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Chemical Kinetics Test - 71

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Chemical Kinetics Test - 71
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  • Question 1
    1 / -0
    A reaction  $$P \rightarrow Q$$  is  $$25\%$$  complete in  $$25 min,$$   $$50\%$$  complete in  $$25 min$$  if  $$[ P ]$$  is halved. The reaction is  $$25 \%$$  completed in   $$50 min$$  if  $$[ P ]$$  is doubled. The order of reaction is
    Solution

  • Question 2
    1 / -0
    Reaction $$A\rightarrow B$$ follows second order kinetics. Doubling the concentration of A will increase the rate of formation of B by a factor of:
  • Question 3
    1 / -0
    Consider the following first order competing reaction :
    $$X\xrightarrow{{{K_1}}}A + B$$ and $$Y\xrightarrow{{{K_2}}}C + D$$ 
    if $$50\% $$ of the reaction of $$X$$ was completed when $$96\% $$ of the reaction of $$Y$$ was completed , the ratio of their rate constant $$\left( {{K_2}/{K_1}} \right)$$ is:
    Solution

  • Question 4
    1 / -0
    For a first-order reaction, the plot of 't' against $$log \ C$$ gives a straight line with a slope equal to:
  • Question 5
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    The initial concentration of $$N_2O_5$$ in the following first order reaction  $$N_2O_{5(g)} \rightarrow 2NO_2(g) + \dfrac{1}{2} O_2 (g)$$ was $$1.24 \times 10^{-2} \ molL^{-1}$$ at 318 K. The concentration of $$N_2O_5$$ after 60 min was $$0.20 \times 10^{-2} \ molL^{-1}$$. Calculate the rate constant of the reaction at 318 K.
    Solution

  • Question 6
    1 / -0
    The curves $$M$$ and $$N$$ represent the variation of energy with reaction coordinates for the reaction $$A(g)+B(g) \rightleftharpoons  C(g)+D(g)$$ in absence and presence of negative catalyst
    Of the curves $$M$$ and $$N$$, which represents the $$E_{a}$$ for the backward reaction in the presence of catalyst 

  • Question 7
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    For a zero order reaction:
    Solution

  • Question 8
    1 / -0
    A graph of $$log_{10}k$$ is plotted against $$1/T$$ for a reaction with order 2.5. If the activation energy is 10 kJ/mol, then magnitude of the slope will be: 
  • Question 9
    1 / -0
    In a first order reaction, $$0.16$$ moles of reactant decrease to $$0.02$$ moles in $$144$$ minutes, its half life is ?
    Solution

  • Question 10
    1 / -0
    The time required for 75% completion of a first reaction is 9 hr. The half-life period of the reaction is:
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