH_2$$:- there is positive inductive effect of methyl group, so electron density on nitrogen is more than that of $$NH_3$$.
C) $$C_6H_5NH_2$$:- the lone pair of nitrogen is taking part in resonance with benzene ring, so it is least available to the attack of an electrophile compared to others.
So, the order is $${ CH }_{ 3 }{ NH }_{ 2 }>{ NH }_{ 3 }>{ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$.
Question 8
1 / -0

The total number of $$\sigma$$ and $$\pi$$ bonds present in azobenzene are:

A
$$24\sigma$$, $$6\pi$$

B
$$25\sigma$$, $$7\pi$$

C
$$28\sigma$$, $$6\pi$$

D
$$27\sigma$$, $$6\pi$$

Solution

A single bond contains 1 $$\sigma$$-bond and a double bond contains one $$\sigma$$ and one $$\pi$$-bond.

Azobenzene contains 25 $$\sigma$$ bonds and 7 $$\pi$$ bonds.

Hence, the correct option is 'B'
Question 9
1 / -0

Gabriel phthalimide reaction is used for the preparation of:

A
primary aromatic amines

B
secondary amines

C
primary aliphatic amines

D
tertiary amines

Solution

Gabriel phthalimide reaction is used for the preparation of primary aliphatic amines.
In presence of $$NaOH$$ or $$KOH$$, phthalimide reacts with primary aliphatic alkyl halide to form primary aliphatic amine.
Here, $$-X$$ group is replaced with $$-NH_2$$ group. The side product is phthalic acid.
Question 10
1 / -0

Which of the following is a $${ 1 }^o$$ amine?

A
$$\left( { CH }_{ 3 } \right) _{ 3 }{ CNH }_{ 2 }$$

B
$${ C }_{ 6 }{ H }_{ 5 }{ NHCH }_{ 3 }$$

C
$${ CH }_{ 3 }NHCH\left( { CH }_{ 3 } \right) _{ 2 }$$

D
$$\left( { CH }_{ 3 }{ CH }_{ 2 } \right) _{ 2 }NCH_{ 3 }$$

Solution

In a one degree amine, only one hydrogen atom of $$NH_3$$ is replaced by alkyl group.

So, A is correct because one of the hydrogens has been replaced by $$(CH_{3})_{3}C-$$ group.

General formula for primary amine is $$RNH_2$$

Note that the kind of alkyl group does not matter in deciding the type of amine, what matters is the number of hydrogen replaced.

Option A is correct.

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Re-Attempt Weekly Quiz Competition

Amines Test - 12

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Amines Test - 12

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Question 1

N-N-diethylethanamine

N-ethylethanamine

N-methylmethanamine

ethanamine

phenylmethanamine

Solution

Question 2

azoxybenzene

azobenzene

hydrazobenzene

aniline

Solution

Question 3

$${ H }_{ 2 }N-{ NH }_{ 2 }$$

$${ CH }_{ 3 }-{ NH }_{ 2 }$$

$$\left( { CH }_{ 3 } \right) _{ 2 }{ NC }_{ 6 }{ H }_{ 5 }$$

$$C_{ 6 }{ H }_{ 5 }-NH-{ CH }_{ 3 }$$

Solution

Question 4

$${ CH }_{ 3 }{ NH }_{ 2 }$$

$$\left( { CH }_{ 3 } \right) _{ 2 }NH$$

$$\left( { CH }_{ 3 } \right) _{ 3 }N$$

$${ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$

Solution

Question 5

aliphatic $${ 1 }^{ 0 }$$ - amine

aromatic $${ 1 }^{ 0 }$$ - amine

aliphatic $${ 2 }^{ 0 }$$ - amine

aromatic $${ 2 }^{ 0 }$$ - amine

Solution

Question 6

Dimethylamine

Aniline

Isobutylamine

Secondary butyl amine

Solution

Question 7

$${ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }>{ CH }_{ 3 }{ NH }_{ 2 }>{ NH }_{ 3 }$$

$${ CH }_{ 3 }{ NH }_{ 2 }>{ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }>{ NH }_{ 3 }$$

$${ CH }_{ 3 }{ NH }_{ 2 }>{ NH }_{ 3 }>{ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$

$${ NH }_{ 3 }={ CH }_{ 3 }{ NH }_{ 2 }={ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$

Solution

Question 8

$$24\sigma$$, $$6\pi$$

$$25\sigma$$, $$7\pi$$

$$28\sigma$$, $$6\pi$$

$$27\sigma$$, $$6\pi$$

Solution

Question 9

primary aromatic amines

secondary amines

primary aliphatic amines

tertiary amines

Solution

Question 10

$$\left( { CH }_{ 3 } \right) _{ 3 }{ CNH }_{ 2 }$$

$${ C }_{ 6 }{ H }_{ 5 }{ NHCH }_{ 3 }$$

$${ CH }_{ 3 }NHCH\left( { CH }_{ 3 } \right) _{ 2 }$$

$$\left( { CH }_{ 3 }{ CH }_{ 2 } \right) _{ 2 }NCH_{ 3 }$$

Solution

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