Dual Nature of Radiation and Matter Test

Result

Dual Nature of Radiation and Matter Test - 77

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Weekly Quiz Competition

Question 1
1 / -0

The energy associated with a radiation having wavelength 300 nm is nearly [h= $$6.626\times 10^{-34}Js]$$:

A
$$6.6\times 10^{-29} J$$

B
$$6.6\times 10^{-19} J$$

C
$$3.3\times 10^{-19} J$$

D
$$2.2\times 10^{-19} J$$

Solution
Question 2
1 / -0

Given diagram indicates the energy levels of certain atoms. When the system moves from $$2\,E$$ level to $$E$$, a photon of wavelength $$\lambda$$ is emitted. The wavelength of photon produced during its transition from $$\dfrac{4E}{3}$$ level to $$E$$ is-

A
$$\dfrac{\lambda}{3}$$

B
$$\dfrac{3 \lambda}{3}$$

C
$$\dfrac{4}{3}\lambda$$

D
$$3 \lambda$$

Solution
Question 3
1 / -0

A particle 'A' of mass 'm' and charge 'q' is accelerated by a potential difference of 50 V. Another particle B of mass '4m' and charges 'q' is accelerated by a potential difference of 2500 V. The ratio of de-Broglie
wavelengths $$\dfrac { \lambda _{ A } }{ \lambda _{ B } } $$ is close to :

A
10.00

B
14.14

C
0.07

D
4.47

Solution
Question 4
1 / -0

The frequency of light emitted for the transition $$n = 4$$ to $$n = 2$$ of He is equal to the transition atom corresponding to which of the following in Hydrogen atom?

A
$$n = 4$$ to $$n = 3$$

B
$$n = 3$$ to $$n = 1$$

C
$$n = 2$$ to $$n = 1$$

D
$$n = 3$$ to $$n = 2$$
Question 5
1 / -0

The electronic transition from $$n=2$$ to $$n=1$$ will produce shortest wavelength in

A
$$Li^{2+}$$

B
$$He^{+}$$

C
$$He$$

D
$$H^{+}$$

Solution
Question 6
1 / -0

The increase in the energy of an electron for changing its de-Broglie wavelength from $$1$$ $$\overset { \circ }{ A } $$ to $$0.5$$ $$\overset { \circ }{ A } $$ will be -

A
1.5 keV

B
0.45 keV

C
0.25 keV

D
100 eV

Solution
Question 7
1 / -0

$$E_1$$, $$E_2$$ and $$E_3$$ are the KE of an electron. $$\alpha$$ -particle and a proton $$(H^+)$$. The de wavelength of all the particles is equal, then

A
$$
E _ { 1 } > E _ { 3 } > E _ { 2 }
$$

B
$$
E _ { 1 } > E _ { 2 } > E _ { 3 }
$$

C
$$
E _ { 2 } > E _ { 3 } > E _ { 1 }
$$

D
$$
E _ { 3 } > E _ { 2 } > E _ { 1 }
$$

Solution
Question 8
1 / -0

An electron is confined to tube of length L, the electron's potential energy in one half of the tube is zero, while the potential energy in the other half is 10eV. if the electrons has a total energy E= 15 eV, then the ratio of the de brogile wavelength of the electron in the 10 eV region of the tube to that inthe other half is :-

A
$$ \frac {1}{\sqrt 3} $$

B
$$ \sqrt 3 $$

C
$$ 3 $$

D
$$ \frac {1}{3} $$
Question 9
1 / -0

At $${ 200 }^{ \circ }C$$ hydrogen molecules have velocity $$2.4\times cm\quad { s }^{ -1 }$$. The Imbroglio wavelength in this case is approximately.

A
1 $$\mathring { A } $$

B
1000 $$\mathring { A } $$

C
100 $$\mathring { A } $$

D
10 $$\mathring { A } $$

Solution
Question 10
1 / -0

If the velocity of hydrogen molecular is $$5\times { 10 }^{ 4 }cm /sec$$ then its de-Broglie wavelength is

A
$$2\overset { o }{ A } $$

B
$$\overset { o }{ 4A } $$

C
$$8\overset { o }{ A } $$

D
$$100\overset { o }{ A } $$

Solution