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The d- and f- Block Elements Test - 5

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The d- and f- Block Elements Test - 5
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Mohr’s salt is a

    Solution

    Mohr Salt is FeSO4.(NH4)2.6H2O. It is obtained by a combination of two different salts which were crystallized in the same regular ionic lattice. It is formed by an equimolar mixture of ferrous sulphate and ammonium sulphate. Since two salts are involved, Mohr salt is a double salt.

  • Question 2
    1 / -0

    Which one of the following is an example of non – typical transition elements?

    Solution

    Zn, Cd and Hg are not considered as transition elements because they do not have incompletely filled d orbital in it's ground state or stable oxidation state.

  • Question 3
    1 / -0

    Zr and Hf have almost equal atomic and ionic radii because

    Solution

    As after lanthanum, electron filling take place in f-subshell. Electrons present in f-subshell didn't do good shielding due to which with the increasing atomic number or increasing effective nuclear charge size gets constricted and size of Hf and Zr becomes almost equal.

  • Question 4
    1 / -0

    What is the shape of Fe(CN)5 molecule?

    Solution

    Fe has 5 carbonyl ligands around it i.e. CN=5. It has trigonal bipyramidal geometry with dsp3 hybridisation.

  • Question 5
    1 / -0

    Which of the following compound is amphoteric?

    Solution

    Amphoteric substances are those which can act as either acids or bases. Cr(OH)3 in water produces either salts (chromates), if combined with alkaline hydroxides (strong bases) such as potassium or sodium chromates and it can produce chromium salts if combined with strong acids (HCl, HF, H2SOetc.) giving chromium sulfate, chloride, fluoride etc.

  • Question 6
    1 / -0

    Which of the following sulphides is soluble in aqua regia?

    Solution

    HgS is only soluble in aqua regia. Aqua regia is a mixture of concentrated HCl and concentrated HNOin ratio 3:1. The solubilization turns Hg in HgCl42-, a complex called chloromercurate which is stable in water.
    3HgS + 2NO3- + 12Cl- + 8H3O+ ⇔3HgCl42- + 2NO + 12H2O + 3S

  • Question 7
    1 / -0

    Silver is refined by cupellation process. The process removes the impurity of

    Solution

    Cupellation is a refining process in metallurgy, where ores or alloyed metals are treated under very high temperatures and have controlled operations to separate noble metals, like gold and silver, from base metals like lead, copper, zinc or bismuth, present in the ore. Cupellation removes the impurity of Pb from silver. The reaction is given as below:
    Ag(s) + 2Pb(s) + O2(g) → 2PbO(absorbed) + Ag(l)

  • Question 8
    1 / -0

    Mohr’s salt is a better volumetric agent then ferrous sulphate because

    Solution

    Mohr’s salt is a better volumetric agent than ferrous sulphate because it is less readily oxidised in the solid state. Also Mohr’s salt is more stable than FeSO4.

  • Question 9
    1 / -0

    Red hot steel rods on suddenly immersing in water become

    Solution

    Red hot steel rods on suddenly immersing in water become hard and brittle.

  • Question 10
    1 / -0

    Which of the following methods is based on distribution law?

    Solution

    The parkes process is for removing silver from lead. It is an example of liquid-liquid extraction.

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