Application of ...

The area bounded by the curve $$y^{2}=x$$ and the line $$\mathrm{x}=4$$ is:

The area of the region between the curve $$y=4x^{2}$$ and the line $$y=6x-2$$ is:

The area bounded by the parabola $$y^{2}=4x$$ and the line $$y=2x-4$$:

The area bounded by the line $$\mathrm{x}=1$$ and the curve $$\sqrt{\dfrac{y}{x}}+\sqrt{\dfrac{x}{y}}=4$$ is

Area of the region enclosed by $$y^{2}=8x$$ and $${y}=2{x}$$ is

The area between the curves $$y=\sqrt{x}$$ and $$y=x^{3}$$ is

The area bounded by the parabola $$x^{2}=4ay,\ \mathrm{x}$$-axis and the straight line $$\mathrm{y}=2\mathrm{a}$$ is:

The area bounded by $$\mathrm{y}=\mathrm{s}\mathrm{i}\mathrm{n}\mathrm{x},\ \mathrm{y}=\mathrm{c}\mathrm{o}\mathrm{s}\mathrm{x}$$ between any two successive intersections is:

The area bounded by the curves $$y=\sin x,y=$$ cosx and the $$\mathrm{y}$$-axis and the first point of intersection is:

Assertion(A): The area bounded by $$y^{2}=4x$$ and $$x^{2}=4y$$ is $$\displaystyle \frac{16}{3}$$ sq. units.

Reason(R): The area bounded by $$y^{2}=4ax$$ and $$x^{2}=4ay$$ is $$\displaystyle \frac{16a^2}{3}$$ sq. units