Amines Test

Result

Amines Test - 41

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Weekly Quiz Competition

Question 1
1 / -0

Treatment of cyclobutylmethyl amine with nitrous acid does not give.

A

B

C

D

E

Solution
Question 2
1 / -0

What is the increasing order of basic strength of the following compounds in aqueous solutions?

A
$$III < I < II < IV$$

B
$$I < II < IV < III$$

C
$$I < II < III < IV$$

D
$$III < I < IV < II$$

Solution
Question 3
1 / -0

Which of the following amines will react with cyclohexane to give enamine?

A
$$C{H_3}N{H_2}$$

B
$${(C{H_3})_2}NH$$

C

D

Solution
Question 4
1 / -0

Among the following which one is most basic?

A
$$ NH_3 $$

B
$$ CH_3 NH_2 $$

C
$$ CH_3 CH_2NH_2 $$

D
$$ C_6H_5NH_2 $$

Solution

The basicity of the among compounds is due to the presence of lone pair on Nitrogen.

$$CH_3CH_2NH_2$$ is more basic than $$NH_3$$ because of electron-donating group in $$CH_3CH_2NH_2$$ increases the electron density on nitrogen atom. $$CH_3NH_2$$ is less basic than $$CH_3CH_2NH_2$$ because of ethyl group present in ethylamine which increases electron density on N in ethylamine and attracts $$H^+$$ better than methylamine.

$$C_6H_5NH_2$$ is less basic than ethylamine because in $$C_6H_5NH_2$$ the lone pair of electron on nitrogen is less available for protonation. It is delocalised into the Benzene ring by resonance. In ethylamine no such delocalisation takes place.

Hence, among them $$CH_3CH_2NH_2$$ is most basic.
Question 5
1 / -0

The strongest base among the following is:

A
Amide ion

B
Hydroxide ion

C
Trimethylamine

D
Ammonia

E
Aniline

Solution

Lesser the stability of the species ion, more basic be the given species. As $$NH_2^-$$ (amide ion) is the least stable species ion. Thus, it is the most basic species.

Hence, option A is the correct answer.
Question 6
1 / -0

N-Ethylphthalimide $$\longrightarrow $$ Ethylamine
Reagent for the conversion of this reaction is:

A
$$H_2O$$

B
$$NaBH_4$$

C
$$NH_2-NH_2$$

D
$$CaH_2$$

Solution
Question 7
1 / -0

The correct order of $$K_b$$ value of following is:
$$(C_2H_5)_2\ddot{N}H, NH_3, \ddot{N}(C_2H_5)_3$$

A
$$1 > 2 > 3$$

B
$$1 > 3 > 2$$

C
$$3 > 2 > 1$$

D
$$3 > 1 > 2$$

Solution

$$+I$$ effect is maximum in secondary amine and minimum in primary amine.
Thus the correct order of $$K_b$$ will be
$$(C_2H_5)_2\ddot{N}H > \ddot{N}(C_2H_5)_3 > NH_3$$
Question 8
1 / -0

This set contains the questions with single correct answer.

A
primary amine

B
secondary amine

C
tertiary amine

D
quaternary salt

Solution

N attech with one carbon so it is primary amine
Question 9
1 / -0

In the following componds the order of basicity is:

A
I > IV > II > III

B
II > I > IV > III

C
III > I > IV > II

D
IV > I > III > II

Solution

A specie with a higher ability to donate electrons is more basic.

In III, electrons of Nitrogen are in resonance. So, it has the least tendency to donate electrons. Hence, is the least basic among the all given.

$$\mathrm{sp^3}$$ hybridized Nitrogen has more tendency to donate electrons than $$\mathrm{sp^2}$$ hybridized Nitrogen.

In Iv, the compound has a lesser tendency to donate electrons than that in I because of steric hindrance.

So, the order of basicity is:
$$\mathrm{I>IV>II>III}$$

Hence, Option "A" is the correct answer.
Question 10
1 / -0

Which one of the following is the weakest base?

A
$$ (C_2H_5)_3 N $$

B
$$ (C_2H_5)_2 NH $$

C
$$ C_2H_5NH_2 $$

D
$$ NH_3 $$

Solution

The $$+I$$ effect increases with increase in the alkyl group.Therefore the basic strength will be the highest in $$(C_2H_5)3N$$ and least in $$NH_3$$. Therefore the decreasing order of basic strength in gas phase will be $$(C_2H_5)3N > (C_2H_5)2NH > C_2H_5NH_2 > NH_3$$.