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Dual Nature of Radiation and Matter Test - 15

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Dual Nature of Radiation and Matter Test - 15
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  • Question 1
    1 / -0
    The work function of a metal
    Solution

    Correct Answer: Option (A)

    The explanation for the correct answer:

    Work function is defined as the minimum amount of energy required to remove an electron to infinity from the surface of a given solid or metal. 

    Different metals have different work functions due to their difference of strength of bond with electrons.

    Hence, the work function of a metal is different for different metals.

  • Question 2
    1 / -0
    Einstein’s photoelectric equation states that
    $$E_{k} = h v - W$$, In this equation $$E_k$$ refers to :
    Solution
    $$E_{k}=h\nu  -\phi $$ (here $$\phi=W$$)
    here $$E_{k}$$ refers to the maximum kinetic energy of emitted electrons.
  • Question 3
    1 / -0
    The process of photoelectric emission depends on
    Solution
    Photo electric effect happens only if energy of electrons is greater than threshold energy, i.e the  work function.
    Work function depends on material.
    $$\therefore $$ photo electric emission on depends. on nature of surface.

  • Question 4
    1 / -0
    The best suitable metal for photoelectric effect is:
    Solution
    Photoelectric effect occurs easily if the metal has low ionization potential  cesium, the alkali metal has low ionization potential, hence it is best suitable for photoelectric effect. 
  • Question 5
    1 / -0
    The wavelength of matter waves does not depend on
    Solution
    Wavelength of matter,
    $$\lambda =\dfrac{h}{mv}$$
  • Question 6
    1 / -0
    De-Broglie wavelength depends on
    Solution
    $$\lambda =\dfrac{h}{mv}$$
    So $$\lambda $$ depends on mass of the particle.
  • Question 7
    1 / -0
    Work function is the energy required
    Solution
    Work function refers to the minimum frequency of photons required to eject an electron from its surface.
    $$\phi =h{ \upsilon  }_{ o }$$
  • Question 8
    1 / -0
    Threshold wavelength depends on
    Solution
    $$\phi =\dfrac{hc}{\lambda }$$
    $$h$$ and $$c$$ are constants.
    $$\therefore \phi$$ depends only on $$\lambda $$.
  • Question 9
    1 / -0
    The Einstein’s photo-electric equation is based upon the conservation of
    Solution
    Einsteins photoelectric equations states that
    $$E_{k}=h\nu - \phi $$
    where, $$E_{k}$$ is maximum kinetic energy of emitted photoelectrons
    h is plank's constant.
    $$\nu $$ is frequency of incident light
    $$\phi $$ is work function of metal.
    So, it is clearly based upon energy conservation.
  • Question 10
    1 / -0
    An electron beam after collision with the target produces X-rays of wavelength $$4 A^0$$. The velocity of the electron beam is
    Solution
    Energy of x-ray beam $$= \frac{hc}{ \lambda} = 4.95*10^{-16} J =\frac{1}{2} mv^2$$ and it gives $$v = 6.31*10^7$$ m/s.
    So, the answer is option (B).
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