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Chemical Kinetics Test - 82

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Chemical Kinetics Test - 82
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Weekly Quiz Competition
  • Question 1
    1 / -0
    If the order of the reaction $$x+y\xrightarrow[]{hv}xy$$ is zero, it means that the rate of ____
    Solution
    In photochemical reactions the rate of reaction is independent of the concentration of reacting species.
  • Question 2
    1 / -0
    Which the following statements is true for a first order reaction?
    Solution

  • Question 3
    1 / -0
    Fill in the blanks by choosing the correct option:

    Order of the reaction is the $$ \underline {X}  $$ of the powers to which concentration terms are raised in experimentally determined rate equation. The unit of first order rate constant is $$  \underline {Y} $$. The units of first order rate constant when concentration is measured in terms of pressure and time in minute is $$ \underline {Z} $$
    Solution

  • Question 4
    1 / -0
    Cyclopropane rearranges to form propene
    $$ \Delta \rightarrow CH_3 -CH =CH_2 $$
    this follows first order kinetics. the rate constant is $$ 2.714 \times 10^{-3} sec^{-1} $$the initial concentration of cyclopropane is $$ 0.29 M $$what will be concentration  of cyclopropane after 100 sec ?
    Solution
    $$ k = \dfrac { 2.303}{t} log  \dfrac {a}{(a-x) } $$

    $$ (a-x) $$ is the concentration left after $$ 100 sec $$

    $$ 2.7 \times 10^{-3} = \dfrac { 2.303}{ 100} log  \dfrac { 0.29}{ (a-x) } $$

    $$ \Rightarrow  \dfrac { 0.27}{ 2.303} = log  \dfrac { 0.29}{ (a-x) } \Rightarrow  0.117 = log  \dfrac { 0.29}{ (a-x)  } $$

    $$ \Rightarrow  (a-x)  = 0.22 M $$
  • Question 5
    1 / -0
    the half - life of the reaction $$ X \rightarrow Y $$ following first  order kinetics , when the initial concentration of X is $$ 0.01 mol L^{-1} $$ and initial rate is $$ 0.00352 mol L^{-1} min^{-1} $$ will be 
    Solution
    $$ \dfrac {dx}{dt} = k[X] $$ 

    $$ 0.00352 = k \times 0.01 \Rightarrow  k = 0.352 $$

    $$ t_{1/2} = \dfrac  { 0.693}{k} = \frac { 0.693}{ 0.352} = 1.969 min $$

    Option B is correct.
  • Question 6
    1 / -0
    the rate constant for a first order reaction is $$ 2 \times 10^{-2} min^{-1} $$ the half -life period of reaction is 
    Solution
    $$Given:k=2\times10^{-2}min^{-1}$$

    $$ t_{1/2} = \dfrac { 0.693}{k} = \dfrac { 0.693}{ 2 \times 10^{-2} } = 34.64 min $$

    Option B is correct.
  • Question 7
    1 / -0
    Rate constant in case of first order reaction is 
    Solution
    Option B is correct.

  • Question 8
    1 / -0
    Which of the following is incorrect statement ?
    Solution
    Elementary reactions that occur are unimolecualar and biomolecular ones,
    where unimolecular may include bond dissociation or cis - trans transetion Biomolecular reactions strictly involve two species In comparison, zero order
    reactions are complex in nature. (e $$\mathrm{g}$$. involving an engyme in $$\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$$
    decomposition) 
    Thus option $$D$$ is incorrect statement.
  • Question 9
    1 / -0
    The activation energy of the reaction, $$A + B \rightarrow C + D + 38kcal$$ is $$20$$ kcal, What would be the activation energy of the reaction,
    $$C + D \rightarrow A + B$$
  • Question 10
    1 / -0
    In a certain first-order reaction, $$B^{n+}$$ is getting converted to $$B^{(n+4)+}$$  in solution. The rate constant of this reaction is measured by titrating a volume of the solution with a reducing agent which reacts only with $$B^{n+}$$ and $$B^{(n+4)+}$$. In the process, it converts  to $$B^{n+}$$ to $$B^{(n-2)+}$$ and $$B^{(n+4)+}$$ to $$B^{(n-1)+}$$,At $$t=0$$ the volume of reagent consumed is 55 ml and at $$t = 20$$ min, the volume used is 70.5 ml. The rate constant for the conversion of $$B^{n+}$$ of $$B^{(n+4)+}$$ (ln 2 = 0.7, ln 5 = 1.6) 
    Solution

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