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Biomolecules Test - 47

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Biomolecules Test - 47
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  • Question 1
    1 / -0
    Which of the following carbohydrates develop blue colour on treatment with iodine solution?
    Solution
    Starch develops blue colour on treatment with iodine solution due to the formation of the starch-iodine complex. Iodine (in the form of $${ I }_5^-$$ ions) gets stuck in the coils of beta amylose molecules (beta amylose is a soluble starch). 

    The starch forces the iodine atoms into a linear arrangement in the central groove of the amylose coil. There is some transfer of charge between the starch and the iodine that changes the way electrons are confined and so, changes the spacing of the energy levels. 

    The iodine-starch complex has energy level spacing that is suitable for absorbing visible light giving the complex its intense blue color. 
  • Question 2
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    Which one of the following is not an attribute of enzymes ? 
    Solution

  • Question 3
    1 / -0
    Which one of the following is not a pyrimidine base ? 
    Solution

  • Question 4
    1 / -0
    White prepipitate is formed in.
    Solution
    In Millon's test, first the compound (to be tested) i.e, protein is nitrated by $$HNO_3$$ and then complexed with $$Hg(I)$$ and $$Hg(II)$$ ions. A red precipitate is obtained. However, if the protein contains tyrosine, sometimes initially a white precipitate is formed that turns red on heating.
  • Question 5
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    ______________ are found in nitrates, phosphates of metals.
    Solution
    Because these are found in the earth's crust and all the metal salts which are found in earth's crust are called inorganic salts
  • Question 6
    1 / -0
    The chemical name of vitamin $${B}_{12}$$ is:
    Solution
    The chemical name of vitamin $$B_12$$ is cyanocobalamine and it contains cobalt.
  • Question 7
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    Identify disaccharides among the following:

    (a) Stachyose            (b) Lactose
    (c) Maltose               (d) Raffinose
    Solution
    Stachyose: Tetrasaccharide consisting of two galactose units, one-glucose unit, and one fructose unit.

    Lactose: Disaccharide sugar derived from galactose and glucose.

    Maltose: Disaccharide formed from two units of glucose.   

    Raffinose: Trisaccharide composed of galactose, glucose, and fructose.

    Hence, option D is correct.
  • Question 8
    1 / -0
    An apoenzyme is a
    Solution
    Correct Option: A
    Explanation:

    • An apoenzyme is a protein that forms an inactive enzyme.
    • The inactive part of the enzyme is called the the apoenzyme. 
    • Upon binding with the cofactor or the prosthetic group, which may be organic or inorganic it becomes active. 
    • The apoenzyme with the cofactor or prosthetic group forms the holoenzyme.
    • Hence, the apoenzyme is a protein.
  • Question 9
    1 / -0
    Sucrose on hydrolysis gives:
    Solution
    Sucrose gives glucose and fructose on hydrolysis with invertase enzyme.
    $$\underset { sucrose }{ { C }_{ 12 }{ H }_{ 22 }{ O }_{ 11 } } +{ H }_{ 2 }O\xrightarrow [  ]{ Invertase } \underset { glucose }{ { C }_{ 6 }{ H }_{ 12 }{ O }_{ 6 } } +\underset { fructose }{ { C }_{ 6 }{ H }_{ 12 }{ O }_{ 6 } } $$
  • Question 10
    1 / -0
    The enzymes are destroyed by
    Solution
    When the protein in the enzyme denatures then its function are lost. Some enzymes extracted from bacterias can sustain a temperature upto 70° c . Enzymes in human body can work to an optimum temperature of 42°c after that they get denatured.
    So, option B is correct. 
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