The d- and f- Block Elements Test

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The d- and f- Block Elements Test - 72

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Question 1
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Directions For Questions

Paramagnetism is a property due to the presence of unpaired electrons. In case of transition metals as they contain unpaired electron in the (n-1) d orbitals most of the transition metal ions and their compounds are paramagnetic. Paramagnetism increases with increase in number of unpaired electrons. Magnetic moment is calculated from spin only formula $$\mu =\sqrt{n(n+2)}$$ B.M=no of unpaired electrons. Similarly the colour of the compounds of transition metals may be attributed to the presence of incomplete (n-1) d subshell. When an electron from a lower energy of d-orbital is excited to a higher energy d-orbital the energy of excitation corresponds to the frequency of light absorbed. The frequency generally lies in the visible region. The colour observed corresponds to complementry colour of the light absorbed. The frequency of the light absorbed is determined by the nature of the ligand.

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Which of the following pair of compounds is expected to exhibit same colour in aqueous solution ?

A
$$FeCl_{2},CuCl_{2}$$

B
$$VOCl_{2},CuCl_{2}$$

C
$$VOCl_{2},FeCl_{2}$$

D
$$FeCl_{2},MnCl_{2}$$

Solution
Question 2
1 / -0

Directions For Questions

Paramagnetism is a property due to the presence of unpaired electrons. In case of transition metals as they contain unpaired electron in the (n-1) d orbitals most of the transition metal ions and their compounds are paramagnetic. Paramagnetism increases with increase in number of unpaired electrons. Magnetic moment is calculated from spin only formula $$\mu =\sqrt{n(n+2)}$$ B.M=no of unpaired electrons. Similarly the colour of the compounds of transition metals may be attributed to the presence of incomplete (n-1) d subshell. When an electron from a lower energy of d-orbital is excited to a higher energy d-orbital the energy of excitation corresponds to the frequency of light absorbed. The frequency generally lies in the visible region. The colour observed corresponds to complementry colour of the light absorbed. The frequency of the light absorbed is determined by the nature of the ligand.

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Titanium shows magnetic moment of 1.73 B M in its compound . What is the oxidation state of titanium in the compound ?

A
+2

B
+1

C
+3

D
+4

Solution
Question 3
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Consider the following statements and arrange in the order of true/false as given in the codes.
$$S_{1}$$ : The IUPAC name of the compound $$\left [ Cr\left ( NH_{3} \right )_{5} \left ( NCS \right )\right ]\left [ ZnCl_{4} \right ]$$ is pentaamminethiocyanato-N-chromate (III) tetraachlorozincate (II).
$$S_{2}: CoSO_{4}$$ is paramagnetic and coloured.
$$S_{3}:\left [ Co\left ( NH_{3} \right )_{4}\left ( NO_{2} \right )_{2} \right ]NO_{3}$$ shows ionisation, linkage and geometrical isomerism.
$$S_{4}$$ : The C-O bond length in the complex, $$\left [ Fe\left ( CO \right )_{5} \right ]$$ is same as that found in carbon monoxide itself.

A
F T T F

B
T T T T

C
F T T F

D
T T T F
Question 4
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Directions For Questions

$$CuSO_{4}.5H_{2}O+KCN$$ (excess) $$\rightarrow A$$ (cyano complex)

$$CuSO_{4}.5H_{2}O+NH_{4}OH$$ (excess) $$\rightarrow B$$ (ammine complex)

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Predict the magnetic nature of $$A$$ and $$B$$:

A
Both are diamagnetic

B
Both are paramagnetic

C
$$A$$ is paramagnetic and $$B$$ is diamagnetic

D
$$A$$ is diamagnetic and $$B$$ is paramagnetic
Question 5
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Consider the following statements and arrange in the order of true/false as given in the codes.
$$S_{1}$$ : Both $$\left [ Co\left ( ox \right )_{3} \right ]^{3-}$$ and $$\left [ CoF_{6} \right ]^{3-}$$ are paramegnetic.
$$S_{2}:CoCl_{3}3NH_{3}$$ complex is non-conducing.
$$S_{3}$$ : The number of possible isomers for the complex $$\left [ Pt\left ( NO_{2} \right )\left ( py \right )\left ( OH \right )\left ( NH_{3} \right ) \right ]$$ is six.
$$S_{4}$$ : The oxidation state of iron in brown ring complex $$\left [ Fe\left ( H_{2}O \right )_{5}NO^{+} \right ]SO_{4}$$ is +II where NO is $$NO^{+}$$

