Amines Test

Result

Amines Test - 47

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Weekly Quiz Competition

Question 1
1 / -0

A secondary amine is

A
An organic compound with two - $$ NH_{2} $$ groups

B
A compound with two carbon atoms and an -$$ NH_{2} $$ group

C
A compound with an-$$ NH_{2} $$ group on the carbon atom in number 2 position.

D
A compound in which two of the hydrogens of $$ NH_{3} $$ have been replaced by organic groups.

Solution

An amine in which the amino group is directly bonded to two carbons of any hybridization and this is happen when a organic compound with 2 amine group

Hence A is correct answer
Question 2
1 / -0

$$ CH_{2}= CH-CH_{2}-NH-CH_{3} $$ is a

A
Secondary amine

B
Primary amine

C
Tertiary amine

D
None of these

Solution

in this given structure amine is bond with 2 carbon atom so. this is a secondary carbon
Question 3
1 / -0

The order of basic strength among the following amines in benzene solution is

A
$$CH_{3}NH_{2}> (CH_{3})_{3} N> (CH_{3})_{2}NH$$

B
$$(CH_{3})_{2}NH> CH_{3}NH_{2}> (CH_{3})_{3}N$$

C
$$CH_{3}NH_{2}> (CH_{3})_{2}NH> (CH_{3})_{3}N$$

D
$$(CH_{3})_{3}N> CH_{3}NH_{2}> (CH_{3})_{2}NH$$

Solution

$$(CH_{3})_{2} NH \quad> CH_{3}NH_{2} \quad> (CH_{3})_{3}N$$
$$K_{b} = 5.4\times 10^{-4} \ \ 4.5\times 10^{-4} \quad 0.6\times 10^{-4}$$
Question 4
1 / -0

The correct order of basicities of the following compounds is

A
$$2> 1> 3> 4$$

B
$$1> 3> 2> 4$$

C
$$3> 1> 2> 4$$

D
$$1> 2> 3> 4$$

Solution

The correct order is 2>1>3>4
Because oh the ethyl amine is most basic than amide and 2 degree amine
Question 5
1 / -0

Which of the following compound is the strongest base?

A
Ammonia

B
Aniline

C
Methylamine

D
N-methyl aniline

Solution

Methyl amine is the strongest base.
Question 6
1 / -0

Order of basicity of ethyl amines in aqueous medium is

A
$$Secondry> primary> Tertiary$$

B
$$primary>Secondry>Tertiary$$

C
$$Secondry>Tertiary> primary$$

D
$$Tertiary> primary> Secondry$$

Solution

order of basicity in aqueous medium in methylamines is secondary>primary>tertiary. But in the case of ethylamines it is secondary>tertiary>primary.
Question 7
1 / -0

Gabriel's phthalimide synthesis is used for the preperation of

A
primary aromatic amine

B
Secondary acid

C
Primary aliphatic amine

D
Tertiary amine

Solution

Gabriel phthalimide synthesis is used for the preparation of aliphatic primary amines. Since ethanamine is the only primary amine among the given compounds,

Hence primary aromatic amine is correct answer.
Question 8
1 / -0

Which of the following compound is expected to be most basic

A
Aniline

B
Methylamine

C
Hydroxylamine

D
Ethylamine

Solution

Due to +ve I.E. of alkyl group, N-atom of amines acquires patrial -ve charge and thus electron pair is easily donated. Hence most basic compound is Ethylamine ($$C_2H_5NH_2$$).
Option D is correct.
Question 9
1 / -0

The strongest base among the following is

A

B

C

D

Solution

does not have aromaticity by which the lone pair of electron of nitrogen does not delocalised in benzene ring so it will be strong base on other hand rest 3 have aromaticity i.e., the follow the huckel rule so the electron pair of Nitrogen delocalised in ring by resonance and resulting they become less basic.
Question 10
1 / -0

Correct the order of increasing basicity is

A
$$NH_3 < C_6H_5NH_2 < (C_2H_5)_2NH < C_2H_5NH_2 < (C_2H_5)_3N$$

B
$$C_6H_5NH_2 < NH_3 < (C_2H_5)_3N < (C_2H_5)_2NH < C_2H_5NH_2$$

C
$$ C_{6}H_{5}NH_{2}< NH_{3}< C_{2}H_{5}NH_{2}< (C_{2}H_{5})_{3}N< (C_{2}H_{5})_{2}NH $$

D
$$C_6H_5NH_2 < (C_2H_5)_3N < NH_3 < C_2H_5NH_2 < (C_2H_5)_2NH$$

Solution

Electron donors are bases. Electron withdrawing groups (eg, benzyl) decrease the basicity of amines and Electron donating groups (eg, alkyl) increase the acidity of amines.
so correct order is
$$C_6H_5NH_2 < (C_2H_5)_3N < NH_3 < C_2H_5NH_2 < (C_2H_5)_2NH$$
Hence D is correct answer