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Atoms Test - 24

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Atoms Test - 24
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  • Question 1
    1 / -0
    The radius of a shell for $$H-atom$$ is $$4.761\,\overset{o}{A}$$. The value of n is:
    Solution
    We know, Bhor's radius
    $$ r_{n} = 52.9n^{2}$$ Pm   $$ \rightarrow (1)$$ 
    As we are given,
    $$r_{n} = 4.761\dot{A}$$        $$ \rightarrow (2)$$
    equating both the equations
    $$ 4.761\times 10^{-10} = 52.9 n^{2}\times 10^{-10}$$
    $$ n^{2} = 9$$
    $$ n = 3 $$

  • Question 2
    1 / -0
    Which of the following samples will have the same number of atoms as 40 g calcium?
    Solution

    Molar mass of $$Ca=M`= 40$$

    Molar mass of$$Mg=M=24$$

    Given mass of $$Ca= m`=40g$$

    Given mass of $$Mg=m=?$$

    Formula: $$m= m`× M/ M`$$

    $$m= 40\times \dfrac{24}{40}$$

    $$m= 24g$$

  • Question 3
    1 / -0
    The band spectra (characteristic of molecular species) is due to emission of radiation
    Solution
    Solids and liquids give continuous and line spectra. Only gases are known to give band spectra.
  • Question 4
    1 / -0
    Emission spectrum of $$CO_{2}$$ gas
    Solution
    The emission spectrum of $$CO_2$$ gas that has been studied by the electron beam excitation method is a band spectrum.
  • Question 5
    1 / -0
    Number of spectral lines in hydrogen atom is
    Solution
    Infinitely large transition are possible (in principle) for the hydrogen atom
  • Question 6
    1 / -0
    Two photons of same frequencies moving in same medium have:
    a) same linear momenta and wavelengths
    b) same linear momenta and same speeds
    c) same energies and same linear momenta
    Solution

    $$V_{1}=V_{2}$$

    $$\dfrac{C}{\lambda _{1}}=\dfrac{C}{\lambda _{2}}$$

    So $$\lambda_{1} =\lambda _{2}$$

    & linear momentum

    $$P=\dfrac{h}{\lambda }$$

    $$P_{1}=\dfrac{h}{\lambda _{1}}$$

    $$P_{2}=\dfrac{h}{\lambda _{2}}$$

    $$\therefore P_{1}=P_{2}$$

    And $$E_{1}=P_{1}C$$

    $$E_{2}=P_{2}C$$

    So $$E_{1}=E_{2}$$

  • Question 7
    1 / -0
    Which of the following relates to photons both as wave motion and as a stream of particles?
    Solution
    $$(a)$$ Interference exhibits the wave nature of light.
    $$(b)$$ $$ E = m c^{2}$$ exhibits the particles nature of light
    $$(c)$$ Diffraction exhibits the wave nature of light.
    $$(d)$$ $$E = h \nu$$ shows both particle nature and wave nature of light, i.e., light is having a particular wavelength $$ \lambda$$ and the energy is in the form of packets.
  • Question 8
    1 / -0
    Match the following :
    Type IType II
    a) Continuous emission spectrume) Tungsten filament of bulb
    b) Line emission spectrumf) $$CO_2$$ gas
    c) Band emission spectrumg) Sodium vapour lamp
    d) Line absorption spectrumh) chromosphere of sun
    Solution
    Continuous emission spectrum can be seen for Tungsten emission filament of bulb.
    Line emission spectrum is observed when sodium Vapour lamp is used.
    Band emission spectrum is observed for molecules like $$CO_{2}$$ gas.
    Line absorption spectrum is observed when elements in chromospere of sun absorb light of their characteristics wavelength.
  • Question 9
    1 / -0
    A cathode ray tube has a potential difference of $$V$$ between the cathode and anode. The speed of the cathode rays is given by
    Solution
    $$PD = V$$
    $$KE = eV = $$$$\dfrac{1}{2} mv^2 $$     $$ m =$$ mass of cathode particle
    $$v = $$$$\sqrt{(\dfrac{2e}{m})V} $$       $$ v =$$ max velocity, $$e =$$ charge on cathode particle
    $$ v \propto \sqrt V $$
  • Question 10
    1 / -0
    In X-ray spectrum, transition of an electron from an outer shell to an inner shell gives a characteristics X-ray spectral line. If we consider the spectral lines $$K_{\beta },L_{\beta },M_{\alpha }$$ then
    Solution
    $$K_{\alpha }$$ means, electron jumps from L shell to K shell.
    similarly $$L_{\alpha}$$ means electron jumps from M shell to L shell
    $$L_{\beta }$$ means electron jumps from N shell to L shell.
    $$M_{\alpha }$$ means electron jumps from N shell to M shell.
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