Amines Test

Result

Amines Test - 77

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Weekly Quiz Competition

Question 1
1 / -0

$$o-Br - C_{6}H_{5}-NH_{2}$$

A
aliphatic $$1^{\circ}$$ - amine

B
aromatic $$1^{\circ}$$ - amine

C
aliphatic $$2^{\circ}$$ - amine

D
aromatic $$2^{\circ}$$ - amine
Question 2
1 / -0

What will be the product of the given reaction?

A

B

C

D

Solution

Diazo coupling will take place from the least hindered (ortho, para) position of most activated phenolic ring.
Question 3
1 / -0

Product is:

A

B

C

D

Solution

lone pair on N marked as (c) is most nucleophilic and form the compound as given in the reaction along with $$CH_3I$$
Question 4
1 / -0

What is the most basic nature ?

A

B

C

D
Question 5
1 / -0

Which of the following amine will be prepared by Gabriel phthalimide reaction?

A
n-Butylamine

B
Triethylamine

C
neo-Pentylamine

D
tert-Butylamine

Solution

Gabriel phthalimide reaction is used to prepare primary unhindered amine only. because in Gabriel phthalimide reaction no other place for nitrogen, therefor it attack at terminal position only and after hydrolysis it give primary amine i.e n-Butylamine.
Question 6
1 / -0

Which of the following is not correct regarding basic strength ?

A

B

C

D

Solution

Amines are basic in nature. There basic nature is result of presence of lone pair of electrons on nitrogen. Amines when dissolved in water attract a proton to form alkylammonium ion and a hydroxide ion. The order of basicity is primary <tertiary>secondary. The aromatic amines are weaker bases than ammonia.
Question 7
1 / -0

Which of the following is most basic

A

B

C

D

Solution

So, option D is correct.
Question 8
1 / -0

Which of the following amines can be prepared by Gabriel phthalimide reaction?

A
Neo-pentylamine

B
n-butylamine

C
Triethylamine

D
t-butylamine

Solution

The only primary amine can be prepared from Gabriel phthalimide reaction.
Thus only n-butylamine can be prepared by Gabriel phthalimide reaction.
Question 9
1 / -0

In the following compounds, the decreasing order of basic strength will be:

A
$$(C_2H_5)_2NH>C_2H_5NH_2>NH_3$$

B
$$(C_2H_5)_2NH>NH_3>C_2H_5NH_2$$

C
$$NH_3>C_2H_5NH_2>(C_2H_5)_2NH$$

D
$$C_2H_5NH_2>NH_3>(C_2H_5)_2NH$$

Solution

Solution:- (A) $$(C_2H_5)_2NH>C_2H_5NH_2>NH_3$$
Basic strength order
$$(CH_3CH_2)_2NH>CH_3CH_2NH_2>NH_3$$
$$2^0$$ amine $$1^0$$ amine
Alkyl group shows $$+I$$ effect, and hence increases basicity.
Question 10
1 / -0

Which of the following is NOT a correct method of the preparation of benzylamine from cyanobenzene?

A
(i) $$HCl/ H_{2}O$$ (ii) $$NaBH_{4}$$

B
(i) $$LiAlH_{4}$$ (ii) $$H_{3}O^{+}$$

C
(i) $$SnCl_{2} + HCl(gas)$$ (ii) $$NaBH_{4}$$

D
$$H_{2}/ Ni$$

Solution

Hence option A is correct.