Polymers Test

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Polymers Test - 11

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Weekly Quiz Competition

Question 1
1 / -0

Which one of the following sets forms the biodegradable polymer?

A
$${H}_{2}N-{CH}_{2}-COOH$$ and $${H}_{2}N-{({CH}_{2})}_{5}-COOH$$

B
$$HO-{CH}_{2}-{CH}_{2}-OH$$ and $$COOH-C_6H_4-COOH$$

C
$$C_6H_5-CH=CH_2 $$ and $${CH}_{2}=CH-CH={CH}_{2}$$

D
$${CH}_{2}=CH-CN$$ and $${CH}_{2}=CH-CH={CH}_{2}$$

Solution

The condensation polymerization of $${H}_{2}N-{CH}_{2}-COOH$$ and $${H}_{2}N-{({CH}_{2})}_{5}-COOH$$ forms Nylon-2-Nylon-6 which is a bio-degradable polymer. It can be degraded by microorganisms like bacteria fungi, etc. which are present in the environment. It is non-toxic and non-polluting.

In options B, C and D, the condensation polymerisation of monomers results in the formation of non-biodegradable polymers.

Hence, option A is correct.
Question 2
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Natural rubber has:

A
all cis-configuration

B
all trans-configuration

C
alternate cis- and trans-configuration

D
random cis-and trans-configuration
Question 3
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Isoprene is:

A
$$3$$-methyl-$$1, 2$$-butadiene

B
$$2$$-methyl-$$1, 3$$-butadiene

C
$$3$$-chloro-$$1, 2$$-butadiene

D
$$2$$-chloro-$$1, 3$$-butadiene

Solution

$$H_2C=\underset{\underset {\displaystyle {\,\,\,\,CH_3}} |}{C}-CH=CH_2$$

Isoprene is a monomer of natural rubber. Its formula is $$2$$-methyl-$$1,3$$-butadiene.
Question 4
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Which one of the following structures represents the neoprene polymer?

A
$$[\!\!\!-\underset{C_6H_5}{\underset{|}{C}H} - CH_2-\!\!\!]_n$$

B
$$(\!\!\!\!-CH_2-CH = \underset{Cl}{\underset{|}{C}} - CH_2-\!\!\!\!)_n$$

C

D

Solution

Neoprene is a polymer of chloroprene which is chemically 2- chlorobuta - 1, 3 -diene (isoprene). Neoprene exhibits good chemical stability and maintains flexibility over a wide temperature range.

Option B is correct.
Question 5
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Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation.
I. $$CH_2=CH-C_6H_4(NO_2)$$
II.$$CH_2=CH-C_6H_4(CH_3)$$
III.$$CH_2=CH-C_6H_4(OCH_3)$$

A
$$I > II > III$$

B
$$II > I > II$$

C
$$III > II > I$$

D
$$I > III > II$$

Solution

Electron releasing groups such as $$-CH_3, -OCH_3$$ activate the monomer towards cationic polymer as it stabilizes the carbocation formed. On the other hand, $$-NO_2$$ is an electron-withdrawing group. So, it reduces the stability of carbocation formed.

Thus, the correct order is:

$$CH_2=CH-C_6H_4(OCH_3) > CH_2=CH-C_6H_4(CH_3) >CH_2=CH-C_6H_4(NO_2)$$.
Question 6
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In vulcanisation of rubber,

A
sulphur reacts to form new compound

B
sulphur cross links are introduced

C
sulphur forms a very thin protective layer over rubber

D
All of the above.

Solution

In vulcanisation of rubber, sulphur cross links are introduced. Natural rubber is mixed with 3 to 5% sulphur and heated at $$100- 150^oC$$ to form cross linking of cis-1,4 polyisoprene chains through disulphide bonds (-S-S-) . Vulcanization of rubber makes it more strong, tough and elastic.
Question 7
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Polymer used in bullet proof glass is:

A
lexan

B
PMMA

C
nomex

D
kevlar

Solution

Lexan is a kind of polycarbonate i.e. thermosetting polymers containing carbonate groups. They are strong, tough materials, and are optically transparent. This is why a laminated polycarbonate (Lexan) is used to make bulletproof glass.
Question 8
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A synthetic rubber which is resistant to the action of oils, gasoline and other solvents is:

A
buna-S

B
polyisoprene

C
neoprene

D
polystyrene

Solution

Neoprene is synthetic rubber. It is a polymer of chloroprene and is resistant to the action of oils, gasoline and other solvents.
$$nCH_2=\underset{Cl}{\underset{|}{C}}-CH=CH_2\xrightarrow {polymerization}\, [\!\!\!-CH_2-\overset{Cl}{\overset{|}{C}}=CH-CH_2-\!\!\!]_n$$
$$\text{chloroprene}$$ $$\text{neoprene or synthetic rubber}$$

Option C is correct.
Question 9
1 / -0

Dicarboxylic acids react with diols to form which type of co-polymer?

A
Random

B
Alternating

C
Block

D
Graft

Solution

Dicarboxylic acids react with diols to form alternating type of co-polymer. They form polyesters such as glyptal, daozon. They are alternating co-polymer because there is alternative one carboxylic acid and one alcoholic unit.
Question 10
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Polymerisation in which two or more chemically different monomers take part is called:

A
addition polymerisation

B
copolymerisation

C
chain polymerisation

D
homopolymerisation

Solution

Copolymerisation is a polymerization reaction in which a mixture of more than one monomeric species is allowed to polymerize to form a copolymer.

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Polymers Test - 11

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Polymers Test - 11

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Question 1

$${H}_{2}N-{CH}_{2}-COOH$$ and $${H}_{2}N-{({CH}_{2})}_{5}-COOH$$

$$HO-{CH}_{2}-{CH}_{2}-OH$$ and $$COOH-C_6H_4-COOH$$

$$C_6H_5-CH=CH_2 $$ and $${CH}_{2}=CH-CH={CH}_{2}$$

$${CH}_{2}=CH-CN$$ and $${CH}_{2}=CH-CH={CH}_{2}$$

Solution

Question 2

all cis-configuration

all trans-configuration

alternate cis- and trans-configuration

random cis-and trans-configuration

Question 3

$$3$$-methyl-$$1, 2$$-butadiene

$$2$$-methyl-$$1, 3$$-butadiene

$$3$$-chloro-$$1, 2$$-butadiene

$$2$$-chloro-$$1, 3$$-butadiene

Solution

Question 4

$$[\!\!\!-\underset{C_6H_5}{\underset{|}{C}H} - CH_2-\!\!\!]_n$$

$$(\!\!\!\!-CH_2-CH = \underset{Cl}{\underset{|}{C}} - CH_2-\!\!\!\!)_n$$

Solution

Question 5

$$I > II > III$$

$$II > I > II$$

$$III > II > I$$

$$I > III > II$$

Solution

Question 6

sulphur reacts to form new compound

sulphur cross links are introduced

sulphur forms a very thin protective layer over rubber

All of the above.

Solution

Question 7

lexan

PMMA

nomex

kevlar

Solution

Question 8

buna-S

polyisoprene

neoprene

polystyrene

Solution

Question 9

Random

Alternating

Block

Graft

Solution

Question 10

addition polymerisation

copolymerisation

chain polymerisation

homopolymerisation

Solution

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