Coordination Compounds Test

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Coordination Compounds Test - 26

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Weekly Quiz Competition

Question 1
1 / -0

Total no. of possible isomers for complex compound $$[Cu(NH_{3})_{4}][PtCl_{4}]$$ are:

A
3

B
2

C
4

D
none of these

Solution

$$[Cu(NH_3)_4][PtCl_4],$$ $$[Cu(NH_3)_3Cl][PtCl_3NH_3],$$ $$ [Cu(NH_3)_2Cl_2][PtCl_2(NH_3)_2], $$ $$[Cu(NH_3)Cl_3][PtCl(NH_3)_3],$$ $$ [Cu(Cl)_4][Pt(NH_3)_4]$$
So five isomers are possible ,but third one do not exist due to unsatisfie charge on complex so only $$4$$ exist.
Question 2
1 / -0

Indicate the incorrect statement:

A
Number of hybrid orbitals formed is equal to no. of atomic involved

B
$$2{p}_{x}$$ and $$2{p}_{y}$$ orbitals of carbon can be hybridized to yield two new more stable orbitals

C
Effective hybridisation is not possible with orbitals of widely different energies

D
The concept of hybridization has a greater significance in the $$VB$$ theory of localised orbitals than $$MO$$ theory.

Solution

$$2{ p }_{ x }$$ & $$2{ p }_{ y }$$ orbitals of Carbon cannot be hybridized to yield $$2$$ more stable orbitals. This is because hybridization takes place between orbitals of different atoms thus the statement of option $$B$$ is incorrect. Hence answer is option $$B$$.
Question 3
1 / -0

Which can exist both as diastereoisomer and enantiomer?

A
$$[Pt(en)_{3}]^{4+}$$

B
$$[Pt(en)_{2}ClBr]^{2+}$$

C
$$[Ru(NH_{3})_{4}Cl_{2}]^{0}$$

D
$$[PtCl_{2}Br_{2}]^{0}$$

Solution

It exists as lis trans which is diastereomer and its cis form is optically active and exits as enantiomer also,where as only exists as enantiomers.
Question 4
1 / -0

A violet colour compound is formed in detection of $$S$$ in a compound:

A
$${ Na }_{ 4 }\left[ Fe{ \left( CN \right) }_{ 5 }NOS \right] $$

B
$${ Na }_{ 3 }\left[ Fe{ \left( CN \right) }_{ 5 }NOS \right] $$

C
$${ Na }_{ 2 }\left[ Fe{ \left( CN \right) }_{ 5 }NOS \right] $$

D
$${ Na }\left[ Fe{ \left( CN \right) }_{ 5 }NOS \right] $$

Solution

$$Na_2S+Na_2[Fe(CN)_5NO]\rightarrow Na_4[Fe(CN)_5NOS]$$(Violet Color Compond)
Question 5
1 / -0

Which of the following complex has five unpaired electrons?

A
$$[Mn({ H }_{ 2 }{ O })_{ 6 }{ ] }^{ 2+ }$$

B
$$[Mn(CN)_{ 6 }{ ] }^{ 3- }$$

C
$$[{ CrCl }_{ 3 }({ H }_{ 2 }{ O }_{ 3 }]$$

D
$$[Ag({ NH }_{ 3 }{ ) }_{ 2 }{ ] }^{ + }$$

Solution

$$Mn^{2+}$$ has $$d^5$$ configuration, since $$H_2O$$ is weak ligand field, so it does not causes pairing of electrons and hence it has 5 unpaired electrons.
Question 6
1 / -0

In which of the following pair of complexes, the experimental magnetic moment and the geometric shapes same?

A
$$K\left[ Mn{ O }_{ 4 } \right] $$ and $${ K }_{ 2 }\left[ Ni{ Cl }_{ 4 } \right] $$

B
$${ K }_{ 2 }\left[ Ni\left( CN \right) _{ 4 } \right] $$ and $${ K }_{ 4 }\left[ Ni\left( CN \right) _{ 4 } \right] $$

C
$${ K }_{ 2 }\left[ Ni\left( CN \right) _{ 4 } \right] $$ and $${K}_2\left[ Ni{ \left( { NH }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] $$

D
$${ K }_{ 3 }\left[ Fe\left( CN \right) _{ 6 } \right] $$ and $${ K }_{ 4 }\left[ Fe\left( CN \right) _{ 6 } \right] $$

Solution

$$K_2[ Ni (CN)_4] \Rightarrow Ni^{+2} \Rightarrow 3d^8 4s^0$$

With cyanide, $$Ni^{+2}$$ form square planar and
diamagnetic complex.

$$K_2[ Ni (NH_3)_2Cl_2] \Rightarrow Ni^{0}\Rightarrow 3d^8 4s^2$$

Ammonia is a strong field ligand, There won't be any lone pair. Diamagnetic and square planar complex.

