Application of ...

Area bounded by curve $$y = (x - 1)(x - 2)(x - 3)$$ and x-axis between lines $$x = 0, x = 3$$

The area of the figure bounded by $$y=sinx, \ y=cosx$$ is the first quadrant is

The area bounded by the curve $$ y =x^4 -2x^3 + x^2 + 3 $$ the axis of abscissas and two oridnates corrsponding to the point of minimum of function y(x) is 

The area of the region bounded by $$y^2=2x +1$$ and $$x-y-1=0$$ is 

The area of the region enclosed by the curve $$ \mid y \mid =-(1- \mid x \mid)^2 +5 $$, is

If the area bounded by the curve $$ y=x^2 +1, y=x $$ and the pair of lines $$ x^2 + y^2 + 2xy - 4x -4y +3 =0 $$ is $$K$$ units, then the area of the region bounded by the curve $$y=x^2 +1, \ y= \sqrt{x-1}$$ and the pair of lines $$ (x+y-1)(x+y-3)=0 ,$$ is

The area bounded by the curve $$y= \dfrac{3}{\mid x \mid}$$ and $$y+ \mid 2-x \mid =2$$ is

The area bounded by the curves $$y=x^2 +2$$ and $$y=2 \mid x \mid -cosx +x$$ is 

The areas of the figure into which the curve $$y^2=6x$$ divides the circle $$x^2 + y^2 = 16$$ are in the ratio

The area bounded by the curve $$f(x) = \mid \mid tanx + cotx \mid - \mid tanx - cotx \mid \mid$$ between the lines $$x=0, \ x= \dfrac{\pi}{2}$$ and the $$X-$$axis is