Amines Test

Result

Amines Test - 45

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Weekly Quiz Competition

Question 1
1 / -0

Potassium phthalimide reacts with 'A' which on hydrolysis gives isopentylamine, whiat is 'A'?

A

B

C

D

Solution

hence A is correct answer
Question 2
1 / -0

Which is most basic?

A
$$C_6H_5NH_2$$

B
$$(C_6H_5)_2NH$$

C
$$C_2H_5NH_2$$

D
$$(C_2H_5)_2NH$$

Solution

option D have less resonating and secondry amine so this is most basic
Question 3
1 / -0

Which is most basic?

A
Aniline

B
p-nitroaniline

C
Benzylamine

D
p-methylaniline

Solution

in p-nitroaniline, acetanilide and aniline, the lone pair of nitrogen is in conjugation with the aromatic system (benzene ring). So, it is delocalized and is not freely available for donation. so they are less basic and
option C is most basic
Question 4
1 / -0

An isonitrile on reduction gives:

A
$$3^oamine$$

B
$$2^oamine$$

C
$$1^oamine$$

D
quaternary ammonium salts

Solution

Reduction of isocyanide by LiAlH4 gives secondary amines, in which nitrogen is directly attached to one hydrogen and two alkyl groups.
Question 5
1 / -0

Which has the highest $$pK_b$$ value?

A
$$R_3C-NH_2$$

B
$$R_2NH$$

C
$$RNH_2$$

D
$$NH_3$$

Solution

when a compound attech with alkyl compound so the pKb value is less so amine NH3 have highest value of Pkb
Question 6
1 / -0

Which on reduction does not give primary amine?

A
$${ CH }_{ 3 }CN$$

B
$${ C }_{ 2 }{ H }_{ 5 }NC$$

C
$${ CH }_{ 3 }{ CONH }_{ 2 }$$

D
All of these

Solution

$$C_2H_5NC$$ is after reaction not give primary amine
Question 7
1 / -0

The basicity of compounds I, II, III and IV varies in the order:
$$\underset { I }{ { CH }_{ 3 }{ NH }_{ 2 } } $$, $$\underset { II }{ { (CH }_{ 3 }{ )_{ 2 }NH } } $$, $$\underset { III }{ { (CH }_{ 3 }{ )_{ 3 }N } } $$, $$\underset { IV }{ { C }_{ 6 }{ H }_{ 5 }{ CH }_{ 2 }{ NH }_{ 2 } } $$

A
I>II>III>IV

B
II>I>III>IV

C
III>I>II>IV

D
IV>I>II>III

Solution

$$(i)$$ The order of basicity of amines in aqueous solution is :
secondary $$>$$ primary $$>$$ tertiary

$$(ii)$$ In case of benzylamine, the phenyl ring $$(C_6H_5)$$ is slightly electron withdrawing. So, the electron density on the nitrogen atom is less in benzylamine in comparison to that of primary amine.

Hence, from the above two points, the correct order of basicity of amines is : $$(CH_{3})_{2}NH>CH_{3}NH_{2}>(CH_{3})_{3}N>C_6H_5CH_{2}NH_{2}$$
$$II$$ $$I$$ $$III$$ $$IV$$
So, option (B) is correct.
Question 8
1 / -0

The correct order of basic nature in aqueous solution is:

A
$$C_6H_5NH_2>NH_3>CH_3NH_2>(CH_3)_2NH$$

B
$$NH_3>C_6H_5NH_2>CH_3NH_2>(CH_3)_2NH$$

C
$$(CH_3)_2NH>CH_3NH_2>NH_3>C_6H_5NH_2$$

D
$$CH_3NH_2>(CH_3)_2NH>NH_3>C_6H_5NH_2$$

Solution

$$(CH_3)_2NH>CH_3NH_2>NH_3>C_6H_5NH_2$$

the secondry amine is most basic than primary then amine other molecule
Question 9
1 / -0

Which one of the following is most basic?

A
$$FCH_2NH_2$$

B
$$FCH_2CH_2NH_2$$

C
$$C_6H_5NH_2$$

D
$$C_6H_5CH_2NH_2$$

Solution

benzene structure is more resonance and increase the basicity so ateech benzene with CH3Nh2 is more basic
hence D is correct answer
Question 10
1 / -0

Reduction of alkyl nitrile produces:

A
secondary amine

B
primary amine

C
tertiary amine

D
amide

Solution

The nitrile reacts with the lithium tetrahydridoaluminate in solution in ethoxyethane (diethyl ether, or just "ether") followed by treatment of the product of that reaction with dilute acid. Overall, the carbon-nitrogen triple bond is reduced to give a primary amine. Primary amines contain the -NH2 group.
hence B is correct answer