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Solutions Test 24

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Solutions Test 24
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  • Question 1
    1 / -0
    A spherical balloon of 21 cm21\ cm diameter is to be filled up with H2H_2 at NTPNTP from a cylinder containing the gas at 20 atm20\ atm at 27C27^{\circ}C. The cylinder can hold 2.822.82 litre of water. The number of balloons that can be filled up
    Solution

  • Question 2
    1 / -0
    The vapour pressure of a given liquid will decrease if:
  • Question 3
    1 / -0
    An aqueous solution containing liquid A(M. wt. =128) 64%A(M.\ wt.\ =128)\ 64\% by weight has a vapour pressure of 145 mm Hg145\ mm\ HgIf the vapour pressure of water is 155 mm Hg155\ mm\ Hg then vapour of AA at the same temperature will be
    Solution

  • Question 4
    1 / -0
    The solubility of a specific non-volatile salt is 4g in 100 g of water at 250{25}^{0}C. If 2.0g, 4.0g and 6.0g of the salt added of 100g of water at 250{25}^{0}C, in system X, Y and Z. The vapour pressure would be in the order:
    Solution

  • Question 5
    1 / -0
    The pressure exerted by a mass of x mg resting on the area of 1.00 cm2{ cm }^{ 2 } is 1.00 Pa, then x is
    Solution

  • Question 6
    1 / -0
    Reaction of NO{NO} takes place with hydrogen if equal molar mixture of snow and hydrogen is taken at initial total pressure of 350 mm of Mercury, total pressure reduces to half its value after 121 seconds while if initial total pressure would have been 275 mm it reduces to half of the 196 seconds calculate the order of reaction?
    Solution

  • Question 7
    1 / -0
    The vapour pressure of pure water at 25C25^{\circ}C is 30 mm30\ mm. The vapour pressure of 10% (W/W)10\%\ (W/W) glucose  solution at 25C25^{\circ}C is :
    Solution
    1010% solution 10g\Rightarrow 10g of glucose , 90g90g of water in 100gm100gm of solution

    So, number of moles of water in 90gm90gm=9018=5 \cfrac {90}{18}= 5 moles

    Number of moles of glucose= 10180=0.056\cfrac {10}{180}=0.056 moles

    So, total moles= 5+0.056=5.0565+0.056=5.056 moles

    Mole fraction of water= 5/5.056=0.9885/5.056=0.988

    So, final vapour pressure= P×Xwater=30×0.980=29.6 mmP\times X_{water}=30\times 0.980=29.6\ mm

    Hence, the correct option is CC
  • Question 8
    1 / -0
    Relative decrease in vapour of an aqueous NaCl{\text{NaCl}} is 0.1670.167. Number of moles of NaCl{\text{NaCl}} present in 180 g180\ g of H2O{{\text{H}}_{\text{2}}}{\text{O}} is:
  • Question 9
    1 / -0
    The vapour pressure of pure benzene at a certain temperature is 200 mm Hg. At the same temperature the vapour pressure of a solution containing 2 g of non volatile non electrolyte solid in 78 g of benzene is 195 mm Hg. What is the molecular mass of solid?
    Solution

  • Question 10
    1 / -0
    Calculate vapour pressure of solution obtained by mixing 0.1 mol of K4[Fe(CN)6]K_4[Fe(CN)_6] to 360 gm of water at 270C{27}^0C. [Given: Vapour pressure of pure water at 27C is 25 torr.]
    Solution

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