The p-Block Elements Test

Result

The p-Block Elements Test - 49

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Equal masses of $$S_2, S_4$$ and $$S_8$$ are taken. Highest number of free species are present in:

A
$$S_2$$

B
$$S_4$$

C
$$S_8$$

D
all have same number of molecule

Solution

The order of molecular weights will be
$${ S }_{ 2 }<{ S }_{ 4 }<{ S }_{ 8 }$$.
So, if the the equal masses are taken, then highest number of molecules will be in $${ S }_{ 2 }$$.
So, correct answer is option A.
Question 2
1 / -0

The nitride salt of $$Ca$$ when treated with $$H_{2}O$$ gives:

A
$$N_{2}$$

B
$$CaO$$

C
$$CaH_{2}$$

D
$$NH_{3}$$

Solution

When calcium nitride reacts with di nitrogen it forms ammonia and calcium hydroxide.
$$Ca_3N_2 + 6 H_2O\rightarrow 3 Ca(OH)_2 + 2 NH_3$$.
Question 3
1 / -0

Which property is most important in making fluorine, the strongest oxidising halogen?

A
Hydration enthalpy

B
Bond dissociation energy

C
Ionisation enthalpy

D
Electron gain enthalpy

Solution

$$\displaystyle\frac{1}{2}F_2+e^-+aq. \rightarrow F^-(aq),$$

$$\Delta

H=\underset{(+ve)}{H_{Gibbs}}+\underset{Hydrogen

\ enthalpy}{\underset{(-ve)}{H_{Elec.

gain}}+\underset{(-ve)}{H_{hyd}}}=-ve$$

Since the heat of hydration for fluorine is very high and $$-$$ve. (due to small size)

The overall reaction is highly exothermic and therefore fluorine shows strongest oxidizing nature.

Hence, option $$A$$ is correct.
Question 4
1 / -0

Which of the following is not a peroxy acid?

A
Perphosphoric acid

B
Pernitric acid

C
Perdisulphuric acid

D
Perchloric acid

Solution

Perchloric acid is not a peroxy acid while other given acids are examples of peroxy acids.

A peroxy acid is an acid that contains an acidic –OOH group or peroxo linkage (−O−O− linkage).

Option D is correct.
Question 5
1 / -0

Helium is used in balloons in place of hydrogen because it is:

A
Incombustible

B
Lighter than hydrogen

C
Radioactive

D
More abundant than hydrogen

Solution

Helium is used in balloons in place of hydrogen because it is incombustible. $$He$$ do not catch fire like hydrogen. $$He$$ is a inert element. Hence, option A is correct.
Question 6
1 / -0

The catalyst used in the manufacture of nitric acid by Ostwald's process is:

A
$$V_2O_5$$

B
$$Pt$$

C
$$Mo$$

D
$$Fe$$

Solution
Question 7
1 / -0

An element is oxidised by fluorine and not by chlorine. Identify the element.

A
Sodium

B
Aluminium

C
Oxygen

D
Sulphur

Solution

$$\begin{array}{l}\text{ Flourine is more Electronegative element than Oxygen and Oxygen is more Electronegative }\\\text{ than Chlorine. }\\\text{ Hence, Flourine can oxidise Oxygen whereas Chlorine reduced Oxygen. }\\\text{ Hence option }(C)\text{ is correct. }\end{array}$$
Question 8
1 / -0

In the Haber process of synthesis of $$NH_3$$, which of the following statement is correct?

A
$$Mo$$ acts as a catalyst and $$Fe$$ as a promoter

B
$$Fe$$ acts as a catalyst and $$Mo$$ as a promoter

C
$$Fe$$ acts as inhibitor and $$Mo$$ as a catalyst

D
$$Fe$$ acts as promoter and $$Mo$$ as autocatalyst

Solution

Preparation of Ammonia:
$$N_2 + 3H_2\rightarrow 2NH_3$$
At high pressure about 200-250 atm, and a moderate temperature of $$750K$$, the reaction takes place. Removal of ammonia is done by liquefaction, In the process, iron is used as a catalyst and molybdenum as a promoter.
Question 9
1 / -0

When plants and animals decay, the organic nitrogen is converted into inorganic nitrogen. The inorganic nitrogen is in the form of:

A
ammonia

B
elements of nitrogen

C
nitrates

D
nitrides

Solution

When plants and animals decay, the organic nitrogen is converted into inorganic nitrogen. The inorganic nitrogen is in the form of ammonia $$\displaystyle NH_3$$.
Question 10
1 / -0

Which one of the following statements is incorrect?

A
All halogens have weaker X-X bond than X- X' bond, in interhalogens (except F-F bond in fluorine)

B
Radius ratio between iodine and fluorine (among halogens) is maximum

C
Interhalogen compounds are more reactive than halogen compounds

D
Among interhalogen compounds, maximum number of atoms are present in iodine fluoride

Solution

All interhalogens have weaker $$X-X'$$ bonds and not $$X-X$$ bonds but F is an exception due to high electronegativity and small size.

Hence, option (A) is incorrect.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 49

Result

The p-Block Elements Test - 49

Score

-

Rank

-

SHARING IS CARING

Question 1

$$S_2$$

$$S_4$$

$$S_8$$

all have same number of molecule

Solution

Question 2

$$N_{2}$$

$$CaO$$

$$CaH_{2}$$

$$NH_{3}$$

Solution

Question 3

Hydration enthalpy

Bond dissociation energy

Ionisation enthalpy

Electron gain enthalpy

Solution

Question 4

Perphosphoric acid

Pernitric acid

Perdisulphuric acid

Perchloric acid

Solution

Question 5

Incombustible

Lighter than hydrogen

Radioactive

More abundant than hydrogen

Solution

Question 6

$$V_2O_5$$

$$Pt$$

$$Mo$$

$$Fe$$

Solution

Question 7

Sodium

Aluminium

Oxygen

Sulphur

Solution

Question 8

$$Mo$$ acts as a catalyst and $$Fe$$ as a promoter

$$Fe$$ acts as a catalyst and $$Mo$$ as a promoter

$$Fe$$ acts as inhibitor and $$Mo$$ as a catalyst

$$Fe$$ acts as promoter and $$Mo$$ as autocatalyst

Solution

Question 9

ammonia

elements of nitrogen

nitrates

nitrides

Solution

Question 10

All halogens have weaker X-X bond than X- X' bond, in interhalogens (except F-F bond in fluorine)

Radius ratio between iodine and fluorine (among halogens) is maximum

Interhalogen compounds are more reactive than halogen compounds

Among interhalogen compounds, maximum number of atoms are present in iodine fluoride

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.