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Inverse Trigonometric Functions Test - 65

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Inverse Trigonometric Functions Test - 65
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  • Question 1
    1 / -0
    Solution of $${\tan ^{ - 1}}\frac{{2x}}{{1 - {x^2}}} + {\cot ^{ - 1}}\frac{{1 - {x^2}}}{{2x}} = \frac{{2\pi }}{3}\,\,$$ are
    Solution

  • Question 2
    1 / -0
    If $$A=\tan {-1}(\frac {x\sqrt 3}{2k-x})$$ and $$B=\tan ^{-1}(\frac {2x-k}{k\sqrt 3})$$, then the value of A-B is
  • Question 3
    1 / -0
    If $$\alpha$$ is the only real root of the equation $$\displaystyle x^3 + bx^2 + c = 0 $$ ($$b$$ < $$c$$) then the value of $$\displaystyle Tan^{1}\alpha + Tan^{1}\left ( \dfrac{1}{\alpha} \right  ) $$ = 
    Solution

  • Question 4
    1 / -0
    If $$\displaystyle Sin^{1}(x - \dfrac{x^2}{2} + \dfrac{x^3}{4} - .......) + Cos^{1}(x^2 - \dfrac{x^4}{2} + \dfrac{x^6}{4} - ......) = \dfrac{\pi}{2} $$ for 0 < $$\left | x \right |$$ < $$\sqrt{2}$$ then $$x$$ = 
    Solution

  • Question 5
    1 / -0
    The value of $${ sin }^{ -1 }\left[ cot\left( { sin }^{ -1 }\sqrt { \left( \cfrac { 2-\sqrt { 3 }  }{ 4 }  \right)  } +{ cos }^{ -1 }\left( \cfrac { \sqrt { 12 }  }{ 4 }  \right) +{ sec }^{ -1 }\sqrt { 2 }  \right)  \right] $$ is :
    Solution

  • Question 6
    1 / -0
    If $${ sin }^{ -1 }x+{ sin }^{ -1 }y=\cfrac { 2\pi  }{ 3 } $$, then $${ cos }^{ -1 }x+{ cos }^{ -1 }y=$$
  • Question 7
    1 / -0
    If $$A=\tan ^{-1}(\frac {x\sqrt 3}{2k-x})$$ and $$B=\tan {-1}(\frac {2x-k}{k\sqrt 3})$$, then the value of $$A-B$$ is
    Solution

  • Question 8
    1 / -0
    If $$x$$ = $$Tan^{1}(1)$$ + $$Cos^{1}(\dfrac{1}{2})$$ + $$Sin^{1}(\dfrac{1}{2})$$ and $$y$$ = $$ cos\left [ \dfrac{1}{2}Cos^{1}(1/8) \right ] $$ then 
    Solution

  • Question 9
    1 / -0
    If $$A=2{\tan}^{-1}\left(2\sqrt{2}-1\right)$$ and $$B=3{\sin}^{-1}\left(1/3\right)+{sin}^{-1}\left(3/5\right)$$, then 
    Solution

  • Question 10
    1 / -0
    The value of $${\sin}^{-1}\left( \sin12 \right )+{\sin}^{-1}\left( \cos12 \right )=$$
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