Application of ...

Area common to the curve $$y^2 = 16x$$ and $$y = 2x$$, is : 

The area bounded by the curve $$y=sin(x-[x]),y=sin1,\,x=1$$ and the x-axis is

The area of the region bounded by $$\left| arg\left( z+1 \right)  \right| \le \frac { \pi  }{ 3 } $$ and $$ \left|z+1   \right| \le \frac { \pi  }{ 4 } $$ is given by

The curves $$y = x^{2} - 1, y = 8x - x^{2} - 9$$ at

The area enclosed between the curves $$y={ ax }^{ 2 }$$ and $$x={ ay }^{ 2 }$$ $$(a>0)$$ is $$1\ sq.unit$$. then $$a=$$

The area bounded by the curves $$y=f(x)$$, the x-axis and the ordinates $$x=1$$ and $$x=\beta $$ is $$(\beta -1)\sin(3\beta +4)$$. Then $$f(x)$$ is

Two vertices of a rectangle are on the positive x-axis. The other two vertices lie on the lines $$y=4x$$ and $$y=-5x+6$$. Then the maximum area of the rectangle is?

The area of the region bounded by the curve $${a^4}{y^2} = \left( {2a - x} \right){x^5}$$ is to that curve whose radius is $$a$$, is given by the ration.

The area enclosed between the curves $$y=a{ x }^{ 2 }$$ and $$x=a{ y }^{ 2 }$$ $$\\ (a>0)$$ is $$1sq.unit$$. then $$a=$$

If area bounded by $$f(x)=x^{\frac{1}{3}}(x-1)$$ $$x-$$axis is A then find the value of $$28A$$.