Application of ...

Area bounded between the curves $$y=\sqrt{4-x^2}$$ and $$y^2=3|x|$$ is/are?

Let $$A_{n}$$be the area bounded by the curve $$y=(\tan x)^{n}$$ and the lines $$x=0,y=0$$ and $$4x-\pi=0$$, where 

The area of a region bounded by $$X$$ -axis and the curves defined by $$y = \tan x$$ $$0 \leq x \leq \frac { \pi } { 4 }$$ and $$y = \cot x , \frac { \pi } { 4 } \leq x \leq \frac { \pi } { 2 }$$ is 

The area bounded by the curve $$ y = \dfrac { \sin { x }  }{ { x } } , x-$$ axis and the ordinates $$ x=0,x=\dfrac { \pi }{ { 4 } }$$ is:

The parabolas $$y^2=4x, x^2=4y$$ divide the square region bounded by the lines $$x=4$$, $$y=4$$ and the coordinate axes. If $$S_1, S_2, S_3$$ are respectively the area of these parts numbered from top to bottom then $$S_1 : S_2 : S_3$$ is?

Area of the figure bounded by $$x$$ -axis, $$y = \sin ^ { - 1 } x , y = \cos ^ { - 1 } x$$ and the first point intersection from the origin is

The area (in sq.units) of the region $$\left\{ ( x , y ) :{ y} ^ { 2 } \ge 2 x\right.$$ and $${x} ^ { 2 } +{ y} ^ { 2 } \le 4 x , x \ge 0 , y \ge 0$$ is 

Area bounded by $$y=-x^{2}+6x-5,y=-x^{2}+4x-3$$ and $$y=3x-15$$ for $$x > 1$$, is (in $$sq.\ units$$)

Find the area of shaded portion 

The area bounded by the curves $$\sqrt{x}+\sqrt{y}=1$$ and $${x}+{y}=1$$ is ?