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  • Question 1
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    The area enclosed by the curve $$y=\sqrt{(4-x^2)}, y\geq \sqrt{2}\sin\left(\dfrac{x\pi}{2\sqrt{2}}\right)$$ and x-axis is divided by y-axis in the ratio.

  • Question 2
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    The area of the region enclosed between by the $${x^2} + {y^2} = 16$$  and the parabola  $${y^2} = 6x$$.

  • Question 3
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    In the square ABCD, the "shaded" region is the intersection of two circular regions centered at B and D respectively. If AB= 10, then what is the area of the shaded region?

  • Question 4
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    Area bounded by $$|x-1| \le 2$$ and $$x^{2}-y^{2}=1$$, is

  • Question 5
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    Directions For Questions

    Three circles passes through centre of each other, each having radius $$\sqrt{3}$$ unit. They are inscribed in a rectangle of length $$4\sqrt{3}$$ unit and breadth $$2\sqrt{3}$$ unit.

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    Find area curved by three circles 

  • Question 6
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    Directions For Questions

    A continuous function $$f\left(x\right)$$ satisfying $${x}^{4}-4{x}^{2}\le f\left(x\right)\le 2{x}^{2}-{x}^{3}$$ for all $$x\in\left[0,2\right]$$ such that the area bounded by $$y=f\left(x\right),y={x}^{4}-4{x}^{2}$$ the $$y-$$axis and the line $$x=t\left(0\le t\le 2\right)$$ is $$k$$ times the area bounded by $$y=f\left(x\right),y=2{x}^{2}-{x}^{3},y-$$axis and the line $$x=t, \left(0\le t\le 2\right).$$ Answer the following questions:

    ...view full instructions

    If $$k=2$$ then $$f\left(x\right)$$ attains point of inflection at

  • Question 7
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    The triangle formed by the tangent to the parabola $$y^2=4x$$ at the point whose abscissa lies in the interval $$\left[a^2, 4a^2\right]$$, the ordinate and the x-axis, has the greatest area equal to?

  • Question 8
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    Consider the two curves 

    $${ C }_{ 1 } :{ y }^{ 2 }=4x $$
    $$ { C }_{ 2 } : { x }^{ 2  }+ { y }^{ 2 } - 6x + 1 = 0$$
    Then, the area of region between these curves?

  • Question 9
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    Area bounded by the curves $$y=\log _{ e }{ x } \quad$$ and  $$y={ \left( \log _{ e }{ x }  \right)  }^{ 2 }$$ is ?

  • Question 10
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    The area enclosed between the curve $$y=x^3$$ and $$y=\sqrt{x}$$ is 

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