Amines Test

Result

Amines Test - 19

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which of the following is the most stable diazonium salt?

A
$$C_6H_5CH_2N_2^+X^-$$

B
$$CH_3N_2^+X^-$$

C
$$CH_3CH_2N_2^+X^-$$

D
$$C_6H_5N_2^+X^-$$

Solution

Aliphatic amines do not give diazo compounds. The most stable diazonium salt is $$C_6H_5 N_2^+ X^-$$. Diazonium salt containing aryl group directly linked to the nitrogen atom is most stable due to resonance stabilization between the benzene nucleus and N-atom.
Question 2
1 / -0

Arrange the following in the increasing order of solubility in water:

i) $$ \displaystyle { C}_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$

ii) $$ ({ C }_{ 2 }{ H }_{5 }{ ) }_{ 2 }NH $$

iii) $$ { C }_{ 2 }{ H }_{ 5}{ NH }_{ 2 } $$

A
i < ii < iii

B
ii < i < iii

C
iii < i < ii

D
iii < ii < i

Solution

The decreasing order of solubility in water; is iii) $$ { C }_{ 2 }{ H }_{ 5}{ NH }_{ 2 } $$ > ii) $$ ({ C }_{ 2 }{ H }_{5 }{ ) }_{ 2 }NH $$ > i) $$ \displaystyle { C}_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$

The extent of $$H$$ bond formation in iii) $$ { C }_{ 2 }{ H }_{ 5}{ NH }_{ 2 } $$ is maximum as it has two $$H$$ attached to $$N. $$ Hence, it has highest solubility. $$ \displaystyle { C}_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$ solubility is least due to large hydrophobic part.

So, the correct option is $$A.$$
Question 3
1 / -0

How many primary amines are possible with the formula $$\displaystyle { C }_{ 4 }{ H }_{ 11 }N$$?

A
1

B
2

C
3

D
4

Solution

The possible primary amine with the formula $$\displaystyle { C }_{ 4 }{ H }_{ 11 }N$$ are

(i) $$\displaystyle { CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }{ CH }_{ 2 }{ NH }_{ 2 }$$

(ii) $$\displaystyle { CH }_{ 3 }\overset { \overset { { CH }_{ 3 } }{ | } }{ CH } -{ CH }_{ 2 }-{ NH }_{ 2 }$$

(iii) $$\displaystyle { CH }_{ 3 }-\overset { \overset { { CH }_{ 3 } }{ | } }{ \underset { \underset { { NH }_{ 2 } }{ | } }{ C } } -{ CH }_{ 3 }$$

(iv) $$\displaystyle { CH }_{ 3 }-{ CH }_{ 2 }-\underset { \underset { { CH }_{ 3 } }{ | } }{ CH } -{ NH }_{ 2 }$$
Question 4
1 / -0

Methyl amine reacts with methyl iodide. For completion of reaction, how many moles of methyl iodide are required?

A
1

B
2

C
3

D
4

Solution

$$\therefore$$ 3 moles of $$C{H}_{3}I$$ (methyl iodide) are required for reaction with methyl amine.

The correct answer is 3.
Question 5
1 / -0

Acetonitrile $$\xrightarrow { Hydrolysis } $$ ?

A
Acetic acid

B
Propionic acid

C
Formic acid

D
None of these

Solution

Cyanides on hydrolysis give carboxylic acid and $$N{H}_{3}$$.

Option A is correct.
Question 6
1 / -0

Acetonitrile on reduction gives:

A
propanamine

B
methanamine

C
ethanamine

D
none of these

Solution

Cyanides on reduction give $$1$$ amine.
Question 7
1 / -0

Ethylamine is ?

A
$$\displaystyle { CH }_{ 3 }-{ CH }_{ 2 }-{ CH }_{ 3 }$$

B
$$\displaystyle CH_3-\underset {\displaystyle \underset {\displaystyle O}{ ||}}{C}-OH$$

C
$$\displaystyle { CH }_{ 3 }-O-{ C }_{ 3 }{ H }_{ 7 }$$

D
$$\displaystyle CH_3-\underset {\displaystyle \underset {\displaystyle O}{ ||}}{C}-CH_3$$

E
$$\displaystyle CH_3 - CH_2- NH_2$$

Solution

Ethylamine is $$\displaystyle CH_3CH_2NH_3$$. It is organic derivative of ammonia in which one H atom attached to nitrogen is replaced by ethyl group.
Question 8
1 / -0

