Dual Nature of ...

The radio of deBroglie wavelengths of a proton and an alpha particle of same energy is

The de-Broglie wavelength of an electron is the same as the wavelength of a photon. The K.E of photon is $$'x'$$ times the K.E of the electron,then $$'x'$$ is (m-mass electron ,h- planck's constant,c-velocity of light)

The de Broglie wavelength corresponding to the root-mean-square velocity of hydrogen molecules at temperature $$20^{o}\ C$$ is 

A proton is accelerated through $$225\, V$$. Its de Brogile wavelength is:

Electron has energy of 100 $${ e }{V }$$ what will be its wavelength

A photon and an electron both have wavelength $$1A^{o}$$. The ratio of energy of photon to that of electron is

The de Broglie wavelength of an electron moving with a velocity $$1.5 \times{ 10 }^{ 8 }{ ms }^{ -1 }$$ is equal to that a photon. The ratio of the kinetic energy of the electron to the that of the photon is 

Mark the correct statement: In photo electric effect-

A photon and an electron both have wavelength $$1\mathring { A } $$. The ratio of energy of photon to that of electron is 

An $$\alpha $$ particle is moving in a circular path of radius in the presence of magnetic field B. The de-Broglie wavelength associated with the particle will be $$(q\rightarrow charge\quad on\quad \alpha \quad particle)$$