Electrochemistry Test

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Electrochemistry Test - 10

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Weekly Quiz Competition

Question 1
1 / -0

The standard electrode potential is measured by

A
Voltmeter

B
Electrometer

C
Pyrometer

D
Galvanometer

Solution

Voltmeter measures the potential. EMF of the cell is measured either by a calibrated potentiometer or by a high resistance voltmeter.
Question 2
1 / -0

When KMnO₄ acts as an oxidizing agent and ultimately forms,MnO²₄⁻MnO₂, Mn₂O₃ and Mn²⁺, then the number of electrons transferred in each case

A
3, 5, 7, 1

B
1, 3, 4, 5

C
4, 3, 1, 5

D
1, 5, 3, 7

Solution

No. of electrons = change in oxidation number of active element.
Question 3
1 / -0

Which of the following is a redox reaction?

A
CaC₂O₄+ 2HCl → CaCl₂+ H₂C₂O₄

B
Zn + 2AgCN → 2Ag + Zn (CN)₂

C
Mg(OH)₂+ 2NH₄Cl → MgCl2 + 2NH₄OH

D
NaCl + KNO₃→ NaNO₃+ KCl

Solution

In redox both oxidation and reduction take place simultaneously.

zinc is oxidised and silver is reduced.
Question 4
1 / -0

When a reversible work is done by a galvanic cell, the relationship between gibbs free energy and emf of the cell is given by the relationship as

A
Δ_rG = − 3FE_(cell)

B
Δ_rG = − nFE_(cell)

C
Δ_rG = FE_(cell)

D
Δ_rG = − 2FE_(cell)

Solution

When galvanic cell operates, work is done on the surroundings, as electrical energy flows through external circuit. such work by convention is taken as negative. so Δ_rG = − nFE_(cell)

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Re-Attempt Weekly Quiz Competition

Electrochemistry Test - 10

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Electrochemistry Test - 10

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Question 1

Voltmeter

Electrometer

Pyrometer

Galvanometer

Solution

Question 2

3, 5, 7, 1

1, 3, 4, 5

4, 3, 1, 5

1, 5, 3, 7

Solution

Question 3

CaC2O4 + 2HCl → CaCl2 + H2C2O4

Zn + 2AgCN → 2Ag + Zn (CN)2

Mg(OH)2 + 2NH4Cl → MgCl2 + 2NH4OH

NaCl + KNO3 → NaNO3 + KCl

Solution

Question 4

ΔrG = − 3FE(cell)

ΔrG = − nFE(cell)

ΔrG = FE(cell)

ΔrG = − 2FE(cell)

Solution

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CaC₂O₄+ 2HCl → CaCl₂+ H₂C₂O₄

Zn + 2AgCN → 2Ag + Zn (CN)₂

Mg(OH)₂+ 2NH₄Cl → MgCl2 + 2NH₄OH

NaCl + KNO₃→ NaNO₃+ KCl

Δ_rG = − 3FE_(cell)

Δ_rG = − nFE_(cell)

Δ_rG = FE_(cell)

Δ_rG = − 2FE_(cell)