Primary amine $$(RNH_2)$$ reacts with nitrous acid to give :

A
$$RNH_3^+NO_2$$

B
ROH

C
ROR

D
None of these

Solution

$$1^o$$ aliphatic amines on reaction with $$HNO_2$$ from alcohol and evolve $$N_2$$
$$RNH_2+HONO \xrightarrow [ ]{NaNO_2-HCl} ROH + N_2+H_2$$
Question 9
1 / -0

The decreasing order of basic character of the three amines and ammonia is :

A
$$NH_{3} > CH_{3} NH_{2} > C_{2}H_{5}NH_{2} > C_{6}H_{5} NH_{2}$$

B
$$C_{2}H_{5}NH_{2} > CH_{3} NH_{2} > NH_{3} > C_{6}H_{5}NH_{2}$$

C
$$C_{6}H_{5}NH_{2} > C_{2}H_{5}NH_{2} > CH_{3}NH_{2} > NH_{3}$$

D
$$CH_{3} NH_{2} > C_{2}H_{5}NH_{2} > C_{6}H_{5}NH_{2} > NH_{3}$$

Solution

(i) Electron donors are bases.
(ii) Electron withdrawing groups (eg, benzyl) decrease the basicity of amines.
(iii) Electron donating groups (eg, alkyl) increase the acidity of amines.
$$\therefore$$ The correct order of basicity of amines in
$$C_{2}H_{5}NH_{2} > CH_{3}NH_{2} > NH_{3} > C_{6}H_{5}NH_{2}$$
Question 10
1 / -0

Which compound is different from the others?

A
Methyl ethyl ketone

B
Pentan-2-one

C
2-Pentanone

D
Methyl propyl ketone

Solution

Methyl ethyl ketone ( $$\displaystyle CH_3 - \underset { \underset {\displaystyle O}{||} }{C} - CH_2-CH_3$$) is different from the others.

Methyl ethyl ketone (also called butanone) contains $$4 C$$ atoms.

Pentan-2-one, 2-pentanone and methyl propyl ketone are different names of same compound $$\displaystyle CH_3 - \underset { \underset {\displaystyle O}{||} }{C} - CH_2-CH_2-CH_3$$ which contains $$5 C$$ atoms.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Amines Test - 19

Result

Amines Test - 19

Score

-

Rank

-

SHARING IS CARING

Question 1

$$C_6H_5CH_2N_2^+X^-$$

$$CH_3N_2^+X^-$$

$$CH_3CH_2N_2^+X^-$$

$$C_6H_5N_2^+X^-$$

Solution

Question 2

i < ii < iii

ii < i < iii

iii < i < ii

iii < ii < i

Solution

Question 3

1

2

3

4

Solution

Question 4

1

2

3

4

Solution

Question 5

Acetic acid

Propionic acid

Formic acid

None of these

Solution

Question 6

propanamine

methanamine

ethanamine

none of these

Solution

Question 7

$$\displaystyle { CH }_{ 3 }-{ CH }_{ 2 }-{ CH }_{ 3 }$$

$$\displaystyle CH_3-\underset {\displaystyle \underset {\displaystyle O}{ ||}}{C}-OH$$

$$\displaystyle { CH }_{ 3 }-O-{ C }_{ 3 }{ H }_{ 7 }$$

$$\displaystyle CH_3-\underset {\displaystyle \underset {\displaystyle O}{ ||}}{C}-CH_3$$

$$\displaystyle CH_3 - CH_2- NH_2$$

Solution

Question 8

$$RNH_3^+NO_2$$

ROH

ROR

None of these

Solution

Question 9

$$NH_{3} > CH_{3} NH_{2} > C_{2}H_{5}NH_{2} > C_{6}H_{5} NH_{2}$$

$$C_{2}H_{5}NH_{2} > CH_{3} NH_{2} > NH_{3} > C_{6}H_{5}NH_{2}$$

$$C_{6}H_{5}NH_{2} > C_{2}H_{5}NH_{2} > CH_{3}NH_{2} > NH_{3}$$

$$CH_{3} NH_{2} > C_{2}H_{5}NH_{2} > C_{6}H_{5}NH_{2} > NH_{3}$$

Solution

Question 10

Methyl ethyl ketone

Pentan-2-one

2-Pentanone

Methyl propyl ketone

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.