A
F T T F

B
T T T T

C
F T T F

D
T T T F
Solution
$$S_1:[CoF_6]^{3−}\text{ is paramagnetic with 5 unpaired electrons but }[Co(ox)_3]^{3−}\text{ is diamagnetic as all electrons}$$ $$\text{are paired.}$$
$$S_2:\text{ It exists as }[Co(NH_3)_3Cl_3],\text{ neutral molecule.}$$
$$S_3:\text{ It is a correct statement. It shows linkage and geometrical isomerism.}$$
$$S_4: [Fe(+I)(H_2O)_5NO^+]SO^{2−}_4$$

Option C is correct.
Question 6
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Directions For Questions

In metal carbonyls, there is synergic bonding interaction between metal and carbon monoxide. This leads to an increase in strength of the metal-ligand bond and a decrease in bond order of CO in carbonyl complex as simple carbonyls are invariably spin-paired complexes except for vanadium metal.

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Which amongst the following metal carbonyls are inner orbital complexes with diamagnetic property?

A
$$ Ni(CO)_{4} $$

B
$$ Fe(CO)_{5} $$

C
$$ V(CO)_{6} $$

D
$$Cr(CO)_{6} $$
Question 7
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The catalytic activity of the transition metals and their compounds is described to their

A
chemical reactivity

B
magnetic behaviour

C
unfilled d-orbitals

D
ability to adopt multiple oxidation states and their complexing ability

Solution

The catalytic activity of the transition metals and their compounds is described to their chemical reactivity.
Hence, Option "A" is the correct answer.
Question 8
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Which of the following is a colourless ion?

A
$$ Cu^{2+} $$

B
$$ Fe^{3+} $$

C
$$ Ti^{3+} $$

D
$$ Zn^{2+} $$

Solution

$$ Zn^{2+} $$ has no unpaired electrons. All the electrons are paired and due to this, $$ Zn^{2+} $$ ion will be colourless.
Question 9
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The transition metal used as a catalyst is:

A
Nickel

B
Platinum

C
Cobalt

D
All of these

Solution

$$Ni$$,$$Pt$$ and $$Co$$ all three transition metals are used as a catalysts.

Option D is correct.
Question 10
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Which of the following transition metal is used as a catalyst?

A
Nickel

B
Cobalt

C
Gold

D
Both (A) and (B)

Solution

Ni and Co are used as catalyst. Ni is used in hydrogenation as catalyst.

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The d- and f- Block Elements Test - 72

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The d- and f- Block Elements Test - 72

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Question 1

$$FeCl_{2},CuCl_{2}$$

$$VOCl_{2},CuCl_{2}$$

$$VOCl_{2},FeCl_{2}$$

$$FeCl_{2},MnCl_{2}$$

Solution

Question 2

+2

+1

+3

+4

Solution

Question 3

F T T F

T T T T

F T T F

T T T F

Question 4

Both are diamagnetic

Both are paramagnetic

$$A$$ is paramagnetic and $$B$$ is diamagnetic

$$A$$ is diamagnetic and $$B$$ is paramagnetic

Question 5

F T T F

T T T T

F T T F

T T T F

Solution

Question 6

$$ Ni(CO)_{4} $$

$$ Fe(CO)_{5} $$

$$ V(CO)_{6} $$

$$Cr(CO)_{6} $$

Question 7

chemical reactivity

magnetic behaviour

unfilled d-orbitals

ability to adopt multiple oxidation states and their complexing ability

Solution

Question 8

$$ Cu^{2+} $$

$$ Fe^{3+} $$

$$ Ti^{3+} $$

$$ Zn^{2+} $$

Solution

Question 9

Nickel

Platinum

Cobalt

All of these

Solution

Question 10

Nickel

Cobalt

Gold

Both (A) and (B)

Solution

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