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Amines Test - 62

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Amines Test - 62
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  • Question 1
    1 / -0
    The correct order of decreasing basicity of the given compounds is :

    Solution

  • Question 2
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    Which is the weakest base among the followings?
    Solution
    Lewis base = The entity that has the tendency to donate electrons,
    Here in $$4th$$ compound, lone pairs of $$N$$ is not going in resonance but two $$Methyl(-CH_3)$$ group are sterically hindered it to donate electrons, that's why it is weakest base.
  • Question 3
    1 / -0
    The solubility of diethyl ether in water is comparable with that of:
    Solution
    Diethyl ether is a common polar aprotic solvent. It has limited solubility in water and dissolves in water. In di-ethyl ether, the flexible chain of atoms sweeps out a volume that prevents hydrogen bonding between the ether oxygen atom and hydrogen atoms of water. But ethanamine soluble in water and form intermolecular $$H-$$ bonds with water. 
  • Question 4
    1 / -0
    Compare the basic strength of compounds given:

    Solution

  • Question 5
    1 / -0
    Which of the following compound is the most basic?
  • Question 6
    1 / -0
    Which of the following aryl amine undergoes diazotization most readily?
    Solution
    Diazotization reaction is an electrophilic
    substitution reaction.
    so, the benzene ring attached with more
    The mesomeric effect group(+M)  will readily
    undergo a diazotization reaction.
    so option $$c$$ is correct.

  • Question 7
    1 / -0
    The correct order of basicites of the following compounds is:-

  • Question 8
    1 / -0
    $$CH_3NH_2     \quad \underrightarrow{{(CH_3COOCH_3)}, { \Delta}} \quad X$$ 
  • Question 9
    1 / -0

    The correct decreasing order of $$p{ K }_{ b }$$:

    Solution
    We know that more is the $$pK_b$$ value ,less  basic will be the given compound.

    Since chlorine exerts $$-I$$ effect  , hence it is least basic and has  more $$pK_b$$ value. 

    Similarly , on basis on electronic effects, the answer is option D.
  • Question 10
    1 / -0
    Diazomethane was photolysed to generate singlet carbine which was treated with cis-2-butene. The main product(s) of the reaction is/are:
    Solution
    Solution:- (A) cis-$$1,2$$-dimethylcyclopropane
    $$\underset{\text{Diazomethane}}{C{H}_{2}-\overset{+}{N}={N}^{-}} \xrightarrow[-N \equiv N]{h \nu} \underset{\text{Singlet carbene} \left( \text{Methylene} \right)}{:C{H}_{2}}$$
    The addition of methylene would yield trans-$$1,2$$-dimethylcyclopropane from trans-$$2$$-butene and cis-$$1,2$$-dimethylcyclopropane from cis-$$2$$-butene.
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