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Electrochemistry Test - 67

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Electrochemistry Test - 67
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  • Question 1
    1 / -0
    Find the potential of a half-cell having reaction, $$Ag_{2}S+2e\rightarrow2Ag+S^{2-}$$ in a solution buffered
    $$pH=3$$ and which is also saturated with $$0.1\ M\ H_{2}S$$. For $$H_{2}S:\ K_{1}=10^{-8}$$ and $$K_{2}=2\times 10^{-13},\ K_{sp}(Ag_{2}S)=2\times 10^{-48},\ E_{Ag,ag}^{o}=0.8$$
    Solution

  • Question 2
    1 / -0
    Which of the following represent first law of Faraday?
    Solution

  • Question 3
    1 / -0
    In $$Zn|Zn^{+2}|| Ag^+|Ag$$, how will cell potential be affected if KI is added to $$Ag^{+}$$ half cell?
  • Question 4
    1 / -0
    A : Electrochemical cell is based on redox reaction.
    R : Electrochemical cell converts electrical energy into chemical energy.
  • Question 5
    1 / -0
    Which of the following substance has the lowest electric resistivity at room temperature?
  • Question 6
    1 / -0
    The no. of electrons involved in the electro deposition of 63.5 g. of Cu from aq. $$ CuSO_4 $$ is :
    Solution

  • Question 7
    1 / -0
    In the electrolysis of aqueous $$NaCl$$, what volume of $$Cl_2(g)$$ is produced in the time that it takes to liberate $$5.0$$ liter of $$H_2(g) ?$$ Assume that both gases are measured at STP.
    Solution

  • Question 8
    1 / -0
    How many faradays of charge is transferred to produce 11.2 L of $$H_2$$ at STP in the reaction, in the reaction, $$ NaH +H_2O \rightarrow NaOH +H_ 2 \uparrow $$ ?
    Solution

  • Question 9
    1 / -0
    2 ml ethanoic acid was taken in test tubes - A, B and C. 2 ml, 4 ml and 8 ml of water was added to the test tubes A, B and C respectively. Which test tube will show clear solution?
  • Question 10
    1 / -0
    Deduce from the following $${E^ \circ }$$ value of half cells, What combination of half cells would result in cell with the largest potential? 
    i) $${A^{3 - }} \to {A^2} + {e^ - };{\rm{ }}{{\rm{E}}^ \circ } = 1.5V$$
    ii) $${B^{2 + }} + {e^ - } \to {B^ + };{\rm{ }}{{\rm{E}}^ \circ } =  - 2.1V$$
    iii) $${C^{2 + }} + {e^ - } \to  + {C^ + };{\rm{ }}{{\rm{E}}^ \circ } =  + 0.5V$$
    iv) $$D \to {D^{2 + }} + 2{e^ - };{\rm{ }}{{\rm{E}}^ \circ } =  - 1.5V$$
    Solution

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