Amines Test

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Amines Test - 48

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Weekly Quiz Competition

Question 1
1 / -0

By the presence of a halogen atom in the ring, basic properties of aniline is

A
Increased

B
Decreased

C
unchanged

D
Doubled

Solution

By the presence of a halogen atom in the ring, basic properties of aniline is increased because it is more electronegative so donation of electron will be easy, so basicity increases.

hence A is correct
Question 2
1 / -0

Which of the following is most basic

A
$$ C_{6}H_{5}NH_{2} $$

B
$$ (CH_{3})_{2}NH $$

C
$$ (CH_{3})_{3}N $$

D
$$ NH_{3} $$

Solution

In general, methylamine $$CH_3NH_2$$) is a stronger base than ammonia (NH3) and dimethylamine $$((CH_3)_2NH$$ is a stronger base than methylamine. However, in water, triethylamine $$((CH_3CH_2)_3N)$$ which should be even stronger based on stronger inductive effect, is a weaker base than dimethylamine or methylamine.

Hence B is correct
Question 3
1 / -0

Which one of the following is not a base

A
$$ N_{2}H_{4} $$

B
$$ N_{2}OH $$

C
$$ (CH_{3})_{3}N $$

D
$$ NH_{3} $$

Solution

substance that accepts and H+ from water is considered a base Both $$NH_3$$ and H2O are amphoteric
Question 4
1 / -0

Which of the following amines would undergoes diazotisation

A
Primary aliphatic amines

B
Primary aromatics amines

C
Both (a) and (b)

D
None of these

Solution

Only primary aromatic amines can undergo diazotization.
Question 5
1 / -0

If methyl is alkyl group, then which order of basicity is correct

A
$$R_{2}NH> RNH_{2}> R_{3}N> NH_{3}$$

B
$$R_{2}NH> R_{3}N> RNH_{2}> NH_{3}$$

C
$$RNH_{2}> NH_{3}> R_{2}NH> R_{3}N$$

D
$$NH_{3}> RNH_{2}> R_{2}NH> R_{3}N$$

Solution

Greater is the stability of the substituted ammonium cation, stronger should be the corresponding amine as a base. Thus, the order of the basicity of aliphatic amines should be primary > secondary > tertiary, which is opposite to the inductive effect based order. Secondly, when the alkyl group is small, like $$CH_3$$ group, there is no steric hindrance to H-bonding. In case the alkyl group is bigger than methyl group, there will be steric hindrance to H-bonding. Therefore, the change of nature of the alkyl group, e.g., from -$$CH_3$$ to$$C_2H_5$$ results in change of the order of basic strength. Thus, there is a subtle interplay of the inductive effect, solvation effect and steric hinderance of the alkyl group which decides the basic strength of alkyl amines in the aqueous state.
Question 6
1 / -0

Which one less of alkaline

A

B

C

D
All of these

Solution

NO2 is electron withdrawing group so the stability is decreasing
Hence A is correct answer
Question 7
1 / -0

The decreasing order of the basic character of the three amines and ammonia is

A
$$ NH_{3}> CH_{3}NH_{2}> C_{2}H_{5}NH_{2}> C_{6}H_{5}NH_{2} $$

B
$$ C_{2}H_{5}NH_{2}> CH_{3}NH_{2}> NH_{3}> C_{6}H_{5}NH_{2} $$

C
$$ C_{6}H_{5}NH_{2}> C_{2}H_{5}NH_{2}> CH_{3}NH_{2}> NH_{3} $$

D
$$ CH_{3}NH_{2}>C_{2}H_{5}NH_{2}>C_{6}H_{5}NH_{2}> NH_{3} $$

Solution

Electron donors are bases. Electron withdrawing groups (eg, benzyl) decrease the basicity of amines and Electron donating groups (eg, alkyl) increase the acidity of amines.
so The correct order of basicity of amines in
$$ C_{2}H_{5}NH_{2}> CH_{3}NH_{2}> NH_{3}> C_{6}H_{5}NH_{2} $$
Hence B is correct answer
Question 8
1 / -0

Among the following compounds nitrobenzene , benzene, aniline and phenol, the strongest basic behaviuor in acid medium is exhibited by :

A
Phenol

B
Aniline

C
Nitrobenzene

D
Benzene

Solution

Because the N atom in aniline has a lone pair to donate and also due to +I effect of -$$ NH_{2} $$ group
Question 9
1 / -0

