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Wave Optics Test - 76

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Wave Optics Test - 76
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Weekly Quiz Competition
  • Question 1
    1 / -0
    At the first minimum adjacent to the central maximum of a single slit diffraction plate the phase difference between the huygens wavelet from the edge of the slit and the wavelet from the midpoint of the slate
    Solution

  • Question 2
    1 / -0
    In a YDSE experiment , d= 1mm,$$\lambda =6000 A$$ and D =1 m. The minimum distance between two points on screen having 75% intensity of the maximum intensity will be
    Solution

  • Question 3
    1 / -0
    In a double slit experiment, the two slits are $$1\ mm$$ apart and the screen is placed $$1\ m$$ away. A monochromatic light wavelength $$500\ nm$$ is used. What will be the width of each slit for obtaining ten maxima of double slit with in the central maxima of single slit pattern ?
    Solution

  • Question 4
    1 / -0
    In case of diffraction pattern of a single slit under polychromatic illumination first minima of wavelength $${ \lambda  }_{ 1 }$$ is found coincide with the second maximam of wavelength $${ \lambda  }_{ 2 }$$ then
    Solution

  • Question 5
    1 / -0
    The beams, $$A$$ and $$B$$ of plane polarized light with mutually perpendicular planes of polarization are seen through a polaroid. From the position when the beam. A has maximum intensity (and beam $$B$$ has zero intensity), a rotation of polaroid through $$30^{\circ}$$ makes the two beams appear equally bright. If the initial intensities of the two beams are $$I_{A}$$ and $$I_{B}$$ respectively, then $$\dfrac {I_{A}}{I_{B}}$$ equals.
    Solution

  • Question 6
    1 / -0
    The path difference between two identical waves arriving at a point is $$120\lambda $$, if the path difference is $$72\mu m$$ then:
    Solution

  • Question 7
    1 / -0
    In young's double slit experiment , the intensity of light coming form the first slit is double the intensity from the second slit.The ratio of the maximum intensity to the minimum intensity on the interference fringe pattern observed is.
    Solution
    $$\dfrac {I_{max}}{I_{min}}=\left(\dfrac {\sqrt {\dfrac {I_1}{I_2}}+1}{\sqrt {\dfrac {I_1}{I_2}}-1}\right)^2$$

    $$ =\left(\dfrac {\sqrt 2 +1}{\sqrt 2 -1}\right)^2 \approx 34$$; (given $$i_1 =2i_2$$)
  • Question 8
    1 / -0
    In young's double slit experiment, D=1.5 m, $$ d=4.5 \times 10^{-3} $$ m and fringe width x=0.2 mm. what is the path difference between the interfering beams for two successive maxima ?
    Solution

  • Question 9
    1 / -0
    A double slit apparatus is immersed in a liquid of refractive index $$\mu_m$$. It has a slit separation $$d$$ and the distance between the plane of the slits and the screen as $$D(D > > d)$$. The slits are illuminated by a parallel beam of wavelength $$\lambda_{0}$$. The smallest thickness of a sheet of refractive index $$\mu_{p}$$ to bring adjacent minima on the axis is
    Solution

  • Question 10
    1 / -0
    $$Statement-1:$$ On viewing the clear blue portion of the sky through a Calcite Crystal, the intensity of transmitted light varies as the crystal is rotated.
    $$Statement-2:$$ The light coming from the sky is polarized due to scattering of sun light by particles in the atmosphere. The scattering is largest for blue light.
    Solution

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