Coordination Compounds Test

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Coordination Compounds Test - 40

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Question 1
1 / -0

Square planar complex of the type MAXBL(where A, B, X and L are unidentate ligands) shows following set of isomers.

A
two cis and one trans

B
two trans and one cis

C
two cis and two trans

D
three cis and one trans

Solution

Square planar complex of the type $$MAXBL$$ (where A, B, X, and L are unidentate ligands) $$\text{shows two cis and}$$ $$\text{one trans isomer as shown in the image.}$$
Question 2
1 / -0

The hybrid state and oxidation state of two oxygen atoms in $$H_2O_2$$ are respectively:

A
$$sp^2, -1$$

B
$$sp^2, +1$$

C
$$sp^3, -1$$

D
$$sp^3, +1$$

Solution
Question 3
1 / -0

The hybridisation of oxygen atom in $$H_2O_2$$ is:

A
$$sp^3d$$

B
$$sp$$

C
$$sp^2$$

D
$$sp^3$$

E
$$sp^3d^2$$

Solution

each oxygen atom in peroxide is $$sp^3$$ hybridized. There is a covalent $$sp^3-sp^3$$ bond between the two oxygens. Each oxygen atom is covalently linked to its respective hydrogen via.

$$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (D)}$$
Question 4
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When $$1$$ mol $$CrCl_3\cdot 6H_2O$$ is treated with excess of $$AgNO_3, 3$$ mol of $$AgCl$$ are obtained. The formula of the complex is?

A
$$[CrCl_3(H_2O)_3]\cdot 3H_2O$$

B
$$[CrCl_2(H_2O)_4]Cl\cdot 2H_2O$$

C
$$[CrCl(H_2O)_5]Cl_2\cdot H_2O$$

D
$$[Cr(H_2O)_6]Cl_3$$

Solution

One mol of $$ AgCL $$ is precipitated by one mole of $$ CL^- $$ ion, therefore three moles of $$ AgCL $$ would get precipitared by three moles of chloride ions, $$ CL^- $$ and, in this case $$ 3 CL^- $$ are present in ionization sphere ( ie. out side the coordination sphere) in complex at $$ (iv) $$, therefore when $$ 1 $$ mol of it is treated with excess of this complex $$ 3 $$ mols of $$ AgCL $$ is precipitated. This satisfied the formula of the complex at $$ (iv) $$
Question 5
1 / -0

Hybridisation of the _____atom change sin:

A
$$ AIH_3 to AlH_4^- $$

B
$$ H_2O to H_3 O^+ $$

C
$$ NH_2^- $$

D
$$ NF_3 $$

Solution

hybridization of central atom changes as the product is
in this change $$ AlH_3$$ to $$AlH_4^-$$
Question 6
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Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type $$[Pd(C_6H_5)_2(SCN)_2]$$ and $$[Pd(C_6H_5)_2(NCS)_2]$$ are?

A
Linkage isomers

B
Coordination isomers

C
Ionization isomers

D
Geometrical isomers

Solution

Linkage isomerism arises in a coordination compound containing ambidentate ligand. A simple example is by complexes containing the thiocyanate ligand, $$ NCS-, $$ which may bind through the nitrogen to give $$ M-NCS $$ or through sulphur to give $$ M-SCN . $$
Question 7
1 / -0

The hybridization of I in ICl$$_2^+$$ is :

A
$$sp$$

B
$$ sp^2 $$

C
$$ sp^3 $$

D
$$ dsp^2 $$

Solution
Question 8
1 / -0

Which of the following two are isostructral?

A
$$XeF_2, IF_2^-$$

B
$$NH_3, BF_3$$

C
$$CO_3^{2-}, SO_3^{2-}$$

D
$$PCl_5, ICl_5$$

Solution

$$XeF_2$$ is a linear molecule (Xe is $$sp^3d$$ hybridized with three equatorial positions occupied by lone pairs)

$$IF_2^-$$ is a linear molecule (I is $$sp^3d$$ hybridized, with three positions occupied by lone pairs).

Option A is correct.
Question 9
1 / -0

$$[Co(NH_3)_5Br]SO_4$$ and $$[Co(NH_3)_5SO_4]Br$$ are related to each other as :

A
ionization isomers

B
linkage isomers

C
coordination isomers

D
geometrical isomers

Solution

This both complex show ionization isomerism.

Ionization isomerism occurs when the ligand has exchanged places with an anion or neutral molecule that was originally outside the coordination complex.

Hence, the correct option is (A).
Question 10
1 / -0

In $$Cu$$-ammonia complex, the state of hybridisation of $$Cu^{2+}$$ is:

A
$$sp^3$$

B
$$sp^3d$$

C
$$sp^2$$

D
$$dsp^2$$

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Coordination Compounds Test - 40

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Coordination Compounds Test - 40

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Question 1

two cis and one trans

two trans and one cis

two cis and two trans

three cis and one trans

Solution

Question 2

$$sp^2, -1$$

$$sp^2, +1$$

$$sp^3, -1$$

$$sp^3, +1$$

Solution

Question 3

$$sp^3d$$

$$sp$$

$$sp^2$$

$$sp^3$$

$$sp^3d^2$$

Solution

Question 4

$$[CrCl_3(H_2O)_3]\cdot 3H_2O$$

$$[CrCl_2(H_2O)_4]Cl\cdot 2H_2O$$

$$[CrCl(H_2O)_5]Cl_2\cdot H_2O$$

$$[Cr(H_2O)_6]Cl_3$$

Solution

Question 5

$$ AIH_3 to AlH_4^- $$

$$ H_2O to H_3 O^+ $$

$$ NH_2^- $$

$$ NF_3 $$

Solution

Question 6

Linkage isomers

Coordination isomers

Ionization isomers

Geometrical isomers

Solution

Question 7

$$sp$$

$$ sp^2 $$

$$ sp^3 $$

$$ dsp^2 $$

Solution

Question 8

$$XeF_2, IF_2^-$$

$$NH_3, BF_3$$

$$CO_3^{2-}, SO_3^{2-}$$

$$PCl_5, ICl_5$$

Solution

Question 9

ionization isomers

linkage isomers

coordination isomers

geometrical isomers

Solution

Question 10

$$sp^3$$

$$sp^3d$$

$$sp^2$$

$$dsp^2$$

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