Solutions Test

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Solutions Test - 1

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Weekly Quiz Competition

Question 1
1 / -0

Example of solution of liquid in gas is

A
mercury in gold

B
alcohol in water

C
moist air

D
Dry air

Solution

Explanation:

Solute is water (liquid) and solvent is gas( air).
Question 2
1 / -0

Molality of a solution relates the

A
Moles of solution and mass of solution

B
moles of solute and mass of solvent

C
Volume of solution and moles of solute

D
volume of solute and volume of solvent

Solution

Explanation:

Molality is number of moles of solute dissolved in per Kg of solvent.
Question 3
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Which law shows relation between pressure and solubility of a gas in solvent

A
Le chaterliers principle

B
Rate law

C
Raoult’s law

D
Henry’s law

Solution

Explanation:

Henry’s Law states that as the partial pressure of gas increases over liquid solubility of gas also increases.
Question 4
1 / -0

For ideal solution the enthalpy of mixing of the pure components to form the solution is

A
none of these

B
△ H_mix = 0

C
△ H_mix= +ve

D
△ H_mix= −ve

Solution

Explanation:

For ideal solution there is no evolution or absorption of heat on mixing.
Question 5
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For ideal solution the volume of mixing of the pure components to form the solution is

A
△ V_mix= −ve

B
△ V_mix= +ve

C
△ V_mix= 0

D
none of these

Solution

Explanation:

For ideal solution there is no increase or decrease in volume on mixing.
Question 6
1 / -0

Raoult’s law states that for a solution of volatile liquids the partial pressure of each component in the solution is

A
Inversely proportional to the mole fraction

B
Directly proportional to the mole fraction

C
Directly proportional to the volume

D
Directly proportional to the temperature

Solution

Explanation:

Raoult’s law states that for a solution of volatile liquids the partial pressure of each component in the solution is directly proportional to mole fraction of component.
Question 7
1 / -0

Minimum boiling azeotrope is form by the solution which show

A
Large positive deviation from Raoult’s law

B
Large negative deviation from Raoult’s law

C
Positive deviation from Raoult’s law

D
Negative deviation from Raoult’s law

Solution

Explanation:

Positively deviated non ideal solution forms Minimum boiling Point azeotropes.
Question 8
1 / -0

Which of the following is a colligative property?

A
Heat of vapourization

B
Osmotic pressure

C
Dipole moment

D
Change in free energy

Solution

Explanation:

Colligative property is dependent on no. of moles of solute. (Л=cRT)
Question 9
1 / -0

Cryoscopic constant of a liquid is

A
A factor used for calculation of elevation in boiling point

B
Decrease in freezing point when 1 mole of solute is dissolved per Kg of the solvent

C
Decrease in freezing point when 1 g of solute is dissolved per kg of the solvent

D
The elevation for 1 molar solution

Solution

Explanation:

ΔT_f= K_fm. When m(molality )= 1m then k_f= ΔT_f

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Solutions Test - 1

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Solutions Test - 1

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Question 1

mercury in gold

alcohol in water

moist air

Dry air

Solution

Question 2

Moles of solution and mass of solution

moles of solute and mass of solvent

Volume of solution and moles of solute

volume of solute and volume of solvent

Solution

Question 3

Le chaterliers principle

Rate law

Raoult’s law

Henry’s law

Solution

Question 4

none of these

△ Hmix = 0

△ Hmix = +ve

△ Hmix = −ve

Solution

Question 5

△ Vmix = −ve

△ Vmix = +ve

△ Vmix = 0

none of these

Solution

Question 6

Inversely proportional to the mole fraction

Directly proportional to the mole fraction

Directly proportional to the volume

Directly proportional to the temperature

Solution

Question 7

Large positive deviation from Raoult’s law

Large negative deviation from Raoult’s law

Positive deviation from Raoult’s law

Negative deviation from Raoult’s law

Solution

Question 8

Heat of vapourization

Osmotic pressure

Dipole moment

Change in free energy

Solution

Question 9

A factor used for calculation of elevation in boiling point

Decrease in freezing point when 1 mole of solute is dissolved per Kg of the solvent

Decrease in freezing point when 1 g of solute is dissolved per kg of the solvent

The elevation for 1 molar solution

Solution

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△ H_mix = 0

△ H_mix= +ve

△ H_mix= −ve

△ V_mix= −ve

△ V_mix= +ve

△ V_mix= 0