Option C is correct.
Question 7
1 / -0

Which of the following pairs of complexes whose aqueous solutions gives pale yellow and white precipitates respectively with $$0.1M$$ $$Ag{NO}_{3}$$?

A
$$\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 4 }{ Br }_{ 2 } \right] { Cl }_{ 2 }$$ and $$\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 4 }{ Cl }_{ 2 } \right] { Br }_{ 2 }$$

B
$$\left[ Co{ \left( { NH }_{ 3 } \right) }_{ 5 }{ NO }_{ 3 } \right] Br$$ and $$\left[ Co{ \left( { NH }_{ 3 } \right) }_{ 5 }Br \right] { NO }_{ 3 }\quad $$

C
$$\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 4 }{ Cl }_{ 2 } \right] { Br }_{ 2 }$$ and $$\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 4 }{ Br }_{ 2 } \right] { Cl }_{ 2 }\quad $$

D
$$\left[ Co{ \left( { NH }_{ 3 } \right) }_{ 5 }{ NO }_{ 3 } \right] Cl$$ and $$\left[ Co{ \left( { NH }_{ 3 } \right) }_{ 5 }Cl \right] { NO }_{ 3 }$$

Solution

The complex having $$Br$$ and $$Cl$$ out of coordination sphere only gives $$AgBr$$(pale yellow ) and $$AgCl$$ (white ppt.) respectively upon reaction with $$AgNO_3$$.
Question 8
1 / -0

A six coordinate complex of formula $$CrCl_{3} . 6H_{2}O$$ has green colour. A $$0.1\ M$$ solution of the complex when treated with excess of $$AgNO_{3}$$ gave $$28.7\ g$$ of white precipitate. The formula of the complex would be___________.

A
$$[Cr(H_{2}O)_{6}]Cl_{3}$$

B
$$[Cr(H_{2}O)_{5}Cl]Cl_{2} . H_{2}O$$

C
$$[Cr(H_{2}O)_{4}Cl]Cl_{2} . 2H_{2}O$$

D
$$[Cr(H_{2}O)_{3}Cl_{3}] . 3H_{2}O$$

Solution

Since $$0.1M$$ complex gives $$0.2$$ mole $$Agcl$$ means $$2Cl^{-}$$ are ionisable or out of coordination sphere so, complex is $$[Cr(H_2O)_5Cl]Cl_2.H_2O$$
Question 9
1 / -0

Which of the following complexes exists in facial and meridional forms?

A
$$K[Cr(H_{2}O)_{2}(C_{2}O_{4})_{2}]$$

B
$$[Co(NH)_{3}(NO_2)_3]$$

C
$$[Co(NH_{3})_{5} (NO_{2})](NO_{3})_{2}$$

D
$$[Pt(NH_{3})(H_{2}O)Cl_{2}]$$
Question 10
1 / -0

The halogen form compound among themselves with the formula $${ AA }^{ ' },{ AA }_{ 3 }^{ ' },{ AA }_{ 5 }^{ ' }$$ and $${ AA }_{ 7 }^{ ' }$$ where $$A$$ is the heavier halogen. Which of the following pairs representing their structure and being polar and non-polar are correct ?
(A) $${ AA }^{ ' }$$ linear, polar
(B) $${ AA }_{ 3 }^{ ' }$$ $$T-$$ Shaped, polar
(C) $${ AA }_{ 5 }^{ ' }$$ square pyramidal, polar
(D) $${ AA }_{ 7 }^{ ' }$$ pentagonal bipyramidal, non-polar

A
$$(A)$$ and $$(C)$$ are correct

B
$$(A)$$, $$(B)$$ And $$(C)$$ are correct

C
$$(B)$$, $$(C)$$ and $$(D)$$ are correct

D
$$(A)$$, $$(B)$$, $$(C)$$ and $$(D)$$ are correct

Solution

$$AA'$$ linear,polar as both halogen atoms with different electronegativity has polarity. Eg-$$ I-Cl$$
$$AA_5^{'}$$ square pyramidal and polar due to the high electronegativity of other atom. Eg-$$IF_5$$

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Coordination Compounds Test - 26

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Coordination Compounds Test - 26

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Question 1

3

2

4

none of these

Solution

Question 2

Number of hybrid orbitals formed is equal to no. of atomic involved

$$2{p}_{x}$$ and $$2{p}_{y}$$ orbitals of carbon can be hybridized to yield two new more stable orbitals

Effective hybridisation is not possible with orbitals of widely different energies

The concept of hybridization has a greater significance in the $$VB$$ theory of localised orbitals than $$MO$$ theory.

