Wave Optics Test

Result

Wave Optics Test - 79

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Question 1
1 / -0

A screen is at a distance of 2 m from a narrow slit illuminated with light of 600 nm. The first minimum lies 5 mm on either side of the central maximum. The width of slit is.

A
24 mm

B
0.24 mm

C
2.4 mm

D
0.024 mm

Solution
Question 2
1 / -0

In a double-slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then, in the interference pattern:

A
The intensities of both the maxima and the minima increases

B
The intensity of the maximum increase and minima has zero intensity

C
The intensity of the maxima decreases and that of minima increases

D
The intensity of the maxima decreases and the minima has zero intensity

Solution
Question 3
1 / -0

The double slit experiment of young has been shown in the figure: Q is the position of the first bright fringe on the right side and P is the $$11^{th}$$ fringe on the other side as measured from Q. If wavelength of light used is $$6000\overset { \circ }{ A } $$ $$,{ S }_{ 1 }B$$ will be equal to:

A
$$6\times10^{-6}m$$

B
$$6.6\times10^{-6}m$$

C
$$3.138\times10^{-7}m$$

D
$$3.144\times10^{-7}m$$

Solution

$$P$$ is the position of $$11^{th}$$ bright fringe from $$Q$$.From central position $$O, P$$ will be the position of $$10^{th}$$ bridge fringe.
Path difference between the waves at $$P=SB=10 \ \lambda $$
$$=10\times 6000\times 10^{-10}=6\times 10^{-6}m$$
Question 4
1 / -0

In a Young's double slit experiment the intensity at a point where the path difference is $$\lambda /6 (\lambda $$ being the wavelength of light used) is i. If $$I+o$$ denotes the maximum intensity, $$I/I_o$$ is equal to

A
$$3/4$$

B
$$1/\sqrt 2$$

C
$$\sqrt 3/2$$

D
$$1/2$$

Solution
Question 5
1 / -0

Visible light passing through a circular hole from a diffraction disc of radius 0.1 mm on a screen. If X-ray is passed through the same set-up, the radius of the diffraction disc will be :

A
zero

B
< 0.1 mm

C
0.1 mm

D
> 0.1 mm

Solution
Question 6
1 / -0

Light of wavelength $$\lambda $$ from a point source falls on a small circular obstacle of diameter 'd'. Dark and bright circular ring around a central bright pot are formed on a screen beyond the obstacle is D, then the condition for the formation of ring is :

A
$$\lambda \approx \dfrac { { d }^{ 2 } }{ 4D } $$

B
$$d\approx \dfrac { { \lambda }^{ 2 } }{ D } $$

C
$$\approx \dfrac { D }{ 4 } $$

D
$$\sqrt { \lambda } \dfrac { D }{ 4 } $$

Solution
Question 7
1 / -0

Before insertion of plate, mid-point of screen in YDSE (assuming mid point of screen is aligned with the mid point of slits) is a location of

A
A point of central maxima

B
A point of maxima that is not the central maxima

C
A point of minima

D
Neither a point of maxima nor of minima
Question 8
1 / -0

In the interference of waves from two sources of intensities $$I_{0}$$ and $$4I_{0}$$. The intensity at a point where the phase difference is $$\pi$$ is

A
$$I_{0}$$

B
$$2I_{0}$$

C
$$3I_{0}$$

D
$$4I_{0}$$

Solution
Question 9
1 / -0

A polarizer and an analyzer are arranged with their optic axes parallel to each other Symmetric light first passes through the polarizer and then the analyzer and the intensity of the light emerging is 'I'. If the analyzer is turned through $$30^o$$, the percent changes in the intensity is

A
$$75\%$$

B
$$50\%$$

C
$$25\%$$

D
$$40\%$$

Solution
Question 10
1 / -0

An aperture of diameter 1.2 mm has been illuminated by monochromatic light. The diffracted light is observed on a screen. When the screen is gradually displaced towards the aperture, the centre becomes dark for the first time at a distance of 30cm from the aperture. The wavelength of light used is :

A
6000$${A^ \circ }$$

B
4000$${A^ \circ }$$

C
8000$${A^ \circ }$$

D
3000$${A^ \circ }$$

Solution