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Amines Test - 79

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Amines Test - 79
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  • Question 1
    1 / -0
    Which of the following is most basic ?
    Solution

  • Question 2
    1 / -0
    In the Gabriel's phthalimide synthesis, phthalimide is treated first with
    Solution

  • Question 3
    1 / -0
    The correct order of decreasing basicity of the following compounds is:

    Solution
    The order of decreasing basicity of the given compounds is (C) $$III > IV > I > II.$$

    As the $$−NH_2$$​ group has a lone pair of electrons on nitrogen to donate to electron-deficient species.

    Hence, its power to donate electrons is increased when an electron donation group $$(+R, +I)$$  is attached and its donating power is decreased when an electron-withdrawing group is attached at its para position. 

    Since $$NO_2$$​ is an electron-withdrawing group hence it decreases the electron density over $$−NH_2$$​ group hence it decreases the basicity. 

    On the other hand $$−OCH_3​ (+M \text{ effect})$$ group increases the electron density more than the $$CH_3\  group (+I \text{effect}).$$
  • Question 4
    1 / -0
    $$(RCO)_2 NH$$ is
    Solution
    $$R-\overset {\overset {\displaystyle O}{||}}{C}-NH_2 \Rightarrow \text {Primary amide}$$

    $$(R-\overset {\overset {\displaystyle O}{||}}{C})_2-NH \Rightarrow \text {Secondary amide}$$

    Option C is correct.
  • Question 5
    1 / -0
    $$ C_{3}H_{9}N $$ represents
    Solution
    $$C_{3}H_{9}N$$ can form all the 3 amines.

    $$CH_{3}\underset{1^{o} amine}{CH_{2}CH_{2}}-NH_{2},CH_{3}-\underset{2^{o} amine}{CH_{2}-NH}-CH_{3}$$

  • Question 6
    1 / -0
    Rank the following compound in the order of decreasing basicity.

    Solution
    $$III$$ is the stronger base due to lack of delocalisation of lone pair of electron. $$II$$ is weaker base than $$I$$ due to electron withdrawing resonance effect of $$-NO_2$$.
  • Question 7
    1 / -0
    Triaminobenzene is a
    Solution
    All nitrogen represents $$1^oC$$ amine in the Triaminobenzene.
    Option C is correct.

  • Question 8
    1 / -0
    Urotropine is 
    Solution
     $$\text{Urotropin is hexa-methylene tetramine .It is used as a medicine to treat urinary infections.}$$

  • Question 9
    1 / -0
    When aniline is treated with sodium nitrate and hydrocholric acid at O.C, it gives 
    Solution
    $$C_{6}H_{5}NH_{2} \xrightarrow {NaNO_{2} + HCl\,O^{\circ}C} C_{6}H_{5}N_{2}Cl$$
    Option B is correct.
  • Question 10
    1 / -0
    Action of diazomethane on phenol liberates
    Solution
    Option C is correct.

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