Solution

Question 3

$$[Pt(en)_{3}]^{4+}$$

$$[Pt(en)_{2}ClBr]^{2+}$$

$$[Ru(NH_{3})_{4}Cl_{2}]^{0}$$

$$[PtCl_{2}Br_{2}]^{0}$$

Solution

Question 4

$${ Na }_{ 4 }\left[ Fe{ \left( CN \right) }_{ 5 }NOS \right] $$

$${ Na }_{ 3 }\left[ Fe{ \left( CN \right) }_{ 5 }NOS \right] $$

$${ Na }_{ 2 }\left[ Fe{ \left( CN \right) }_{ 5 }NOS \right] $$

$${ Na }\left[ Fe{ \left( CN \right) }_{ 5 }NOS \right] $$

Solution

Question 5

$$[Mn({ H }_{ 2 }{ O })_{ 6 }{ ] }^{ 2+ }$$

$$[Mn(CN)_{ 6 }{ ] }^{ 3- }$$

$$[{ CrCl }_{ 3 }({ H }_{ 2 }{ O }_{ 3 }]$$

$$[Ag({ NH }_{ 3 }{ ) }_{ 2 }{ ] }^{ + }$$

Solution

Question 6

$$K\left[ Mn{ O }_{ 4 } \right] $$ and $${ K }_{ 2 }\left[ Ni{ Cl }_{ 4 } \right] $$

$${ K }_{ 2 }\left[ Ni\left( CN \right) _{ 4 } \right] $$ and $${ K }_{ 4 }\left[ Ni\left( CN \right) _{ 4 } \right] $$

$${ K }_{ 2 }\left[ Ni\left( CN \right) _{ 4 } \right] $$ and $${K}_2\left[ Ni{ \left( { NH }_{ 3 } \right) }_{ 2 }{ Cl }_{ 2 } \right] $$

$${ K }_{ 3 }\left[ Fe\left( CN \right) _{ 6 } \right] $$ and $${ K }_{ 4 }\left[ Fe\left( CN \right) _{ 6 } \right] $$

Solution

Question 7

$$\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 4 }{ Br }_{ 2 } \right] { Cl }_{ 2 }$$ and $$\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 4 }{ Cl }_{ 2 } \right] { Br }_{ 2 }$$

$$\left[ Co{ \left( { NH }_{ 3 } \right) }_{ 5 }{ NO }_{ 3 } \right] Br$$ and $$\left[ Co{ \left( { NH }_{ 3 } \right) }_{ 5 }Br \right] { NO }_{ 3 }\quad $$

$$\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 4 }{ Cl }_{ 2 } \right] { Br }_{ 2 }$$ and $$\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 4 }{ Br }_{ 2 } \right] { Cl }_{ 2 }\quad $$

$$\left[ Co{ \left( { NH }_{ 3 } \right) }_{ 5 }{ NO }_{ 3 } \right] Cl$$ and $$\left[ Co{ \left( { NH }_{ 3 } \right) }_{ 5 }Cl \right] { NO }_{ 3 }$$

Solution

Question 8

$$[Cr(H_{2}O)_{6}]Cl_{3}$$

$$[Cr(H_{2}O)_{5}Cl]Cl_{2} . H_{2}O$$

$$[Cr(H_{2}O)_{4}Cl]Cl_{2} . 2H_{2}O$$

$$[Cr(H_{2}O)_{3}Cl_{3}] . 3H_{2}O$$

Solution

Question 9

$$K[Cr(H_{2}O)_{2}(C_{2}O_{4})_{2}]$$

$$[Co(NH)_{3}(NO_2)_3]$$

$$[Co(NH_{3})_{5} (NO_{2})](NO_{3})_{2}$$

$$[Pt(NH_{3})(H_{2}O)Cl_{2}]$$

Question 10

$$(A)$$ and $$(C)$$ are correct

$$(A)$$, $$(B)$$ And $$(C)$$ are correct

$$(B)$$, $$(C)$$ and $$(D)$$ are correct

$$(A)$$, $$(B)$$, $$(C)$$ and $$(D)$$ are correct

Solution

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