The d- and f- Block Elements Test

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The d- and f- Block Elements Test - 55

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Weekly Quiz Competition

Question 1
1 / -0

Chloride of which of the following elements will be coloured:

A
Silver

B
Mercury

C
Zinc

D
Cobalt

Solution

Chloride of Co elements will be coloured due to presence of unpaired electron.
Question 2
1 / -0

In which of the following. tendency towards formation of coloured ions is maximum

A
s-block elements

B
d-block elements

C
p-block elements

D
f-block elements

Solution

Tendency towards formation of coloured ions is maximum is maximum in d-block elements.
Hence, Option "B" is the correct answer.
Question 3
1 / -0

Arrange $$ Ce^{3+} , La^{3+} ,Pm^{3+} $$ and $$ Yb^{3+} $$ in increasing order of their ionic radii

A
$$ Yb^{3+} < Pm^{3+} < Ce^{3+} < La^{3+} $$

B
$$ Ce^{3+} < Yb^{3+} < Pm^{3+} < La^{3+} $$

C
$$ Yb^{3+} < Pm^{3+} < La^{3+} < Ce^{3+} $$

D
$$ Pm^{3+} < La^{3+} < Ce^{3+} < Yb^{3+} $$

Solution

Due to Lanthanoid contraction order will be: $$ Yb^{3+} < Pm^{3+} < Ce^{3+} < La^{3+} .$$
Question 4
1 / -0

Transition metals show paramagnetism

A
due to characteristic configuration

B
high lattice energy

C
due to variable oxidation states

D
due to unpaired electrons

Solution

Paramagnetic character is actually due to the presence of unpaired electrons. Transition metals show paramagnetism due to one or more number of unpaired electrons.
Question 5
1 / -0

Among the following which exhibits hydrogen, covalent, and coordinate bonding?

A
$$ MnSO_4 . 4H_2 O $$

B
$$ CuSO_4 . 5H_2 O $$

C
$$ FeSO_4 . 6H_2 O $$

D
$$ FeSO_4. 5H_2 O $$

Solution

$$CuSO_4$$ exhibit coordinate, covalent and hydrogen bonding.
Hence, Option "B" is the correct answer.
Question 6
1 / -0

Which of the following pair of elements cannot form an alloy ?

A
$$ Zn - Hg$$

B
$$ Fe - Hg $$

C
$$ Hg - Cr $$

D
$$ Na - Hg $$

Solution

Hg forms alloys with all metals except Iron, Platinum and Tungsten.
Hence, Option "B" is the correct answer.
Question 7
1 / -0

Iron loses magnetic property at

A
Melting point

B
1000K

C
Curie point

D
Boiling point

Solution

Iron loses magnetic property at Curie point. The temperature at which a certain material loses its permanent magnetic properties is known as the Curie temperature.
Question 8
1 / -0

The term platforming is

A
Platinum painting

B
Flat sheet of platinum

C
Platinum manufacturing

D
Platinum used as a catalyst

Solution

The term platforming is referred to use of Platinum as a catalyst in petrochemical plant.
Question 9
1 / -0

If $$CdI_2$$ is pink in colour, the $$CdCl_2$$ will be '________' coloured.

A
yellow

B
red

C
blue

D
cannot be predicted

Solution

In $$CdI_2$$ Pink colour is due to polarization of $$I^-$$ by $$Cd^{2+}$$ has pseudonoble gas configuration. In $$CdCl_2$$, extent of polarization of $$Cl^-$$ by $$Cd^{2+}$$ is relatively less, hence specific colour cannot be predicted.
Question 10
1 / -0

Which metal absorbs hydrogen?

A
$$Al$$

B
$$Fe$$

C
$$Pd$$

D
$$K$$

Solution

Palladium is a unique material with a strong affinity to hydrogen owing to both its catalytic and hydrogen absorbing properties.

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Re-Attempt Weekly Quiz Competition

The d- and f- Block Elements Test - 55

Result

The d- and f- Block Elements Test - 55

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Rank

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SHARING IS CARING

Question 1

Silver

Mercury

Zinc

Cobalt

Solution

Question 2

s-block elements

d-block elements

p-block elements

f-block elements

Solution

Question 3

$$ Yb^{3+} < Pm^{3+} < Ce^{3+} < La^{3+} $$

$$ Ce^{3+} < Yb^{3+} < Pm^{3+} < La^{3+} $$

$$ Yb^{3+} < Pm^{3+} < La^{3+} < Ce^{3+} $$

$$ Pm^{3+} < La^{3+} < Ce^{3+} < Yb^{3+} $$

Solution

Question 4

due to characteristic configuration

high lattice energy

due to variable oxidation states

due to unpaired electrons

Solution

Question 5

$$ MnSO_4 . 4H_2 O $$

$$ CuSO_4 . 5H_2 O $$

$$ FeSO_4 . 6H_2 O $$

$$ FeSO_4. 5H_2 O $$

Solution

Question 6

$$ Zn - Hg$$

$$ Fe - Hg $$

$$ Hg - Cr $$

$$ Na - Hg $$

Solution

Question 7

Melting point

1000K

Curie point

Boiling point

Solution

Question 8

Platinum painting

Flat sheet of platinum

Platinum manufacturing

Platinum used as a catalyst

Solution

Question 9

yellow

red

blue

cannot be predicted

Solution

Question 10

$$Al$$

$$Fe$$

$$Pd$$

$$K$$

Solution

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