Electric Charges and Fields Test

Result

Electric Charges and Fields Test - 77

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Weekly Quiz Competition

Question 1
1 / -0

In the figure distance of the point from $$A$$, where the electric field is zero is:-

A
$$20cm$$

B
$$10cm$$

C
$$33cm$$

D
None of these

Solution
Question 2
1 / -0

A solid metallic sphere has a charge +3Q concentric with this sphere is a conducting spherical shell having charge O. The radius of the sphere is a and that of the spherical shell is b(>a). What is the electric field at a distance r(a < r < b) from the centre?

A
$$\frac { 1 }{ 4{ \pi \epsilon_{0} } } \frac { Q }{ r } $$

B
$$\frac { 1 }{ 4{ \pi \epsilon_{0} } } \frac { 3Q }{ r } $$

C
$$\frac { 1 }{ 4{ \pi \epsilon_{0} } } \frac {3Q }{ r^2 }$$

D
None of the above

Solution
Question 3
1 / -0

A capacitor is a perfect insulator for:

A
constant direct current

B
alternating current

C
direct as well as alternating current

D
variable direct current.

Solution
Question 4
1 / -0

A point charge $$50 \: \mu C$$ is located in the $$XY $$ plane at the point of position vector $$ r_1 = 2i + 3j $$ . What is the electric field at the point of position vector $$r_2 = 8i-5j$$.

A
$$1200 v/m$$

B
$$0.04 V/m$$

C
$$900 V/m$$

D
$$4500 V/m$$

Solution
Question 5
1 / -0

In order to balance the weight of an electron in an electric field E the magnitude and the direction of the electric field will be ( g = 10 $$m/s^2$$)

A
$$5.68 \times 10^{-11}$$ N/C vertically upwards

B
$$5.68 \times 10^{-11}$$ N/C vertically downwards

C
$$5.68 \times 10^{-10}$$ N/C vertically upwards

D
$$5.68 \times 10^{-10}$$ N/C vertically downwards

Solution
Question 6
1 / -0

A charge q is divided into two parts $${ q }_{ 1 }$$ and ($${q} - { q }_{ 1 }$$) What is the ratio q /$${ q }_{ 1 }$$ so that the force between the two parts when placed a given distance apart is maximum:

A
$$1:1$$

B
$$2:1$$

C
$$1:2$$

D
$$1:4$$

Solution
Question 7
1 / -0

There are two point charges $$q_1$$ and $$q_2$$ lying on a circle of unit radius. Electric field intensity at the center of circle due to these charges is $$\vec { E }$$. Find the position vector of the center with respect to $$q_2$$ is $$\vec { r } _ { 1 }$$

A
$$\frac { \vec { E } + k q _ { 1 } \vec { r } _ { 1 } } { k q _ { 2 } }$$

B
$$- \left( \frac { \vec { E } + k q _ { 1 } \overline { r } _ { 1 } } { k q _ { 2 } } \right)$$

C
$$\frac { \mathrm { kq } _ { 1 } \vec { \mathrm { r } } _ { 1 } - \vec { \mathrm { E } } } { \mathrm { k } q _ { 2 } }$$

D
$$\frac { \vec { \mathrm { E } } - \mathrm { kq } _ { 1 } \overline { \mathrm { r } } _ { 1 } } { \mathrm { kq } _ { 2 } }$$

Solution
Question 8
1 / -0

What is the value of electric flux in SI unit in the Y-Z plane of area $$2{m^2}$$ , if intensity of electric field is $$\overrightarrow {\text{E}} {\text{ = }}\left( {{\text{5}}\widehat {\text{i}}{\text{ + 2}}\widehat {\text{j}}} \right){\text{N/C}}$$

A
$$10$$

B
$$20$$

C
$$10\sqrt 2 $$

D
$$2\sqrt {29} $$

Solution
Question 9
1 / -0

A cone of base radius R and height $$h$$ is located in a uniform electric field $${\vec E}$$ parallel to its base. The electric flux entering the cone is

A
$$EhR$$

B
$$\frac{1}{2}EhR$$

C
$$4EhR$$

D
$$2EhR$$

Solution
Question 10
1 / -0

Three charges $${q_1} = 1 \times {10^{ - 8}},{q_2} = 2 \times {10^{ - 6}},{q_3} = - 3 \times {10^{ - 6}}$$ have been placed, as shown in figure, in four surfaces $${S_1},{S_2},{S_3}$$ and $${S_4}$$ electrical flux emitted from the surface $${S_2}$$ in $$N - {m^2}/C$$ wil be

A
$$36\pi \times {10^3}$$

B
$$-36\pi \times {10^3}$$

C
$$36\pi \times {10^9}$$

D
$$-36\pi \times {10^9}$$

Solution