Among the following the weakest base is

A
$$ C_{6}H_{5}CH_{2}NH_{2} $$

B
$$ C_{6}H_{5}CH_{2}NHCH_{3} $$

C
$$ O_{2}N CH_{2} NH_{2} $$

D
$$ CH_{3} NH CHO $$

Solution

$$CH_3CONH_2>CH_3CH_2NH_2>C_6H_5CH_2NH_2>C_6H_5CH_2NHCH_3$$

So the weekest base is B
Question 10
1 / -0

Arrange the following in increasing order of basicity
$$ CH_{3}NH_{2},(CH_{3})_{2}NH,C_{6}H_{5}NH_{2},(CH_{3})_{3}N $$

A
$$ (CH_{3})_{3}N< (CH_{3})_{2}NH< CH_{3}NH_{2}< C_{6}H_{5}NH_{2} $$

B
$$ (CH_{3})_{3}N> (CH_{3})_{2}NH> CH_{3}NH_{2}> C_{6}H_{5}NH_{2} $$

C
$$ C_{6}H_{5}NH_{2}< (CH_{3})_{3}N< CH_{3}NH_{2}< (CH_{3})_{2}NH $$

D
$$ C_{6}H_{5}NH_{2}> (CH_{3})_{3}N> CH_{3}NH_{2}> (CH_{3})_{2}NH $$

Solution

The correct order is
$$ (CH_{3})_{3}N> (CH_{3})_{2}NH> CH_{3}NH_{2}> C_{6}H_{5}NH_{2} $$
Hence B is correct order

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Re-Attempt Weekly Quiz Competition

Amines Test - 48

Result

Amines Test - 48

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SHARING IS CARING

Question 1

Increased

Decreased

unchanged

Doubled

Solution

Question 2

$$ C_{6}H_{5}NH_{2} $$

$$ (CH_{3})_{2}NH $$

$$ (CH_{3})_{3}N $$

$$ NH_{3} $$

Solution

Question 3

$$ N_{2}H_{4} $$

$$ N_{2}OH $$

$$ (CH_{3})_{3}N $$

$$ NH_{3} $$

Solution

Question 4

Primary aliphatic amines

Primary aromatics amines

Both (a) and (b)

None of these

Solution

Question 5

$$R_{2}NH> RNH_{2}> R_{3}N> NH_{3}$$

$$R_{2}NH> R_{3}N> RNH_{2}> NH_{3}$$

$$RNH_{2}> NH_{3}> R_{2}NH> R_{3}N$$

$$NH_{3}> RNH_{2}> R_{2}NH> R_{3}N$$

Solution

Question 6

All of these

Solution

Question 7

$$ NH_{3}> CH_{3}NH_{2}> C_{2}H_{5}NH_{2}> C_{6}H_{5}NH_{2} $$

$$ C_{2}H_{5}NH_{2}> CH_{3}NH_{2}> NH_{3}> C_{6}H_{5}NH_{2} $$

$$ C_{6}H_{5}NH_{2}> C_{2}H_{5}NH_{2}> CH_{3}NH_{2}> NH_{3} $$

$$ CH_{3}NH_{2}>C_{2}H_{5}NH_{2}>C_{6}H_{5}NH_{2}> NH_{3} $$

Solution

Question 8

Phenol

Aniline

Nitrobenzene

Benzene

Solution

Question 9

$$ C_{6}H_{5}CH_{2}NH_{2} $$

$$ C_{6}H_{5}CH_{2}NHCH_{3} $$

$$ O_{2}N CH_{2} NH_{2} $$

$$ CH_{3} NH CHO $$

Solution

Question 10

$$ (CH_{3})_{3}N< (CH_{3})_{2}NH< CH_{3}NH_{2}< C_{6}H_{5}NH_{2} $$

$$ (CH_{3})_{3}N> (CH_{3})_{2}NH> CH_{3}NH_{2}> C_{6}H_{5}NH_{2} $$

$$ C_{6}H_{5}NH_{2}< (CH_{3})_{3}N< CH_{3}NH_{2}< (CH_{3})_{2}NH $$

$$ C_{6}H_{5}NH_{2}> (CH_{3})_{3}N> CH_{3}NH_{2}> (CH_{3})_{2}NH $$

Solution

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