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The d- and f- Block Elements Test - 49

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The d- and f- Block Elements Test - 49
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Weekly Quiz Competition
  • Question 1
    1 / -0
    In the dichromate dianion:
    Solution
    Dichromate is a divalent inorganic anion obtained by removal of both protons from dichromic acid. It is a conjugate base of a hydrogen dichromate.
    The dichromate ion consists of two tetrahedral sharing oxygen at the common corner. The six terminal bonds have the same bond length due to resonance

    Hence, the correct option is B.

  • Question 2
    1 / -0
    The colour of zinc sulphide is:
    Solution
    Colour of zinc sulphide is white.
  • Question 3
    1 / -0
    The correct order of ionic radii of $$Ce, La, Pm$$ and $$Yb$$ in $$+3$$ oxidation state is:
    Solution
     Order of radii:
    $$Yb^{+3}< Pm^{+3} < Ce^{+3} < La^{+3}$$
    Lanthanide contraction is the greater-than-expected decrease in ionic radii of the elements in the lanthanide series from atomic number 57, lanthanum, to 71, lutetium.
    Due to Lanthanide contraction,Ionic radii decreases continously.
  • Question 4
    1 / -0
    Which of the following pairs of ions is colourless?
    Solution

  • Question 5
    1 / -0
    Which of the following is not an actinide?
    Solution
    Elements after lanthanum i.e. from $$Ce$$ (atomic number $$58$$) to $$Lu$$ (atomic number $$71$$) are all lanthanides. The atomic number of Terbium is $$65$$ and hence it is a lanthanide, not an actinide. 

    Hence, the correct answer is option D.
  • Question 6
    1 / -0
    Which of the following pairs of ions have same paramagnetic moment?
    Solution
    $$Cu^{2+}, Ti^{3+} $$ have the same number of unpaired electrons thus they will  have same paramagnetic moment.
  • Question 7
    1 / -0
    Among $$d-$$ block elements, the most abundant element belongs to the:
    Solution
    The most abundant transition metal is iron, which is fourth among all elements and second to aluminum in metals in abundance. Titanium, manganese, zirconium, vanadium, and chromium also have abundances in excess of 100 grams per 1000kg
  • Question 8
    1 / -0
    Which one of the following ion has a magnetic moment of $$5.93\ B.M$$ ?
    Solution

  • Question 9
    1 / -0
    Which has maximum paramagnetic character ?
    Solution
    $$Mn^{+2}$$ has $$d^5$$ configuration with 5 unpaired electrons. Hence, it has the highest paramagnetic character.
  • Question 10
    1 / -0

    Directions For Questions

    The coordination number of $$Ni^{2+}$$ is $$4.$$

    $$NiCl_{2} + KCN \longrightarrow A$$ (Cyano complex)

    $$NiCl_{2} + Conc.\ HCl\ (excess) \longrightarrow B$$ (Chloro complex)

    ...view full instructions

    Predict the magnetic nature of $$A$$ and $$B$$.
    Solution
    $$[Ni(CN)_4]^{2−}$$
    The oxidation number of $$Ni$$ is $$+2$$.
    Atomic number = 28
    $$Ni = [Ar]3d^84s^2$$
    $$Ni^{2+}=[Ar]3d^8$$
    There are no unpaired electrons, so the complex is diamagnetic.

    $$[NiCl_4]^{2−}$$
    The oxidation number of $$Ni$$ is $$+2$$.
    Atomic number = 28
    $$Ni = [Ar]3d^84s^2$$
    $$Ni^{2+}=[Ar]3d^8$$
    Chloride is a weak field ligand, no pairing.
    $$sp^3$$ hybridization (tetrahedral)
    There are two unpaired electrons, so the complex is paramagnetic.

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