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The d- and f- Block Elements Test - 73

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The d- and f- Block Elements Test - 73
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  • Question 1
    1 / -0
    Which ion has maximum magnetic moment?
    Solution
    $$Fe^{3+}$$ ion has maximum magnetic moment as it has highest (5) number of unpaired electrons.
  • Question 2
    1 / -0
    The dark red colour of bombs in fireworks is due to the presence of  
    Solution
    The dark red colour of bombs in fireworks is due to the presence of  Strontium.
    Hence, Option "C" is the correct answer.
  • Question 3
    1 / -0
    Which of the following types of metal make the most efficient catalysts?
    Solution
    Transition metals are the most efficient catalysts due to partially or half-filled d-orbitals.

    Transition metals can form unstable intermediate products with suitable reactants. These intermediate products lower the activation energy of the reaction which makes the reaction faster. 

    So, transition elements are the most efficient catalysts.
  • Question 4
    1 / -0
    Fe, Co and Ni have valuable catalytic properties in process involving 
    Solution
    A Catalyst is a substance which accelerates the rate of a chemical reaction without undergoing any change in its chemical composition or mass during the reaction. A catalyst accelerates the rate of a reaction by lowering the activation energy.

    Fe, Co and Ni have valuable catalytic properties in the process involving hydrogenation due to large surface area and variable valency. Thus Ni is used for the hydrogenation of vegetable oils to vegetable fats.
  • Question 5
    1 / -0
    Which has the maximum ferromagnetic character? 
    Solution
    Iron has a maximum number of unpaired electrons so it has the maximum ferromagnetic character. 
  • Question 6
    1 / -0
    $$ Fe^{2+} $$ does not give prussian blue colour with $$ Fe^{2+} $$, but on its reaction with (x), prussian blue colur appears with the reagent (x) is
    Solution

  • Question 7
    1 / -0
    Which of the following species is expected to show the highest magnetic moment? (At. No.: Cr = 24, Mn = 25, Co = 27, Ni = 28, Cu =29)
    Solution
    Highest magnetic moment depends upon number of unpaired electron since. 

    $$ Cr^{2+} = [Ar]3d^4 4s^0 , \quad Mn^{2+} = [Ar]3d^5 4s^0 $$

    $$ Cu^{2+} = [Ar]3d^9 4s^0,\quad Co^{2+} = [Ar]3d^7 4s^0 ,\quad Ni^{2+} = [Ar]3d^8 4s^0 $$

    So $$ Mn^{2+} $$ contain maximum number of unpaired electron i.e. 5.
  • Question 8
    1 / -0
    Which of the following ions gives coloured solution? 
    Solution
    $$ Fe^{2+} $$ ion is coloured due to presence of 4 unpaired electrons in d-orbitals.
  • Question 9
    1 / -0
    Which of the following ions is paramagnetic?
    Solution
    $$ Ti^{+3} $$ is paramagnetic due to presence of an unpaired electron.

    $$Ti\to [Ar]3d^24s^2$$

    $$Ti^{3+}\to [Ar]3d^14s^0$$

  • Question 10
    1 / -0
    The 3d metal ions form coloured compounds because the energy corresponding to the following lies in the visible range of electromagnetic spectrum 
    Solution
    The 3d metal ions form coloured compounds because the energy corresponding to the d-d transition of 3d electrons lies in the visible range of the electromagnetic spectrum 
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